Tekisliklar orasidagi ɑ burchak, 12.3.6 ga asosan
Masala 8
P (x1,y1,z1) nuqtadan ax + by + cz + d = 0 tekislikkacha bo’lgan D masofani toping.
Javobi
Aytaylik P0(x0,y0,z0) biror bir nuqta bo’lsin, b vektor P0P1 ga to’g’ri keladigan bo’lsin.
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D masofadan P0 gacha bo’lgan masofa, b vektorning skalyar qiymatining normal vektorga bo’linmasiga teng
P0 nuqta tekislikda yotgani uchun, bizda ax0 + by0 + cz= + d = 0, shuning uchun D quyidagicha yozilishi mumkin.
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