Chapter- 4 : Reagents (solution) used in clinical laboratories

Quantitative expressions…..

• For example :-1mole = 6.02 x 1023 particle of substance.
• 1 mole of Na= 23 grams = 6.02 x 1023
• 1mole of glucose C6H12O6= 180gm
• Since, atomic weight of C=12, H=1, O=16
• Example:- How can you prepare 2mole of glucose per liter of aqueous solution?

Quantitative expressions…..

• Solution
• 1 mole C6H12O6= its molecular weight
• 1mole C6H12O6 = 180gm
• 2mole = ?
• 180gm x 2moles = 360gm
• 1 mole
• * 360 gm glucose is dissolved in one liter of solution to give 2 moles of glucose.

Quantitative expressions…..

• Exercises
• How can you prepare 1.5 mole of HCL in litter?
• How can you prepare 70 mole/L NaOH solutions?
• Molar solution (Molarity )
• A molar solution is the solutions which contains 1 mole of the solute per litter of solution. Or a molar solution which contains one gram molecular weight of a solute per liter of solution.
• Simple formula to calculate Morality
• Morality (M) = Actual Mass in grams
• Mole. Wt x Vol in liter

Quantitative expressions…..

• Example-1: How do you prepare 1 molar solution of NaOH.
• Mol wt of NaOH= 40 gm?
• Solution: - by dissolving 40gm NaOH in 1000ml of aqueous solution
• Example-2:-What is the morality of NaOH, if 20gm NaOH is dissolved in 200ml of solution?

Quantitative expressions…..

• Solution
• Actual mass = 20gm
• Molecular wt = 40gm
• Volume = 0.2 lit (200ml)
• M =Actual Mass
• Mol.wt x vol in liter
• M= 20gm
• 40x 0.2 = 2.5M Na OH