Chapter- 4 : Reagents (solution) used in clinical laboratories


Quantitative expressions…



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chapter 4 reagents

Quantitative expressions…..

      • For example :-1mole = 6.02 x 1023 particle of substance.
  • 1 mole of Na= 23 grams = 6.02 x 1023
  • 1mole of glucose C6H12O6= 180gm
  • Since, atomic weight of C=12, H=1, O=16
  • Example:- How can you prepare 2mole of glucose per liter of aqueous solution?

Quantitative expressions…..

  • Solution
  • 1 mole C6H12O6= its molecular weight
  • 1mole C6H12O6 = 180gm
  • 2mole = ?
  • 180gm x 2moles = 360gm
  • 1 mole
  • * 360 gm glucose is dissolved in one liter of solution to give 2 moles of glucose.

Quantitative expressions…..

  • Exercises
        • How can you prepare 1.5 mole of HCL in litter?
        • How can you prepare 70 mole/L NaOH solutions?
  • Molar solution (Molarity )
  • A molar solution is the solutions which contains 1 mole of the solute per litter of solution. Or a molar solution which contains one gram molecular weight of a solute per liter of solution.
  • Simple formula to calculate Morality
  • Morality (M) = Actual Mass in grams
  • Mole. Wt x Vol in liter

Quantitative expressions…..

  • Example-1: How do you prepare 1 molar solution of NaOH.
  • Mol wt of NaOH= 40 gm?
  • Solution: - by dissolving 40gm NaOH in 1000ml of aqueous solution
  • Example-2:-What is the morality of NaOH, if 20gm NaOH is dissolved in 200ml of solution?

Quantitative expressions…..

  • Solution
  • Actual mass = 20gm
  • Molecular wt = 40gm
  • Volume = 0.2 lit (200ml)
  • M =Actual Mass
  • Mol.wt x vol in liter
  • M= 20gm
  • 40x 0.2 = 2.5M Na OH

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