|
ᵩ =450
VB =pb·µV
VВA =ab· µV
VS =pS·µV
ᵩ =900
VB =pb·µV
VВA =ab· µV
VS =pS·µV
ᵩ =1350
VB =pb·µV
VВA =ab· µV
VS =pS·µV
ᵩ =1800
VB =pb·µV
VВA =ab· µV
VS =pS·µV
ᵩ =2250
VB =pb·µV
VВA =ab· µV
VS =pS·µV
ᵩ =2700
VB =pb·µV
VВA =ab· µV
VS =pS·µV
ᵩ =3150
VB =pb·µV
VВA =ab· µV
VS =pS·µV
ᵩ =3600
VB =pb·µV
VВA =ab· µV
VS =pS·µV
Mexanizmni tezlanishlar rejasini qurish.
Krivoship O nuqta atrofida doimiy burchak tezligi ω=20 rad/s bilan aylanadi. A nuqta aylana bo'ylab harakatlanadi, shuning uchun uning tezlanishi ikkita komponentdan iborat:
Krivoshipning burchak tezligi doimiy bo'lgani uchun, krankning burchak tezlanishi
и , т.е.
vektor A nuqtadan aylanish markaziga yo'naltirilgan 0,22 - O nuqta
Tezlanishlarning masshtab koeffitsientini A surish nuqtasi uzunligini 40 mm qilib aniqlaymiz.
Shatun AB tekislik-parallel harakatni amalga oshiradi, shuning uchun tezlanishi ma'lum bo'lgan A nuqtasini qutb sifatida olib, vektor tenglamasini tuzamiz:
(3.2)
Pa nuqtasidan A nuqtadan A dan O ga yo'naltirilgan va uzunligi 40 mm ga teng bo'lgan tezlanish vektorini chizamiz.
Bu vektorning oxiridan (a nuqta) AB ga parallel va uzunligi vektoriga teng (shkala bo'yicha) segmentni chizamiz. ning 5,5⸱ 1=5,5mm, chunki tezlikning masshtab koeffitsiyenti
vektorining oxiridan boshlab AB ga perpendikulyar chiziqni u x-x chiziq bilan kesishguncha o'tkazamiz.
Olingan yopiq shakl Pan2b vektor tenglama (3.2).
Tezlanish rejasidagi barcha qiymatlarni o'lchab, , o'lchov faktoriga ko'paytirib, biz ularning haqiqiy qiymatlarini olamiz.
AB zvenosining burchak tezlanishi:
2. Ishning ketma-ketligi
Ishning mazmuni.
1) talaba krivoship-shatun mexanizmining polzunining har 450 burilishida tezlik va tezlanish rejalarini tuzishi kerak.
2) 2-sonli amaliy darsda olingan mos keladigan pozitsiyalarda polzunning tezlik va tezlanish qiymatlarini solishtiring.
Kerakli jihozlar: krivoship-shatun mexanizmining modeli.
Asboblar: o'lchagich, uchburchak, sirkul va transportyor.
Mexanizm tezligi rejasini tuzish tartibi
1. O'zingizning variyantingizga ko'ra, daftarga krivoshipning har 450 burilishida mexanizmning 8 ta pozitsiyasini chizing.
2. Krivoship oxiridagi A nuqtaning tezligini aniqlang. Chizmada tezlik uzunligi VA ni tanlang va tezlik rejasining masshtab koeffitsientini aniqlang.
3. Ko'rsatmalarga muvofiq 8 ta pozitsiya uchun mexanizm uchun tezlik rejalarini tuzing.
4. Tezlik rejasidagi barcha tezliklarni o'lchang (VB, VBA, VS tezliklari) va haqiqiy tezlik qiymatlarini aniqlang.
5. Shatunning burchak tezligini aniqlang.
6. Polzun tezligini 2-son amaliy darsda olingan natijalar bilan solishtiring
7. Olingan barcha qiymatlarni jadvalga kiriting.
8. Xulosa chiqaring.
№ Holatlar
|
1
|
2
|
3
|
4
|
5
|
6
|
7
|
8
|
Burchak tezlik , rad/s
|
2.2
|
0
|
2.2
|
3.1
|
1.3
|
0
|
1.81
|
1.3
|
А nuqtaning VA, m/sek
|
0.7
|
0
|
0.7
|
0.7
|
0.7
|
0
|
0.7
|
0.7
|
VB,tezlik m/sek
|
8.8
|
9.5
|
5.1
|
0
|
6.6
|
9.5
|
6.6
|
0
|
VBA, tezlik m/sek
|
0.49
|
0
|
0.5
|
0.7
|
0.3
|
0
|
0.4
|
0.3
|
Burchak tezlik , rad/c
|
2.2
|
0
|
2.2
|
3.1
|
1.3
|
0
|
1.81
|
1.3
|
Mexanizmni tezlanish rejasini tuzish tartibi
1. Ko'rsatmalarga muvofiq krivoship uchining A nuqtasining tezlanishini aniqlang. chizmasida tezlanish uzunligini tanlang va tezlashtirish rejasining masshtab koeffitsientini aniqlang .
2. Tezlanishni aniqlang Olingan qiymatini tezlanish rejasining masshtab koeffitsientiga bo'lish yo'li bilan chizma bo'yicha ushbu tezlanishning uzunligini aniqlang.
3. Ko'rsatmalarga muvofiq 8 ta qoida bo'yicha mexanizmni tezlanish rejalarini tuzing.
4. Tezlashtirish rejasi ( ) bo'yicha barcha tezlanishlarni o'lchang va o'lchangan tezlanishlarni tezlanish rejasining masshtab koeffitsientiga ko'paytirish orqali haqiqiy tezlanishlar qiymatlarini aniqlang.
5. Shatunning burchak tezlanishini aniqlang.
6. Polzun tezlanishlarining qiymatlarini 2-sonli amaliy darsda olingan natijalar bilan solishtiring.
7. Olingan barcha qiymatlarni jadvalga kiriting.
8. Xulosa chiqaring.
№ holatlar
|
1
|
2
|
3
|
4
|
5
|
6
|
7
|
8
|
|
288
|
0
|
474
|
198
|
344
|
0
|
186
|
344
|
Tezlanish
|
311
|
0
|
302
|
145
|
326
|
0
|
265
|
412
|
Tezlanish
|
150
|
0
|
714
|
104
|
714
|
0
|
683
|
1240
|
Tezlanish
|
415
|
45.8
|
514
|
594
|
210
|
323
|
818
|
102
|
Tezlanish
|
689
|
248
|
120
|
416
|
103
|
398
|
702
|
103
|
Burchak tezlanish
|
230
|
204
|
360
|
82
|
314
|
129
|
368
|
145
|
Krivoship-shatun mexanizmining tezlanishlar rejasini qurish
n=130 ayl/min lAB= 0,22 m
lOA= 0,052 m
ω= = = 13.6 s-1
anA = ω2 lOA = 184.9 0,052 = 9.61 m/s2
µa = anA 50 = 9.61 50 = 0.19
45 . anBA =ω2AB lAB=2.22 0,22=1.056m/s2
a-an = anBA µa =1.056 0.19= 5.5 m/s2
aτBA= τBA µa = 35 94.6 =3311 m/s2
aBA= ab µa = 50 0.19 =6.65 m/s2
aS = S µa = 46 0.19 =8.17m/s2
aB = B µa = 40 0.19 =7.6 m/s2
ɛAB = aτBA lAB = 3311 0.18 =18394 s-2
90°. anBA =ω2AB lAB= 0
a-an = anBA µa =0
aτBA= τBA µa =0
aBA= ab µa = 0.19 =0 m/s2
aS = S µa = 0 0.19 =0 m/s2
aB = B µa = 50 0.19 =9.5 m/s2
ɛAB = aτBA lAB = 0
135°. anBA =ω2AB lAB=2.22 0,22=1.056 m/s2
a-an = anBA µa =1.056 0.19= 5.5 mm
aτBA= τBA µa = 32 0.19=1344 m/s2
aBA= ab µa = 36 0.19=6.84 m/s2
aS = S µa = 32 0.19=6.08 m/s2
aB = B µa = 27 0.19=5.13 m/s2
ɛAB = aτBA lAB = 44 0,18 =167 s-2
180°. anBA=ω2AB lAB=9.612 0,22=20.3m/s2
a-an = anBA µa =20.3 0.19 =3.8 m/s2
aτBA= τBA µa =0
aBA= ab µa = 50*0.19=9.5
aS = S µa = 25*0.19=4.75
aB = B µa = 0 0.19 =0 m/s2
ɛAB = aτBA lAB = 0
225°. anBA =ω2AB lAB=1.52 0,22=0.49 m/s2
a-an = anBA µa =0.49 0.19= 0.09 mm
aτBA= τBA µa = 32 0.19=441 m/s2
aBA= ab µa = 25 0.19=4.75 m/s2
aS = S µa = 40 0.19=7.6 m/s2
aB = B µa = 35 0.19=6.65 m/s2
ɛAB = aτBA lAB = 4,4 0,18 =167 s-2
270°. anBA =ω2AB lAB= 0
a-an = anBA µa =0
aτBA= τBA µa =0
aBA= ab µa = 0 0.19=0 m/s2
aS = S µa = 0 0.19=0m/s2
aB = B µa = 50 0.19=9.5 m/s2
ɛAB = aτBA lAB = 0
315°. anBA =ω2AB lAB=1.32 0,22=0.3 m/s2
a-an = anBA µa =0.3 0.19=1.5 mm
aτBA= τBA µa = 21 0.19=129 m/s2
aBA= ab µa = 28 0.19=5.32m/s2
aS = S µa = 54 0.19 =5108 m/s2
aB = B µa = 39 0.19= 3689 m/s2
ɛAB = aτBA lAB = 2,9 0,18=11,06 s-2
360°. anBA=ω2AB lAB=832 0,18=1240 m/s2
a-an = anBA µa =1240 94.6 =13.1mm
aτBA= τBA µa =0
aBA= ab µa = 0
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