Ehtimolliklar nazariyasi va matematik statistika

Javob: P4(3)=0,25.
Ill bob bo‘yicha test topshiriqlari
Tanga 5 m arta tashlanadi. «Gerbli» tom oni ikki martadan kam tushish ehtimolligini toping.

A) P 5(0)+ P 5(1) B) P5(5 )+ P 5(0) C) P 5(l) D) P5(0).

Tanga 5 m arta tashlanadi. «Gerbli» tom oni ikki marta tu ­ shish ehtimolligini toping.

A)	P5(0)+P5(\)	C)	1 -(P 5(5)+P5(0))
B)	1—CP5(0)+P 5(1))	D)	Ps(2).

Oilada 5 ta farzand bor. Bu bolalar orasida ikkita o‘g‘il bola bo‘lish ehtimolligini toping. 0 ‘g‘il bolalar tug‘ilish ehtimolligini 0,51 ga teng deb oling.

A) 0,48 B) 0,31 C) 0,51 D) 0,5.

96

Oilada 5 ta farzand bor. Bu bolalar orasida ko‘pi bilan ikki o‘g‘il bola bo lish ehtimolligini toping. 0 ‘g‘il bolalar tug‘ilish ehti­ molligini 0,51 ga teng deb oling.

A) 0,51 B) 0,2 C) 0,48 D) 1.
Hodisaning 25 ta bogiiqsiz tajribaning har birida ro‘y berish ehtimolligi p = 0,8 ga teng. Hodisaning kamida 11 m arta va ko‘pi bilan 23 marta ro‘y berish ehtimolligini toping.
A) 0,9331B) 0,2321C) 0,4831D) 1.
6. Hodisaning 676 ta bogiiqsiz tajribaning har birida ro‘y be­ rish ehtimolligi 0,9 ga teng.Hodisa ro‘y berishi nisbiy chastotasi-ning uning ehtimolligidan chetlanishi absolut qiymati 0,03 dan ortiq bolm aslik ehtimolligini toping.
A) 0,9906 B) 0,9331 C) 0,2321 D) 0,4831.
Hodisaning bogiiqsiz tajribalarning har birida ro‘y berish ehtimolligi p = 0,75 ga teng. Hodisa ro‘y berish nisbiy chastota-sining uning ehtimolligidan chetlanishi absolut qiymati bo‘yicha 0,03 dan ortiq bolm asligini 0,4972 ehtimollik bilan kutish m um ­ kin bolishi uchun olkazilishi lozim b o ig an tajribalar soni n ni toping.
A) 93 B) 91 C) 92 D) 94.
8. O'yin kubigi uch marta tashlanadi. Bunda ikki marta 6 ochko tushish hodisasining ehtimolligini toping.
A) P,(2) = ^ B) />j(2) = i C) />,(2) = A D) P,(2) = ± .

Tangani 8 m arta tashlanadi. Bunda «gerbli» tom oni bilan 6 marta tushishi hodisasining ehtimolligini toping.