Ipning tarangligi nimaga teng?
Masala biroz qiyinroq boʻlgani sababli dastlab havo shariga taʼsir qiluvchi kuchlarni chizib olamiz. Shartda koʻplab kattaliklar berilgan, biz koʻrishimiz osonlashishi uchun ularni chizmada aks ettiramiz. (Ushbu holda muhit havo ekanini yodda tuting.)
Havo shari hech qanday tezlanishga ega boʻlmagani sababli kuchlar muvozanatlashgan boʻlishi kerak (yaʼni natijaviy kuch nolga teng). Demak, yechishni sharga taʼsir qiluvchi yuqoriga va pastga yoʻnalgan kuchlarni tenglashdan boshlashimiz mumkin.
F_A = W +F_{T} \qquad \text{(Yuqoriga va pastga yoʻnalgan kuchlar teng/muvozanatlashgan)}FA=W+FT(Yuqoriga va pastga yoʻnalgan kuchlar teng/muvozanatlashgan)F, start subscript, A, end subscript, equals, W, plus, F, start subscript, T, end subscript, start text, left parenthesis, Y, u, q, o, r, i, g, a, space, v, a, space, p, a, s, t, g, a, space, y, o, ʻ, n, a, l, g, a, n, space, k, u, c, h, l, a, r, space, t, e, n, g, slash, m, u, v, o, z, a, n, a, t, l, a, s, h, g, a, n, right parenthesis, end text
\rho Vg = mg + F_T \qquad \text{(Arximed kuchi va havo sharining ogʻirlik kuchi formulalarini keltirib qoʻying)}ρVg=mg+FT(Arximed kuchi va havo sharining ogʻirlik kuchi formulalarini keltirib qoʻying)rho, V, g, equals, m, g, plus, F, start subscript, T, end subscript, start text, left parenthesis, A, r, x, i, m, e, d, space, k, u, c, h, i, space, v, a, space, h, a, v, o, space, s, h, a, r, i, n, i, n, g, space, o, g, ʻ, i, r, l, i, k, space, k, u, c, h, i, space, f, o, r, m, u, l, a, l, a, r, i, n, i, space, k, e, l, t, i, r, i, b, space, q, o, ʻ, y, i, n, g, right parenthesis, end text
F_T = \rho Vg -mg \qquad \text{(Taranglikni tenglikning bir tomoniga oʻtkazib toping)}FT=ρVg−mg(Taranglikni tenglikning bir tomoniga oʻtkazib toping)F, start subscript, T, end subscript, equals, rho, V, g, minus, m, g, start text, left parenthesis, T, a, r, a, n, g, l, i, k, n, i, space, t, e, n, g, l, i, k, n, i, n, g, space, b, i, r, space, t, o, m, o, n, i, g, a, space, o, ʻ, t, k, a, z, i, b, space, t, o, p, i, n, g, right parenthesis, end text
F_T = \rho (\dfrac{4}{3}\pi r^3)g -mg \qquad \text{(Shar hajmi formulasini keltirib qoʻyamiz)}FT=ρ(34πr3)g−mg(Shar hajmi formulasini keltirib qoʻyamiz)F, start subscript, T, end subscript, equals, rho, left parenthesis, start fraction, 4, divided by, 3, end fraction, pi, r, cubed, right parenthesis, g, minus, m, g, start text, left parenthesis, S, h, a, r, space, h, a, j, m, i, space, f, o, r, m, u, l, a, s, i, n, i, space, k, e, l, t, i, r, i, b, space, q, o, ʻ, y, a, m, i, z, right parenthesis, end text
F_T = (1{,}23 \dfrac{\text{kg}}{\text{m}^3}) [\dfrac{4}{3}\pi (\dfrac{3{,}50 \text{ m}}{2})^3]g -(9{,}20 \text{ kg})g \qquad \text{(Kattaliklarning son qiymatini keltirib qoʻying. Diametrdan radiusga oʻtishni unutmang!)}FT=(1,23m3kg)[34π(23,50 m)3]g−(9,20 kg)g(Kattaliklarning son qiymatini keltirib qoʻying. Diametrdan radiusga oʻtishni unutmang!)F, start subscript, T, end subscript, equals, left parenthesis, 1, comma, 23, start fraction, start text, k, g, end text, divided by, start text, m, end text, cubed, end fraction, right parenthesis, open bracket, start fraction, 4, divided by, 3, end fraction, pi, left parenthesis, start fraction, 3, comma, 50, start text, space, m, end text, divided by, 2, end fraction, right parenthesis, cubed, close bracket, g, minus, left parenthesis, 9, comma, 20, start text, space, k, g, end text, right parenthesis, g, start text, left parenthesis, K, a, t, t, a, l, i, k, l, a, r, n, i, n, g, space, s, o, n, space, q, i, y, m, a, t, i, n, i, space, k, e, l, t, i, r, i, b, space, q, o, ʻ, y, i, n, g, point, space, D, i, a, m, e, t, r, d, a, n, space, r, a, d, i, u, s, g, a, space, o, ʻ, t, i, s, h, n, i, space, u, n, u, t, m, a, n, g, !, right parenthesis, end text
F_T = 180 \text{ N} \qquad \text{(Hisoblang va nishonlang)}FT=180 N(Hisoblang va nishonlang)
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