1-Laboratoriya ishi Kirish

912-17 guruh talabasi

Karimov Islomning sonli

usullar va dasturlash fanidan

1-Laboratoriya ishi

Kirish:

Biz bu dasturimizda berilgan sonlar, va fizik o’lchashlar va hisob kitob ishlari olib borishdagi olingan natijalarda hatoliklar , hisobash xatosi va yo’qotilmas hatolarni aniqlashda qo’llaniladi. Masaln biz oddiy hisoblashda pi 3.14 sonini olamiz aslida esa u 3.1415… qiymatga ega.

Blok sxema:

Boshlash

a, a1, a0, dE1, E1, F1

b, b1, b0, dE2, E2, F2, n1=0

n2=0, m1, m2, aw, dEE1, dEE2


i=1, i<=7



aw%10 aw=aw/10;

n1++;m1=7-n1

dEE1=aw%100

a0=aw/(pow(10,m1)) dEE1>50 a0=aw/100+1;

a0=a0/(pow(10,m1-2))




dE1=1/pow(10,m1);

a1=fabs(a0-a);

E1=a1+dE1;

F1=(E1*1.0)*100/(a0);

a0, a1, E1, F1


i=1, i<=7



bw%10 bw=bw/10;

=0 n2++;m2=7-n2

dEE2=bw%100

b0=bw/(pow(10,m2)) dEE2>50 b0=bw/100+1;

b0=b0/(pow(10,m2-2))




dE2=1/pow(10,m2);

b1=fabs(b0-b);

E2=b1+dE2;

F2=(E2*1.0)*100/(b0);

aa,x,aa0,aa2,aa3,aa4,A1,A2

A3,A4,D,y,aaw;

aa=aa*100000000

aaw=aa;

n=0, m=0


j=1, j<8



aaw%10 aaw=aaw/10;

=0 n++; m=8-n

aa=aa/(pow(10,n));

D=aa0;

j=0, j
aa=aa*1.0/(pow(10,1));



q=aa



)

)


D0=(aa-q)*1.0/(pow(10,m-i))

D

i+1, D





A, B, Aa=A*B/100




1-ish.

Dastur kodi (c++ da):

#include

using namespace std;

int main (){

// 1-MISOL//////////////////////////////////////////////////////////

double a=0, a1,a0,dE1,E1,F1;

double b=0, b1,b0,dE2,E2,F2;

cout<<"a="; cin>>a;

cout<<"b="; cin>>b;

int n1=0,m1,aw,dEE1;

int n2=0,m2,bw,dEE2;

aw=a*pow(10,7);

bw=b*pow(10,7);

for (int i=1; i<=7; i++){

if(aw%10==0){

aw=aw/10;

n1++;

m1=7-n1;

}

}

// a misolniki

dEE1=aw%100;

if(dEE1 > 50){

a0=aw/100+1;

a0=a0/(pow(10,m1-2));

}

else {

a0=aw/(pow(10,m1));

}

dE1=1/pow(10,m1);

a1=fabs(a0-a);

E1=a1+dE1;

F1=(E1*1.0)*100/(a0);

cout<<"---------------------------\na0= "<

cout<

// b misolniki

for (int i=1; i<=7; i++){

if(bw%10==0){

bw=bw/10;

n2++;

m2=7-n2;

}

}

// a misolniki

dEE2=bw%100;

if(dEE2 > 50){

b0=bw/100+1;

b0=b0/(pow(10,m2-2));

}

else {

b0=bw/(pow(10,m2));

}

dE2=1/pow(10,m2);

b1=fabs(b0-b);

E2=b1+dE2;

F2=(E1*1.0)*100/(b0);

cout<<"b0= "<

cout<<" %\n---------------------------\n\n";

// 2- a) MISOL///////////////////////////////////////////////////////////

double aa,x,aa0,aa2,aa3,aa4,A1,A2,A3,A4,D,y;

int aaw;

cout<<"a= "; cin>>aa;

cout<<"a0= "; cin>>aa0;

cout<<"\n";

aa=aa*100000000; //10^8

aaw=aa;

int n=0,m=0;

for (int j=1; j<8; j++){

if(aaw%10==0){

aaw=aaw*1.0/10;

n++;

m=8-n;

}

}

//aa1=aaw%10;

//x=1/(pow(10,m));

//A1=aa0+x;

aa=aa/(pow(10,n));

D=aa0;

for (int i=0; iaa=aa*1.0/(pow(10,1));

int q=aa;

cout<<"a="<

cout<<"a'="<

double D0=(aa-q)*1.0/(pow(10,m-i));

D+=aa0+D0;

cout<<"D"<

}

// 2- b) MISOL///////////////////////////////////////////////////////////

double A,B;

cout<<"A="; cin>>A;

cout<<"B="; cin>>B;

double Aa=A*B*1.0/100;

int daraja=7;
A=A*pow(10,daraja);

n=0;

int Aint=A;

for (int j=0; j

if(Aint%10==0){

Aint=Aint/10;

n++;

m=7-n;

}

}

Aint=Aint%100;

double Aa1;

Aa1=Aint/(pow(10,m))+Aa;

cout<<"Aa1="<}