Tabiiy gazni yonish hisobi.
17-variant.
Quruq gazni tarkibi,%.
CH4q
|
C2H6q
|
C3H8q
|
C4H10q
|
C5H12q
|
CO2q
|
N2q
|
∑
|
89.0
|
2,0
|
0,9
|
1.5
|
1,9
|
0,2
|
5.5
|
100
|
Gaz havoning sarf koeffitsienti α=1,2 bo’lgan holatda yoqiladi.Yoqish uchun berilayotgan havo 8000 C haroratgacha qizdiriladi.Gazdagi namlik miqdori ω=0,9% deb qabul qilamiz.
1) Quruq gaz tarkibini namlikni hisobga olganda holda ishchi gazga qayta hisoblaymiz.
CH4nam= CH4q(100-H2O)/100=89*0,99=88.11%
Gaz tarkibidagi boshqa tashkil qiluvchi gazlar o’zgarishsiz qoladi.
Nam holatdagi ishchi gaz tarkibi,%
CH4nam
|
C2H6nam
|
C3H8nam
|
C4H10nam
|
C5H12nam
|
CO2nam
|
N2nam
|
H2Onam
|
∑
|
88.11
|
2,0
|
0.9
|
1.5
|
0.9
|
0,2
|
5.5
|
1,0
|
100
|
2) Gazning yonish issiqligini aniqlash quyidagi formuladan aniqlaymiz:
Qn =358,2*CH4nam +637,5* C2H6nam +912,5* C3H8nam +1186,5* C4H10nam +1460,8* C5H12nam =36751.972 kDj/nm3 .
3) Nazariy jihatdan yoqilig’ini yoqish uchun talab etiladigan quruq havo miqdorini quyidagi formuladan aniqlaymiz:
Lα =0,0476(2*CH4nam =3,5* C2H6nam +5,0* C3H8nam +6,5* C4H10nam +8* C5H12nam)=9.742
4) Atmosfera havosidagi namlik miqdori d=10 g/kg quruq havo deb qabul qilamiz va namlik hisobga olgan holda nazariy jihatdan talab qilinadigan atmosfera havosini quyidagi formuladan aniqlaymiz:
Lα | =1,016* Lα =9.742*1,016=9.898
5) Sarf koeiffitsienti α=1,2 bo’lgan holatdagi havoning haqiqiy sarfini quyidagi formuladan aniqlaymiz:
Lα = α * Lα =1,2*9.7423=11.69
Lα | = α * Lα | =1,2*9.898=11.877
6) Yonish mahsulotlari tarkibi va miqdorini α=1,2 bo’lgan holat uchun quyidagi formulalar yordamida aniqlaymiz:
VCO2 =0,01(CO2nam+CH4nam+2*C2H6nam+3*C3H8nam +4*C4H10nam+5* C5H12nam)=1.0557 nm3/ nm3
VH2O=0,01(2*CH4nam+3*C2H6nam+4*C3H8nam+5*C4H10nam+6*C5H12nam+H2O +0,16*d*Lα)=2.184 (nm3/nm3)
VN2 =0,01* N2nam +0,79* Lα =9.29 (nm3/nm3)
VO2 =0,21*( α -1)* Lα=0,21*0,2*10,23=0,409 (nm3/nm3)
7) Yonish mahsulotlarining umumiy miqdori (nm3/nm3):
Vα = VCO2 + VH2O +VN2 + VO2 =1.0557+2.184+89.29+0,409=12.939 (nm3/nm3)
8) Yonish mahsulotlarining umumiy miqdori (%):
CO2 =( VCO2 *100)/ Vα=8.154 %
H2O =( V H2O *100)/ Vα=16.88%
N2 =( VN2 *100)/ Vα=71.802 %
O2 =( VO2 *100)/ Vα=3,162 %
Jami:100,0%
nm3 ni kg o’tkazish uchun zichlikka ρ ko’paytiramiz (jadvalga qarang).
9) α=1,2 bo’lganda 100 nm3 gaz yonishi uchun yonish jaroyonining material balansini tuzamiz.
Yonish jaroyonining material balansi
Kirish
|
kg
|
Sarf
|
kg
|
CH4= CH4nam* ρ=88.11*0,717
C2H6=C2H6nam* ρ=2*1,356
C3H8 =C3H8nam * ρ=
0.9*2,020
C4H10 =C4H10nam * ρ=
1.5*2,840
C5H12 =C5H12nam * ρ=
0.9*3,218
CO2 =CO2nam * ρ=0,2*1,977
N2 =N2nam * ρ=5.5*1,251
H2O=H2Onam * ρ=1,0*0.804
Havo
O2=197,9*α*ρ=
197,9*1,2*1,429
N2=197,9*α*3,762*ρ=
197,9*1,2*3,762*1,251
H2O=0,16*d*Lα*ρ=
0,16*10*11.69*0,804
|
63.174
2.712
1.818
4.26
2.8962
0,3954
6.8805
0,804
339,8
1117.64
15.03
|
CO2 = VCO2 *100* ρ=
1,0557*100*1,977
H2O =V H2O *100* ρ=
2.184*100*0,804=
N2 =VN2 *100* ρ=
9.29*100*1,251=
O2 =VO2 *100* ρ=
0,409*100*1,429
Nomutanosiblik
|
208.71
175.59
1162.179
58.4461
-49.5
|
Jami:
|
1555.41
|
Jami:
|
1604.92
|
Balansning nomutonisibligi:(100*0,495)/1555.41=0,0318 %
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