Using System; using System. Collections. Generic; using

Yuqoridagi misolga qadamlar sonini har qil olganimizdagi natija ko’rish uchun quyidagi dasturdan foydalanish mumkin. Dasturning dastlabki ko’rinishi:

Dasturga qadamlar sonini kirgizganimizdan keyingi natija:

Dasturnining C# dasturlash tilidagi kodi:
using System;
using System.Collections.Generic;
using System.Drawing;
using System.Windows.Forms;

namespace To_rlar_metodi
{
public partial class MainForm : Form
{
public MainForm()
{
InitializeComponent();
}
public static void X(ref double [] x)
{
for (int i=1;i{
x[i]=x[i-1]+(x[x.Length-1]-x[0])/(x.Length-1);
}
}
public static void Y(ref double [] y)
{
for (int i=1;i{
y[i]=y[i-1]+(y[y.Length-1]-y[0])/(y.Length-1);
}
}
public static void Ui0(ref double [,] u, double [] x)
{
for (int i=0;i}
public static void U0j(ref double [,] u,double [] y)
{
for (int i=0;i}
public static void Unj(ref double [,] u, double [] y, int n)
{
for (int i=0;i}
public static void Ui1(ref double [,] u, double [] x)
{
for (int i=1;iSin(x[i])+(u[i+1,0]+u[i-1,0])/2;
}
public static void U(ref double [,] u,int n,int k)
{
for (int j=1;j{
for (int i=1;i{
u[i,j+1]=u[i+1,j]+u[i-1,j]-u[i,j-1];
}
}
}
void Button2Click(object sender, EventArgs e)
{
int n,k,i,j;
n=int.Parse(textBox5.Text);
k=int.Parse(textBox6.Text);
double [] x=new double[n+1];
double [] y=new double[k+1];
x[0]=0; x[n]=1; y[0]=0; y[k]=0.5;
Y(ref y);X(ref x);
double [,] u=new double[n+1,k+1];
Ui0(ref u,x);U0j(ref u,y);Unj(ref u,y,n);
Ui1(ref u,x);U(ref u,n,k);
for (i=0;i{
for (j=0;j{
richTextBox1.Text+="U("+x[i]+","+y[j]+")="+u[i,j]+"\t";
}
richTextBox1.Text+="\n";
}
}
void Button1Click(object sender, EventArgs e)
{
textBox5.Clear();
textBox6.Clear();
richTextBox1.Clear();
}
}
}