Muhammad al-xorazmiy nomidagi toshkent axborot texnologiyalari universiteti laboratoriya ishi

O‘ZBEKISTON RESPUBLIKASI AXBOROT TEXNOLOGIYALARI VA KOMMUNIKATSIYALARINI RIVOJLANTIRISH VAZIRLIGI
MUHAMMAD AL-XORAZMIY NOMIDAGI
TOSHKENT AXBOROT TEXNOLOGIYALARI UNIVERSITETI
LABORATORIYA ISHI № 2


MAVZU:REAL MUSTAQIL KUCHLANISH VA TOK MANBALARINING TADQIQOTI

Toshkent–2022


2 – LABORATORIYA ISHI
REAL MUSTAQIL KUCHLANISH VA TOK MANBALARINING TADQIQOTI
Ishning maqsadi: NI Multisim dasturiy muhiti yordamida kuchlanish va tok manbasining tashqi tavsifini o’rganish.

1-rasm. Kuchlanish va tok manbasining tashqi tavsifini o‘rganish printspial sxemasi

2-rasm. NI Multisim dasturiy muhitida yig‘ilgan holati

Dastlabki hisoblashlar

• 
  Zanjirning tokini hisoblash I=E/(R_ich+R_yuk) (A)
  

I₁=8,4/(300+50)=24mA; I₅=8,4/(300+1500)=4,6mA;

I₂=8,4/(300+150)=18,6mA; I₆=8,4/(300+2000)=3,65mA;
I₃=8,4/(300+300)=14mA; I₇=8,4/(300+4000)=1,95mA;
I₄=8,4/(300+800)=7,6mA;

• 
  Yukdagi kuchlanishni topish: U_n=I_n*R_n(yuk) (V)
  

U₁=24*10^-3*50=1,2V U₅=4,6*10^-3*1500=7V

U₂=18,6*10^-3*150=2,8V U₆=3,65*10^-3*2000=7,3V
U₃=14*10^-3*300=4,2V U₁=1,95*10^-3*4000=7,8V
U₄=7,6*10^-3*800=6,1V

• 
  Yukdagi quvvatni hisoblash: P=I²_n*R_n(yuk) (Wt)
  

P₁=(24*10^-3)²*50=0,029 Wt P₅=(4,6*10^-3)²*1500=0,032 Wt

P₂=(18,6*10^-3)²*150=0,052 Wt P₆=(3,65*10^-3)²*2000=0,026 Wt
P₃=(14*10^-3)²*300=0,059 Wt P₇=(1,95*10^-3)²*4000=0,015Wt
P₄=(7,6*10^-3)²*800=0,046 Wt


Foydali ish koeffitsientini hisoblash: 𝜂_n=R_n(yuk)/(R_ich+ R_n(yuk))

𝜂₁=50/(300+50)=0,14 𝜂₅=1500/(300+1500)=0,833

𝜂₂=150/(300+150)=0,33 𝜂₆=2000/(300+2000)=0,87
𝜂₃=300/(300+300)=0,5 𝜂₇=4000/(300+4000)=0,93
𝜂₄=800/(300+800)=0,73

2-jadval

Berilgani		E2=8,4V;		Rich=300Ω
Ryuk	Tajribadan olingan	Tajriba natijalarini hisoblash			Daslabki	hisoblashlar
	Uyuk	I	Pyuk	𝜂	I	U		Pyuk	𝜂
[Ω]	[V]	[mA]	[Wt]	-	[mA]	[V]	[W]		-
50	1,2	24	0,0289	0,1433	24	1,2	0,029		0,14
150	2,8	18,67	0,052	0,3315	18,6	2,8	0,052		0,33
300	4,2	14,02	0,0592	0,4963	14	4,2	0,059		0,5
800	6,1	7,66	0,0458	0,7117	7,6	6,1	0,046		0,73
1500	6,81	4,67	0,0321	0,8182	4,6	7	0,032		0,833
2000	7,3	3,64	0,026	0,8503	3,65	7,3	0,026		0,87
4000	7,8	1,95	0,0152	0,927	1,95	7,8	0,015		0,93

2. Tajriba natijalarga ishlov berish:
- Tajriba asosida olingan kuchlanish Uyuk qiymati asosida keying hisoblashlarni amalga oshiring.
- yuklama tokini hisoblash: I_yuk=U_yuk/R_yuk

I₁=1,2/50=24mA I₅=7/1500=4,67mA

I₂=2,8/150=18,67mA I₆=7,3/2000=3,64mA
I₃=4,2/300=14,02mA I₇=7,8/4000=1,952mA
I₄=6,1/800=7,66mA


-yuknig quvvatini hisoblash: P=I²_yuk*R_(yuk) (Wt)
P₁=(24*10^-3)²*50=0,0289 Wt P₅=(4,6*10^-3)²*1500=0,0321 Wt
P₂=(18,6*10^-3)²*150=0,052 Wt P₆=(3,65*10^-3)²*2000=0,026 Wt
P₃=(14*10^-3)²*300=0,0592 Wt P₇=(1,95*10^-3)²*4000=0,0152Wt
P₄=(7,6*10^-3)²*800=0,0458 Wt
-FIK ni hisoblash:  𝜂= P_yuk/P_manba; bunda: P_manba=E*I_yuk;
𝜂= P_yuk /( E*I_yuk);
𝜂₁=0,0289/(8,4*24*10^-3)=0,1433 𝜂₅=0,0321 /(8,4*4,67*10^-3)=0,8182
𝜂₂=0,052 /(8,4*18,67*10^-3)=0,3315 𝜂₆=0,026 /(8,4*3,64*10^-3)=0,8503
𝜂₃=0,0592 /(8,4*14,02*10^-3)=0,4963 𝜂₄=0,0152/(8,4*1,952*10^-3)=0,927
𝜂₄=0,0458 /(8,4*7,66*10^-3)=0,7117
3. Quyidagi bog’lanishlar grafiklarini chizing:
Iyuk=f(Ryuk)



Uyuk=f(Ryuk)

Pyuk=f(Ryuk)

𝜂 = f (Ryuk);

Xulosa:
Men bu labaratoiya ishimizda shuni ayta olamanki- To’la zanjir uchun Om qonuni ifodasi: I=E/(Rich+R)

Ya’ni to’la zanjirdagi tok kuchlanishga to’g’ri proporsional,
manbaning ich qarshiligi va qarshilik yig’indisiga teskari
proporsionaldir. Biz labaratoriya ishini bajarishda tok kuchi
qarshiliklarning turli qiymatlaridan foydalandik.Shunga bog’liq
ravishda kuchlanishning quvvatning foydali ish koeffitsiyentning har xil qiymatlariga erishdik.Laboratoriyani bajarish davomida zanjirdagi tok kuchi kuchlanishga to’g’ri proporsional , qarshilik va manbaning ichki qarshiligi yig’indisiga teskari proporsional bo’lishini bilib oldim va bu mavzu yuzasidanjuda ko'plab ko'nikmagalarga ega bo'lib oldim.