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Example 3.4 Min-max normalization



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Murodbek Saidov1 for Master Defender

Example 3.4 Min-max normalization. Suppose that the minimum and maximum values for the attribute income are $12,000 and $98,000, respectively. We would like to map income to the range [0.0,1.0]. By min-max normalization, a value of $73,600 for income is transformed to

In z-score normalization (or zero-mean normalization), the values for an attribute, A, are normalized based on the mean (i.e., average) and standard deviation of A. A value, vi , of A is normalized to v 0 i by computing

where A¯ and σA are the mean and standard deviation, respectively, of attribute A. The mean and standard deviation were discussed in Section 2.2, where A¯ = 1 n (v1 + v2 + ··· + vn) and σA is computed as the square root of the variance of A (see Eq. (2.6)). This method of normalization is useful when the actual minimum and maximum of attribute A are unknown, or when there are outliers that dominate the min-max normalization.
Example 3.5 z-score normalization. Suppose that the mean and standard deviation of the values for the attribute income are $54,000 and $16,000, respectively. With z-score normalization, a value of $73,600 for income is transformed to
A variation of this z-score normalization replaces the standard deviation of Eq. (3.9) by the mean absolute deviation of A. The mean absolute deviation of A, denoted sA, is
sA = 1 n (|v1 − A¯| + |v2 − A¯| + ··· + |vn − A¯|).
Thus, z-score normalization using the mean absolute deviation is

The mean absolute deviation, sA, is more robust to outliers than the standard deviation, σA. When computing the mean absolute deviation, the deviations from the mean (i.e., |xi − ¯x|) are not squared; hence, the effect of outliers is somewhat reduced. Normalization by decimal scaling normalizes by moving the decimal point of values of attribute A. The number of decimal points moved depends on the maximum absolute value of A. A value, vi , of A is normalized to v 0 i by computing

where j is the smallest integer such that max(|v 0 i |) < 1.

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