mas hs‘ulot
Dars mavzusi. Algebraik ifodalar.
Dars maqsadlari: o‘quvchilarga algebraik
ulaming fanga qiziqishlarini oshirish.
Sana:
ifodalami o‘rgatish,
Darsning borishi:
Tashkiliy qism.
Algebraik ifodalar.
Algebraik ifodalar.
Harflar yoki raqamlar va harflar bilan ifodalangan bir necha hadlami amallar yordamida birlashtirishdan iborat boMgan yozuv algebraik ifoda deyiladi.
Masalan:
ae x 2 ’ 100
+ У:
jc + 5 3 cd
Algebraik ifodaning qiymati deb, undagi harflar o‘rniga berilgan son qiymatlarini qo‘yib, shu sonlar ustida tegishli amallami bajargandan keyin kelib chiqqan songa aytiladi.
X
Misol: — + у ifodaning qiymatini toping, bu yerda jc=24, y=2
~гт 1 • 1 24 6 _ 6
Yechish: — + 2 = — + 2 = 2—.
100 25 25
Harflar yordamida juft va toq sonlar formulasini yozish mumkin. Agar a juft son bo‘Isa:
agar b toq son bo‘Isa:
a=2n
b=2n+\
bu yerda: n -natural son yoki nol.
Arifmetik amallaming xossalari:
I. Qo‘shish va ko‘paytirish.
o‘rin almashtirish qonuni
a+b=b+a, a-b=b-a
guruxlash qonuni 3
3) taqsimot qonuni
(a+b)+c=a+(b+c), (a-b)c=a(b-c)
a{b+c)=a-b+a-c
Ayirish.
Ayirishni qarama - qarshi songa qo‘shish bilan almashtirish mumkin:
a-b=a+(-b)
Bo‘lish.
Bo‘lish bo‘luvchiga teskari bo‘lgan songa ko‘paytirish bilan almashtirish mumkin:
a 1
- = a- — b b
Nol sonining xossalari:
a+0=a, a - 0=a,
a-0=0,
^ - mavjud emas.
3. Mustahkamlash. Test yechiladi.
TESTLAR.
d
a=4b va c+3b=0 (Ьф0) boTsa, - ni toping.
c
12 112 A) -1- B)l- C)l- D)-- E) -- 7 3 7 3 7 3 7 3 ' 3
Agar ab=9 va 3b=8c boTsa, ac ni hisoblang.
A) 3- B) 3- C) 3- D) 3- E) 3-
J 1 j 9 /3
2 1
a sonning b songa nisbati - ga teng, c sonning b songa nisbati - ga teng, c sonning a songa nisbatini toping.
2 5 5 3 4
А)- В)- C)- D)- E) -
}Ъ }6 } 4 J 5
26-25-25-24+24-23-23-22-12-8 ning qiymatini toping.
A) 106 В) 1 C) 54 D) 8 E) 0
2M8-19-18+18-17-17-16+16-15-15-14 ning qiymatini toping.
A) 50 B)100 C) 98 D) 24 E) 110
18-36-16-36+24-27-25-24-2Е5 ning qiymatini toping.
A) 45 B)1 C)0 D) 15 E) 115
21-13+24-13+45-12+25-44-89-24 ning qiymatini toping.
A) 79 B) 126 C) 89 D) 0 E) 1
36-24-33-24+17-11-14-11+18-16-15-16 ni hisoblang.
A) 166 B) 155 C) 180 D) 2354 E) 153
27-23-24-23+21-19-18-19+17-11-14-11 ni hisoblang.
A) 165 B) 159 C) 143 D) 203 E) 189
2M7-18-17+17-15-15-14+18-13-15-13 ni hisoblang.
A) 125 B) 135 C) 205 D) 180 E) 165
139-15+18-139+15-261+18-261 ni hisoblang.
A) 13200 B) 16200 C) 14500 D) 17500 E) 15100
Agar jc=4,5 va y=3,5 boTsa, x3-x2y-xy2+y3 ni hisoblang.
A) 10 B) 9,5 C) 8 D) 7,2 E) 11
Agar jc=71,8 va y=70,8 boTsa, x3-y3-2y2-3y-l+x2-2xy ni hisoblang.
A) 1 B) 21 C) 79 D) 87,5 E)92,l
Agar a = boTsa, a2b2-ab + \ ifodaning qiymatini toping.
A) 4 B)+ C)1 D)+ E)2
Darsni yakunlash.
Uyga vazifa: test yechish tematik axborotnomalardan
Tayyorladi:
Tekshirdi: 0’TIBDO‘ :
“ ” 20 y.
Xossalari.
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1) an-am =aM;
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2) an:am =a";
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3) (a")"
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4) {a-b)n =anbn;
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5)Г|Т4а>°,,>о;
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6)a°=l.
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Ikki xonali son xona qo‘shiluvchilari yig‘indisi shaklida quyidagicha yozilishi mumkin: аЛО+b, bu yerda a - o‘nliklar soni, b - birliklar soni; uch xonali sonni a- \()2+b- \()+c ko‘rinishda yozish mumkin, bu yerda a - yuzliklar soni, Z>-o‘nliklar soni, c-birliklar soni. To‘rt xonali, besh xonali va h.k. sonlar ham xuddi shu tartibda xona qo‘shiluvchilari yig‘indisi shaklida yoziladi.
Misol: Quyidagi sonlami xona qo‘shiluvchilari yig‘indisi shaklida yozing. Yechish: 1) 235121=2-105+3-104+5-103+M02+2-10+l;
3 532037=3-106+5-105+3-104+2-103+3-10+7;
70 1 508=7-105+l-103+5-102+8;
10101=1-104+M02+1.
3. Mustahkamlash. Test yechiladi.
TESTLAR.
Quyidagilardan qaysi biri -1 ga teng?
A) (-(-l)2)3 B)(-(-l)2)4 C)(-(-l)3)6 D)((-l)3)2 E) ((-1)2)4
Quyidagi ifodalardan qaysi biri 1 gateng?
A) (-(-l)3)3 В) -((-I)5)4 C)((-l)3)5 D)(-(-l)2)3 E) -((-I)2)3
Quyidagi ifodalardan qaysi biri 1 gateng?
A) ((-l)5)2
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B)(-(-l)4)5
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C)((-l)3)3
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D)(-(-l)2)3
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E)((-l)3)5
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r\in—1
Л z 'z
2 4n+\
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ni soddalashtiring.
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A) 24n+2
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B) 22n'2
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C) 2n'2 D) 24n'2 E) 24n+1
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2^и+1
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ni soddalashtiring.
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A) 24n+1
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B) 22n‘2
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C) 2n‘2 D) 24n_1 E) 24n‘2
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2^w—3 23w+3 6. :
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• 2 1+” ni soddalashtiring.
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A) 25n
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B) 24n+2
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C) 24n+1
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D) 23n
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E) 24n
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7.
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