Samarqand davlat universiteti raqamli texnologiyalar fakulteti amaliy matematika informatikayo

> restart;
> with(geometry):
triangle(ABC, [point(A,10.,3.), point(B,-4,7), point(C,4,8)]):
define the ``segment'' bisector bA
> bisector(bA, A, ABC,N); bA
> form(bA); segmebt2d
> OnSegment(N, B, C, sqrt(212/61.));
> coordinates(N);
> detail(bA); name of the object: bA
form of the object: segment2d
the two ends of the segment: [[10., 3.], [1.206942951, 7.650867870]]
5)  ABC ning yuzini quyidagicha hisoblaymiz.
a) , (bunda a- asos, h-asosga tushirilgan balandlik) formulasiga asosan hisoblaymiz. Asos uchun BC tomon uzunligi:
=8.062 ni
va balandlik uchun 3) punktdagi AD uzunligi ekanidan,
 ABC ning yuzasi: ,
b)
formulaga uchburchak ABC ning uchlarining koordinatalarini qo‘yib uni yuzasini topamiz.

> with(geometry):
triangle(ABC, [point(A,10,3), point(B,-4,7), point(C,4,8)]):
area(ABC); 23
A nuqtadan BC tamonga parallel:
> with(geometry):
triangle(ABC, [point(A,10,3), point(B,-4,7), point(C,4,8)]): line(BC, [B,C]); BC
> arallelLine(lA,A,BC); lA
> Equation(lA,[x,y]);
> detail(lA); name of the object: lA
form of the object: line2d
equation of the line: -14-x+8*y = 0
ABC uchburchakni qurish:


ABC uchburchakni tamonlari tenglamalariga asosan qurish;
> with(plots):
> plot([(41-2*x)/7,(68-5*x)/6,(60+x)/8,(75-9/2*x)/10, (14+x)/8,(197*x-1655.)/104.1, (-104.1*x+1631.)/187, (83-8*x)], x=-6..12, color=[red,red,red,blue,blue,green,green, brown], style=[line], thickness=2, view=[-7..12,-18..16]);

ABC uchburchakni uchining koordinatalariga asosan kesmalari bo‘yicha qurish: