Rasmli testlar barchasini yaxshilab o’rganib chiqinglar. 11-sinf biologiya darsligi asosida tuzilgan rasmli test

Javob:yashilAABB,AaBB,AABb,AaBb ko’rinishda oqaabb ko’rinishda
Nisbat:4:1
4.DNK fragmentida 880 ta G bolib umumiy nukleotidlarning 22 foizini tashkil qilagi. Barcha nukleotidlarni toping
22% G - 880ta ekan
yechim
22% --------- 880ta nuk.
100% ---------- x= 4000ta #Javob:4000at
5. 600 ta tripletdan iborat oqsilning og'irligi qancha?
#Yechim:
1ta tripled---------1ta aminokislata
600ta tripled--------x=600ta aminokislata
1ta aminokislata------120D
600ta aminokislata-----X=7200D Javob:7200
6.Gulli o'simliklarning changdonida 760 ta birlamchi jinsiy hujayralar meyoz va mitoz bolinishidan so'ng hosil bolgan spermiylarning 40% qo' sh urug'lanishda ishtirok etgan ushbu o'simlikda xosil bolgan uruglar sonini toping?
Yechim:
1ta birlamchi hujayradan ----------8ta spermiy hosil bo’ladi
760tasidan esa-------------------x=6080
6080---------100%
2432=X------40%
1ta urug uchun ------------2ta spermiy kerak
1216=x------------------------2432tasi Javob:1216
7.Aa Bb Dd Ccee 2va 3 oraliq formada bolsa ularni o'zaro chatishtirsa fenotip va genotip nisbatlarni toping Javob:36:81
8.Shimpanze gemoglabinida DNK ni uzunligi qancha boladi
Yechim:shimpanzening a zanjiri ham b zanjiri ham 2ta dan hisoblanadi
A zanjirining har birida —141ta B zanjirining har birida -----146ta aminokislata bor 141*2=282 a zanjirdagi jami aminokislata
146*2=292 b zanjiridagi jami aminokislata
282+292=574 jami aminokislata
1ta aminokislata--------------------3ta nukleotid
574ta aminokislata------------------x=1722ta i-RNK dagi nukleotid i-RNK va DNK uzunligi o’zaro teng bo’ladi
1ta nukleotid--------0,34nm
1722 ta nukleotid---x=585,48nm Javob:585,48
9.Ma'lum bir o'simlikda 200ta mikrospora bor.Ulardan hosil bo'lgan spermiylarning 18% i qo'sh urug'lanishda qatnashdi.Hosil bo'lgan murtakdagi autosomalar soni 648ta bo'lsa urug'lanishda qatnashmagan spermiylardagi autosamalar sonini toping.
Yechimi:
1ta mikrospora----------2ta spermiy
200ta mikrospora--------x=400ta spermiy
100%--------400ta spermiy
18%-----------x=72ta spermiy
72tani yarmi murtak,yarmi esa endosperm hosil qiladi
72:2=36ta murtak Murak to’plami 2n 36ta murtakda------648ta autosoma
1tasida esa-----------x=18ta autosoma
18ta autosom+2ta jinsiy xromosoma=20ta jami xromosoma
2n=20 n=10ga
Jami 400ta spermiy 72tasi uruglanishda ishtirok etgan
400-72=328ta ishtirok etmagan
1ta spermiyda-----9ta autosoma
328ta spermiyda----x=2952 Javob:2952
10.6 ta urug’ hosil bo’lishida qatnashgan a) urug’kurtakalar b) spernmiylar c) tuxum hujayralar sonini toping?
#a-6 b-12 c-6
11. Gorilla blastomerlari soni undagi xromosomalar Sonidan 3008 ta kam bo'lsa, necha marta meridian(a) va necha marta ekvatrial (b) bo'linganligini aniqlang?
Yechim:
Gorillaning har bir blostomer hujayrasida 48ta xromosoma bo’ladi 1ta blostomer 48ta xromosoma farq
48-1=47 agaer 47ta farq bo’lganda 1ta blostomer bo’lar edi
47--------1ta blostomer
3008-----x=64 demak 64ta blostomer bo’lgan
1248163264
m m e m e m e