1
= (1, 0, 0, 1) has the activity vector (0, 8, 4) and the corresponding output vector is
(0, 1, 1), which is, Y
1
= (0, 1, 1). The value of S
i
is 2 = 1 + 0 + 0 + 1. Therefore, mS
i
= 4. The first component
of the activation vector is 0, which is smaller than 4, and so the first component of the output vector is 0. The
second component of the activation vector is 8, which is larger than 4, and so the second component of the
output vector is 1. The last component of the activity vector is 4, which is equal to mS
i
, and so you use the
third component of the vector Y
1
= (0, 1, 1), namely 1, as the third component of the output.
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C++ Neural Networks and Fuzzy Logic:Preface
Additional Issues
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