Mavzu: Kesmani teng ikkiga bo’lish Darsning maqsadi: Ta’limiy

3.Yangi mavzuni bayon qilish.

y M
x

O D
ODM uchburchakdan:

; cosб= ; tgб= ; ctgб= tengliklardan:MO=1,DM=y, OD=x ekanligini hisobga olsak,sinα=y ; cosб =x ; tgб= ; ctgб=

OMD uchburchakdan:x²+y²=1 , Demak

sin²α+cos ²б=1 tenglik hosil bo’ladi.

4. Yangi mavzuni mustahkamlash.

Darsni mustahkamlash uchun mavzu bo`yicha misollar yechish.

Masala.0⁰,90⁰,180⁰li burchaklarning sinusini toping.

Yechish.0⁰ li burchak OA, 90⁰ li burchak OB nur yordamida aniqlanadi.Ta’rifga ko`ra sin0<sup>0</sup>-A(1;0) nuqtaning ordinatasi sifatida 0 ga, sin90<sup>0</sup>- C (1;0) nuqtaning ordinatasi sifatida 1 ga, sin180<sup>0</sup>- B(-1;0)nuqtaning ordinatasi sifatida 0 ga teng bo`ladi. sin0⁰=0; sin90⁰=1 ; sin180⁰=0