Energetika va sanoatni axborotlashtirish

Bikvadrat tenglamalar. Agar (1) tenglamada b=d=0 bo‘lsa, u holda tenglamatenglamalar. Agar (1) tenglamada b=d=0 bo‘lsa, u holda tenglama

ko‘rinishni oladi.Bunday shakldagi tenglama bikvadrat tenglama deyiladi. Tenglama koeffitsiyentlarini qabul qilingan tartibda yozsak,

tenglamaga ega bo‘lamiz. Agar D= b 2 - 4ас 0 bo‘lsa, tenglamani yechishda

K vadrat tenglamaga ega bo‘lamiz. Ma‘lumki,

MASALANI QO`YILISHI

Berilgan tortinchi darajali tenglamana hususiy bikvadrat va qaytma bolgan hollari uchun tenglamani yechimini topish

#berilgan a*x**4+b*x**3+c*x**2+d*x+e=0 tenglamani hususiy yechimini topuvchi dastur

from math import*

a=int(input('a ni kiriting'))

b=int(input('b ni kiriting'))

d=int(input('d ni kiriting'))

c=int(input('c ni kiriting'))

e=int(input('d ni kiriting'))

print(a,"x4+",b,"x3+",c,"x2+",d,"x+",e,"=0")

if b==0 and c==0 :

print('bu bikvadrat tenglama')

m=b*b-4*a*c

if m>0:

t1=sqrt((b*b+sqrt(d))/2*a)

t2=sqrt((b*b-sqrt(d))/2*a)

print('t1=',t1)

print('t2=-',t1)

print('t3=',t2)

print('t4=-',t2)

elif m==0:

t1=b/2*a

x1=sqrt(t1)

print('x1=',x1,'x2=-',x1)

else :

print('tenglama yechimga ega emas')

else:

print('bu bikvadrat tenglama emas')

#berilgan ax+b*x**3+c*x**2+d*x+e=0 tenglamani hususiy yechimini topuvchi dastur

from math import*

a=int(input('a ni kiriting'))

b=int(input('b ni kiriting'))

c=int(input('c ni kiriting'))

d=int(input('d ni kiriting'))

e=int(input('e ni kiriting'))

print(a,"x4+",b,"x3+",c,"x2+",d,"x+",e,"=0")

if a==e and b==d :

print('bu qaytma tenglama tenglama')

#x+1/x=t

#a(t*t-2)+bt+c=0

#at*t+bt+c-2a=0

m=b*b-4*a*(c-2*a)

if m>0:

t1=((-b*b+sqrt(d))/2*a)

t2=((b*b-sqrt(d))/2*a)

#x+1/x=t1

#x*x-t1x+1=0

n=t1*t1-4

if n>0:

x1=(-t1+sqrt(n))/(2*a)

x2=(-t1-sqrt(n))/(2*a)

elif n==0:

x1=-b/(2*a)

else:

x1="yechim yoq"

#x+1/x=t2

#x*x-t2*x+1=0

n=t2*t2-4

if n>0:

x3=(-t2+sqrt(n))/(2*a)

x4=(-t2-sqrt(n))/(2*a)

elif n==0:

x=-b/(2*a)

print(x)

else:

x3="yechim yoq"

elif m==0:

t=-b/2*a

#x+1/x=t

#x*x-t*x+1=0

n=t*t-4

if n>0:

x1=(-t1+sqrt(n))/(2*a)

x2=(-t1-sqrt(n))/(2*a)

elif n==0:

x1=-b/(2*a)

else:

x1='yechim yoq'

else :

x1='tenglama yechimga ega emas'

print('x1=',x1,'x2=',x2,'x3=',x3,'x4=',x4)

else:

print('bu qaytma tenglama emas')

hulosa