Diskret tuzilmalardan 1-oraliq nazorat varianti №1

Diskret tuzilmalardan 1-oraliq nazorat varianti

№ 4

1. A = {1;2;3} va B = {3;4} to`plamlarning dekart ko`paytmasidan iborat to`plamning nechta elementi bor?

A) 1 B) 3 C) 4 D) 5 E) 6

2. А={1,2,3,4,5,6}. x y binary munosabat yordamida tuzilgan qism to`plamni toping
A) {(1,2), (2,5), (4,2)} B) {(1,1), (1,2), (3,6), (5,6)} C) {(2,1), (6,4)} D) {(3,7)} E) {(2,3),(5,3)}
3. A to`plamdagi R binar munosabat tranzitivlik xossasini qanoatlantiradi, agarda

A) xRx a to`plamdagi ixtiyoriy x uchun ; B) xRy dan yRx kelib chiqadi; C) xRy va yRx dan x=y kelib chiqadi; D) xRy va yRz dan xRz kelib chiqadi

4. 1 dan 20 gacha bo`lgan natural sonlar ichidan yig`indisi toq son bo`lgan 2 ta sonni nechta usulda tanlash mumkin?

A) 80 B) 90 C) 100 D) 110 E) 120

5. 12 ta predmetni 3 ta qutiga nechta ussulda joylash mumkin?

А) 91 B) 27 C) 88 D) 36 E) 120

6. Bitta ham elementga ega bo’lmagan to’plam

1. 
   cheksiz to`plam B) bo`sh to`plam C) chekli to`plam D) nol
   

7. А={1,2,3,4,5,6} to’plamdagi «o’zaro tub» binar munosabatning qism to’plami

A) {(1,1), (1,2), (3,6), (5,6)} B) {(1,2), (2,5), (4,2)} C) {1, 2, 3, 4} D) {(2,3),(5,3)}
8. Qirrasining uzunligi 1 dan 10 gacha butun son bo`lgan hechta turli to`g`ri burchakli parallelepiped qurish mumkin?

А) 220 B) 156 C) 84 D) 36 E) 1024

9. 5 ta qora va 5 ta oq shashkani nechta usulda bitta qatorga terish mumkin?

A) 252 B) 154 C) 360 D) 180 E) нет правильного ответа

10. Matematikadan konferensiyada 4 talaba А, Б, С, Д qatnashishi kerak. Agar Б talabaning qatnasha olmasligi ma`lum bo`lsa, qolgan talabalarni ma`ruzachilar ro`yhatiga nechta usulda joylashtirish mumkin?

А) 24 B) 20 C) 4! D) 50 E) 12

_{11. 5!+6! ni hisoblang.}

A) 840 B) 84 C) 680 D) 180 E) 120

_12. Hisoblang.

A) 4 B) 6 C) 20 D) 9 E) 5

13. (a+b)¹⁰ binom yoyilmasining 2-hadi oldidagi koeffitsiyentni toping.

A) 12 B) 16 C) 6 D) 10 E) 14

14. Tenglamani yeching.

A) 12 B) 10 C) 6 D) 5 E) 2