Базовые элементы электрических цепей

Solution

Solution

1. The number of independent circuits - 2.

2. Set the direction of flow of the loop currents (clockwise) and designate them I11 and I22.

3. We compose equations according to the 2nd Kirchhoff's law for 2 independent contours.

R1 I11 + R2 I11 - R2 I22 = E1-E2

R2 I22 + R3 I22 + R4 I22– R2 I11 = E2

We substitute the values ​​of the parameters into the equations and group the coefficients with the same currents:

8 I11 - 4 I22 = 12 8 I22– 4 I11 = 12

4. Solve the equations.

From the 1st equation I22 = (8 I11 - 12) / 4 = 2 I11 - 3 (1)

Substitute the expression into the second equation: 16 I11 - 24 - 4 I11 = 12

12 I11 = 36 I11 = 3

From the formula (1) I22 = 3

5. We arbitrarily set the direction of real currents and designate them II, I2, I3.

6. We calculate the real currents through the circuit.