6441-Nusxalash frezalash dasgoxi asosida tezliklar qutisini loyixalash

KIRISH.
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6441-Nusxalash frezalash dasgoxi asosida tezliklar qutisini loyixalash.

1. SHipindelning eng kichik aylanishlar soni – n_min=80 ayl/daq
2. SHipindelning eng katta aylanishlar soni – n_min=1700 ayl/daq
3. Tezliklar soni va formulasi – Z=24=3х4х2
4. Eng kata ishlov berish o‘ lchamlari – B=85 mm, L=1356 mm, h=4 mm.
5. Ishlov beriladigon material - Сталь 40 Г Ϭ_b =583 MPA
Grafik qism: Dastgoh kinematik sxemasi va tezliklar qutusisining tarkibiy turi.
Struktura setkasi;

IV) =(2650/85)^-(z-1)= 1.14

Buni standartdan 1.12 deb qabul qilib olamiz.
Aylanishlar chastotasi grafigini quramiz


Aylanishlar chastotasi grafigi yordamida vallar orasidagi uzatishlar munosabatlarini hisoblab chiqamiz:
i₁=1; i₂=1/1.12; i₃=1/1.26; i₄=1/1.41; i₅=1;
i₆=1/1.41; i₇=1/1.97; i₈=1.58; i₉=1/2.4
Tishli g’ildirakdagi tishlar sonini aniqlashda yuqoridagi natijalar asosida [5] 6-jadvaldan Ez=113 ni tanlab olamiz va i₁=z₁/z₂ … i₉=z₁₇/z₁₈ formula orqali hisoblab chiqamiz.
Z₁=57; Z₂=56; Z₃=53; Z₄=60; Z₅= 50; Z₆=63;
Z₇=47; Z₈=66; Z₉=57; Z₁₀=56; Z₁₁=47; Z₁₂=66; Z₁₃=26; Z₁₄=75; Z₁₅=44; Z₁₆=69; Z₁₇=38; Z₁₈=78;

Endi shu hisob kitoblar asosida uzatishlar pog’onasining kinematik sxemasini quramiz:

Hisobot uchun yetishmayotgan parametrlarni aniqlash:
1. Frezaning maksimal diametri:
D_max=1.25*B_max=1.25*85=100
2. Maksimal frezalash chuqurligi
T_max=h (mm) h=4 mm
3. Frezaning tishlar soni:
(2.3.6-jadvaldan) z=12
4. Frezalashda har bir tishga mos keluvchi surish miqdori:
(2.3.2-2.3.3 jadvaldan)
S_z1=0.09-0.11 mm/ayl
5. Frezaning turg‘unlik davri ;
T – 2.2.8 – jadval ;
T – 180 min
6. Kesish tezligi:
V_N=(Cv*D^qv_max)/(T^m*tmax^xv*Sz^yv*Bmax^uv*Z^’’Pv)*k_v=333
5.(2.3.7-jadvalda):
C_v=332; q_v=0.2; x_v=0.1; y_v=0.4; u_v=0.2; h=4mm
Pv=0; m=0.2; Kv=1.2; T=180; Kv_uv=1; C_m=1; n_v=1;
7. Kesish tezligi koeffitsenti:
Kv=K_mv*K_uv=1.2
8. Ishlov berilayotgan materialga bog‘liq koeffitsient:
K_mv – 2.3.10 jadval.
9. Kesuvchi asbobning kesuvchi qismi materialini xisobga oluvchi koeffitsient.
K_uv – 2.3.10-jadvaldan.
K_mv= 1.29; K_uv=1.29
10. Kesish tezligiga mos aylanishlar soni:

=1057 ayl/min
11. Xaqiqiy kessish tezligi:

m/min
12. Frezalashda hosil bo‘ladigon kesish kuchi:

.
C_p=825; X_P=1; y=0.75; u_p=1.1; q_p=1.3;
13.
14. Kesish kuchi koeffitsienti.
K_p- 2.1.9 – 2.1.10 - jadval.

15. Tezlika bog‘liq koeffitsient.
K_vp – 2.3.13 – jadval.
16. Maksimal quvvat.
N_max= 1.67*10^-5*P_z*V_x. (kvt)
N_max=1.67*10¹⁵10^-5*973*340=5.52
17. Elektrodvigitelning zaruriy quvvati.
N_max=(0.6……0.7)* (kvt)
N_e=(0.6*5.5)/0.8=4.1 kvt

Endi esa hisob kitoblarim natijasiga ko’ra kerakli quvvatga mos dvigatel tanlab oldim.

Dvigatel markasi: 4A132 8У3
Quvvati: N_dv=4 Kvt
Aylanishlar soni; 720 ayl/min.
Asosiy konstruktiv elementlarni aniqlash.
Vallarning quvvatini aniqlash:
N_i= N_dv*n_oi
n_oi=y*
y-surish qutisi uchun sarflanadigan quvvat koeffitsenti
ⁱ-0.96 tasmali uzatmadagi yo’qotish
ⁱ- 0.99 poshivmiklar uchun yo’qotish
ⁱ-0.99 tishli uzatmalar uchun yo’qotish
Vallardagi burovchi Moment:
Mi_max=9555*Ni/n_mini
n_mini- i valdagi minimal aylanishlar soni
Val diametrini aniqlash:
d_i =[Mi_max/(0.2*r)]^1/3
r-ruxsat etilgan kuchlanish; r=20MPa
Ushbu hisob kitoblarni har bir val uchun hisoblab val diametrlarini aniqlaymiz.
1-val uchun:
N_i= N_dv*n_oi=3.76
=0.96*0.99*0.99=0.94 M_1max=9555*3.76/720=50
d₁= [50/(0.2*20)]^1/3=23
2-val uchun:
N₂= N_dv*n_o2=3.5
=0.96*0.99²*0.99²=0,92
M_2max=9555*3,5/391=85
d₂= [85/(0.2*20)]^1/3=27
3-val uchun:
N₃= N_dv*n_o3=3.32
=0.96*0.99³*0.99³=0,9
M_3max=9555*0.32/198=160
d₂= [160/(0.2*20)]^1/3=34
4-val uchun:
N₄= N_dv*n_o4=3.12
=0.96*0.99⁴*0.99⁴=0.88
M_4max=9555*3.12/90=331
D₄= [331/(0.2*20)]^1/3=43
Tishli g’ildiraklarning ilashish modulini aniqlash.
m_i= [2000*M_Fi*Y_Fi/(z_i* Ψ*G_Fp)]^1/3
Ψ=8 Tishli g‘ildiraklarni enni hisobga oluvchi koeffitsent;
Y_Fi- Tish xolatini hisobga oluvchi koeffitsent 9-jadvaldan
Z_i= burovchi moment kata bo‘lgan tishlar soni.
M_Fi=M_imax*K_Fv*K_Fb
G_Fp=(G_Flimb/S_F)*K_Fl*K_Fc
S_F=2; K_Fe=1.03; K_Fc=1
G_Flimb=600 MPa
G_Fp=(G_Flimb/S_F)*K_Fl*K_Fc=309
1- val uchun ilashish moduli
M_Fi=M_imax*K_Fv*K_Fb=60
M_1.2= [2000*M_Fi*Y_Fi/(z_i* Ψ*G_Fp)]^1/3=1.5
2-val uchun ilashish moduli
M_Fi=M_imax*K_Fv*K_Fb=102
M₂= [2000*M_Fi*Y_Fi/(z_i* Ψ*G_Fp)]^1/3=1.8
3-val uchun ilashish moduli
M_Fi=M_imax*K_Fv*K_Fb=192
M₃= [2000*M_Fi*Y_Fi/(z_i* Ψ*G_Fp)]^1/3=2.4
4-val uchun ilashish moduli
M_Fi=M_imax*K_Fv*K_Fb=2.4
M₄= [2000*M_Fi*Y_Fi/(z_i* Ψ*G_Fp)]^1/3=397

M_o‘rt= =1.95

vallar uchun standart qatordan m=2 modulni tanlab oldim.
Tezliklar uzatmalar qutusini konstruktiv o’chamlarini aniqlash.
Bo’luvchi diametr – d_i=m*z
Tashqi diametr – d_ai=d_i+2m
Ichki diametr – d_fi=d_i-2.5m
Vallar orasidagi masofa – A_w=(d_k+d_sh)/2.

d_i¹=2*53=106 d_a¹=106+4=110 d_fi¹=106-5=101

d_i¹¹=2*60=120 d_a¹¹=120+4=124 d_f¹¹=120-5=115
d₁=2*57=114 d_a1=114+4=118 d_f1=118-5=109
d₂=2*56=112 d_a2=112+4=116 d_f2=112-5=107
d₃=2*53=106 d_a3=106+4=110 d_f3=106-5=101
d₄=2*60=120 d_a4=120+4=124 d_f4=120-5=115
d₅=2*50=100 d_a5=100+4=104 d_f5=100-5=95
d₆=126 d_a6=130 d_f6=121
d₇=94 d_a7=98 d_f7=89
d₈=132 d_a8=136 d_f8=129
d₉=114 d_a9=118 d_f9=109
d₁₀=112 d_a10=116 d_f10=107
d₁₁=64 d_a11=98 d_f11=89
d₁₂=132 d_a12=136 d_f12=129
d₁₃=76 d_a13=72 d_f13=71
d₁₄=150 d_a14=154 d_f14=145
d₁₅=88 d_a15=92 d_f15=83
d₁₆=138 d_a16=143 d_f16=133
d₁₇=76 d_a17=80 d_f17=75
d₁₈=150 d_a18=154 d_f18=149

Shponka tanlash:

2-val uchun
Val diametri d=27 ga mos shponka razmerlarini jadvaldan tanlab olamiz
b=8
L=18 … 90
4-val uchun
Val diametri d=43 ga mos shponka razmerlarini jadvaldan tanlab olamiz
b=12
L=28 … 140
Podshivnik tanlash
Val diametriga mos podshivniklarni jadvaldan o’lchamlarini tanlab oldik
1-val uchun
Val diametri d_v=23 bolgani uchun bunga standart qatordan
304 markali ya’ni ichki diametri 20 ga teng bo’lgan podshipnik tanlab oldik va o’lchamlarini tanlab oldik
d=20; D=52; B=15 r=2.0;
D_w=(D-d)*0.32= 32*0.32=10.24
S=0.15*(D-d)=0.15*32=4.8
2-val uchun
Val diametri d_v=27 bolgani uchun bunga standart qatordan
305 markali ya’ni ichki diametri 25 ga teng bo’lgan podshipnik tanlab oldik va o’lchamlarini tanlab oldik
d=25; D=62; B=17; r=2.0;
D_w=(D-d)*0.32= 37*0.32=12.95
S=0.15*(D-d)=0.15*37=0.72
3-val uchun
Val diametri d_v=30 bolgani uchun bunga standart qatordan
306 markali ya’ni ichki diametri 30 ga teng bo’lgan podshipnik tanlab oldik va o’lchamlarini tanlab oldik
d=30; D=72; B=19; r=2.0;
D_w=(D-d)*0.32= 32*0.32=10.24
S=0.15*(D-d)=0.15*32=4.8
4-val uchun
Val diametri d_v=34 bolgani uchun bunga standart qatordan
308 markali ya’ni ichki diametri 40ga teng bo’lgan podshipnik tanlab oldik va o’lchamlarini tanlab oldik
d=40; D=90; B=23; r=2.5;
D_w=(D-d)*0.32= 50*0.32=16
S=0.15*(D-d)=0.15*50=7.5
Podshipnik uchun Qopqoq tanlash
Podshivnik tashqi diametriga qarab jadvaldan unga mos qopqoq o’lchamlarini ko’chirib, shular asosida qopqoq yasaymiz.
1-podshivnik uchun: Ochiq qopqoq.
D=52; D₁=66; D₂=82; D₃=44; D₄=50;
d=7; d₁=12; d₂=14; n=4 H=15;
h=5; h₁=5; B=13; b=4; S=5;
D=72; D1=90; D2=110; D3=64
d=9; d1=15; d2=20; n=4
H=12; H2=26; h1=8; b=4; S=6
Yopiq qopqoq;
D=52; D₁=66; D₂=82; D₃=44;
d=4; d₁=12; d₂=14; n=4
H=10; H₂=20; h₁=5; b=4; S=5;

2-podshivnik uchun

D=62; D1=75; D2=95; D3=52
d=7; d1=12; d2=14; n=4
H=10; b=4;
3-podshivnik uchun
D=72; D₁=90; D₂=110; D₃=62;
d=9; d₁=15; d₂=20; n=4
H=12; b=4;
4-podshivnik uchun
D=90; D1=100; D2=130; D3=72
d=9; d1=15; d2=20; n=4
H=12; b=4;