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NATURAL SONLAR USTIDA TO‘RT AMALGA DOIR MASALALAR
YECHISH. AMALLARNI BAJARISH TARTIBI
Sinfda bajariladigan topshiriqlar
1.
Ifodada amallarni bajarish tartibini aniqlang va uning qiymatini toping:
a) 78-45+54-49; b) 231+112-223-109;
d) 721:7 - 112:8+37∙22; e) 322:23–22–483-9:23;
f) 315:(375-24∙15)+98; g) (24∙7-676:13)∙13-238.
Namuna:
Yuqorida ko‘rilgan 1-, 2-, 3-, 4- misollar.
2.
Hisoblang:
a) (56-56):342+(289-288)∙122; b) (56+46)∙23+(444-443)∙34.
3.
Ifodaning qiymatini toping:
a) 48-29+37-19; b) 156+228-193-66;
d) 245:7 - 224:16+35∙11; e) 322:23∙70-161∙9:69;
f) 315:(162+12∙24-11∙39)+5581; g) (24∙7-377:29)∙(2378:58-38);
h) (120+16∙7)∙240:(300-5∙44); i) (372+118∙6):(38∙35-34∙37).
4.
Qo‘shish va ayirish xossalariga tayangan holda ifodaning
qiymatini qulay usulda
hisoblang:
a) 348+37+63; b) 54∙4∙25; d) 378+89-78;
e) 51∙8+49∙8; f) 427-73-27; g) 125∙65-25∙65.
5.
37+5∙7-3 ifodaga qavslarni imkoni bor hamma holatlarda qo‘ying va hosil bo‘lgan
har bir ifodaning qiymatini toping.
6.
Ifoda tuzing va uning qiymatini toping:
a) 24∙11 ko‘paytma va 96:3 bo‘linmaning yig‘indisi;
b) 510 sonidan 236+128 yig‘indining ayirmasi;
d) 27+3 yig‘indining 52-22 ayirmaga ko‘paytmasi;
e) 31+29 yig‘indining 30 soniga bo‘linmasi.
7.
Hisoblang:
a) 97+13662:27+36944-43∙809;
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d) (31 ∙ 9 - 754 : 29) ∙ (1323 : 27 - 31);
e) (186 + 59 ∙ 6): (19 ∙ 35 - 17 ∙ 37) - 12.
3.
Qo‘shish va ayirish xossalanga tayangan holda amallarning
balanlish tartibini
o‘zgartihng va qulay usulda ifodaning qiymatini hisoblang:
a) 56+ 88+44; b) 224 ∙ 4 ∙ 250;
d) 13245 + 8899 – 3245;
e) 87 ∙ 33+ 13 ∙ 33; f) 1555 – 234 –766; g) 1199 ∙ 678 – 199 ∙ 678.
4.
Ifodani soddalshtihng:
a) 11a+ 43 +76a+ 27; b) 332y + 211y + 999 + 677;
d) 234+
35a
+ 725+16a; e) 781 - 455 + 37n + 39n.
5.
Ifodaning qiymatini toping:
a) 66 ∙ 24 :22+ 17017 : 17; b) (42 ∙ 25 - 36) : 39 + (800 : 40 - 18) ∙ 12.
d) 9 ∙ (1030 -579) + 941; e) 8000 - (398+ 132) ∙ 15;
f) (770 - 669) ∙ (546 - 489); g) 136 ∙ (668-588) -404 ∙ 25;
h)1540 : 11 + 1890 : 9 + 982; i) 1953 + (17432 – 56 ∙ 223) : 16.
6.
Tenglamani yeching:
a) 3
x
+ 5
x
+ 96 = 1568; b)
2y
+ 7
y
+ 78 = 1581;
d) 88 880: 110+
x
=809; e) 357y-149y-1843 = 11 469;
f) 256m - 147m - 1871 =63 747; g) 6871 + p: 121 =7000.
7.
Velosipedchilar birinchi kuni 154 km, ikkinchi kuni birinchi kundan 23 km ko‘p,
uchinchi kun esa ikkinchi kundan 13 km kam masofani bosib o‘tdilar.
Velosipedchilar uch kunda qancha masofa bosib o‘tishgan?
8.
Tikuv sexida har biri 30 m dan bo‘lgan 9 to‘p va har biri 40 m dan bo‘lgan 13 to‘p
mato boredi. Bu matoning 243 metri ishlatildi. Sexda necha metr mato qoldi?
9.
Sayohatchi bir shahardan ikkinchisiga bormoqchi. U oldin avtomobilda 70 km/soat
tezlikda 2 soat yo‘l bosdi. So‘ng piyoda 4 soat 5 km/soat tezlik bilan yurdi. Shunda,
ikkinchi shahargacha yana 14 km yo‘l qoldi. Bu shaharlar orasidagi masofa qancha?