Variant-3 Matematika Uchta a, b va c natural sonlar yig‘indisi log3(3x − ) = − X tenglamani

qizinchi hadlari yig‘indisi 2x² – 8x + 24 a³+2a²-5a-6 soddalshtring

uch hadning eng kichik qiymatiga teng bo‘lsa, bu (aЄ (‒ 1; 2) ).A)1/(a+3)

arifmetik progressiyaning dastlabki 11 ta hadining B)1/(a+1) C)1/a-1 D)1/a-3

yig‘indisini toping. 11. log₄²12+4log₄12•log₄(1/3)+3log₄²(1/3)

A) 66 B) 55 C) 44 D) 88 log₄12+3log₄(1/3)

4.(3lg(-x))^1/2 =lg|x| tenglamaning ildizlari ko‘paytma- A)2 B)3 C)1 D)-2

sini toping. 12. x+log_1/2y=log_1/2x-0.5y

A) – 1 B) – 1000 C) – 1001 D) 1000 log_1/2x-7x=log_1/2y-2.5y

5. x+x²+x³+.........+x²⁰¹⁷+x²⁰¹⁸ sodalashtring tenglamalar sistemasidan x+y=?

x^-1+x^-2+x^-3+...+x^-2017+x^-2018. A)7/2 B)5/2 C)3/2 D)tjy

A)1 B)x C)x²⁰¹⁷ D)x²⁰¹⁸ 13.Quydagi tenglamani butun

6.𝑎𝑎𝑏𝑏 ̅̅̅̅̅̅̅ (a va b raqamlar) to‘rt xonali son qandaydir sonlar da iborat yechimini yigin-

biror sonning kvadrati bo‘lsa, a – b ayirmani toping. disini toping. y²-xy-2x²-13=0

A)-1 B)1 C)0 D)2

14. Uchta son arifmetik progressiyani hosil qiladi. Bu sonlarning yig'indisi 189 ga teng Birnchi son uchinchi sondan 2 marta katta.Bu sonlarnin kichigini toping?

A)35 B)36 C)42 D)aniqlab bulmaydi

15.x>0,y>0,z>0,t>0 x,y,z −arifmetik progressiyaning ketmaket hadlari, y,z,t−geometrik progreesiyaning ketma-ket hadlari hamda, x+y+z=12, y+z+t=19 bulsa, t=? A)6 B)7 C)9 D)-7 16.M(3;4) nuqtadan 3x + 4y −1= 0 tog'ri chiziqgacha bo'lgan masofani toping? J:

17.Agar a=(4)^1/3+(2)^1/3+1 bulsa, (3/a)+(3/a²)+(1/a³) ning qiymatini toping? A)2 B)-2 C)1 D)-1

18.Hisoblang: (5+6)(5²+6²)(5³+6³)...(5¹⁰²¹+6¹⁰²⁴)+5²⁰⁴⁸

3¹⁰²⁴ A)3¹⁰²⁴ B)4¹⁰²⁴ C)12¹⁰²⁴ D)5/3

19.sodalashtring:



A)a B)b C)c D)x

20.hisoblang:A)3 B)-3 C)-4 D)4

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