12
;
10
60
10
80
10
140
10
4
10
2
10
10
)
10
4
10
1
10
2
(
20
)
(
)
0
(
)
0
(
)
(
3
3
3
3
3
3
3
3
3
3
1
3
2
1
3
2
1
3
1
11
P
P
P
P
R
R
P
I
R
R
R
P
u
R
R
R
R
R
P
I
P
u
p
c
c
);
(
)
(
;
10
75
,
1
10
12
10
60
10
75
,
1
10
12
10
60
)
(
)
(
)
(
2
1
9
6
3
9
6
3
11
11
P
I
P
I
F
F
P
P
P
P
P
P
P
I
k
c
;
10
75
,
1
10
12
10
60
)
(
2
1
9
6
3
F
F
P
P
I
c
Sigimdagi kuchlanishning tasviri:
3.4) Yoyish teoremasidan foydalanib tok va kuchlanishlarning haqiqiy qiymatlarini
hisoblaymiz:
n
k
t
P
k
c
c
k
e
A
t
i
P
I
1
)
(
)
(
, bu yerda
)
(
)
(
1
2
1
k
k
k
P
F
P
F
A
;
yoki
)
(
)
(
lim
P
F
P
P
A
k
P
P
k
k
;
Tok tasvirining mahrajini nolga tenglashtirib, uning ildizlarini aniqlaymiz va tok
originalini topamiz:
F
2
=12
·10
6
p+1,75
·10
9
=0
;
)
(
)
(
)
(
;
6
14
10
12
10
75
,
1
1
1
2
1
1
1
6
9
t
P
t
P
c
i
i
i
e
P
F
P
F
e
A
t
i
c
p
F
1
(p)= -60
·10
3
; F
1
(p
1
)= -60
·10
3
; F
2
(p)=12
·10
6
p+1,75
·10
9
; F
2
’(p)=12·10
6
;
;
10
5
10
12
10
60
146
3
146
6
3
A
e
e
t
i
t
t
c
A
e
t
i
t
c
146
3
10
5
Pkt
c
C
e
Pk
F
Pk
Pk
F
F
F
t
U
p
F
p
p
F
p
p
p
P
U
'
0
0
10
75
,
1
10
12
10
20
10
240
2
3
2
3
2
3
9
6
9
6
Kuchlanish tasvirining mahrajini nolga tenglashtirib uning ildizlarini va kuchlanish
originali ifodasini topamiz:
;
)
(
)
(
)
10
75
,
1
10
12
(
10
20
10
240
)
10
75
,
1
10
12
(
10
35
10
240
10
15
20
4
)
10
75
,
1
10
12
(
10
60
20
10
4
1
10
75
,
1
10
12
10
60
)
0
(
1
)
(
)
(
2
3
3
6
9
6
3
6
9
6
9
3
6
3
6
3
6
3
P
F
P
P
F
p
p
p
p
p
P
p
p
P
p
p
p
u
pC
p
I
p
U
c
c
c
13
t
u
1
(t)
t
u
U
0
0
;
0
10
75
,
1
10
12
9
6
2
p
p
p
F
p
;
0
0
p
;
146
1
1
c
p
;
10
20
10
240
9
6
3
p
p
F
9
3
10
20
0
F
;
10
15
10
20
146
10
240
10
20
10
240
9
9
9
1
6
1
3
p
P
F
;
10
75
,
1
10
12
9
6
2
p
P
F
;
10
75
,
1
0
9
2
F
)
10
75
,
1
10
12
146
(
'
9
6
1
2
1
P
F
P
B
e
e
t
U
t
t
c
146
146
9
9
9
9
58
,
8
42
,
11
10
75
,
1
10
15
10
75
,
1
10
20
B
e
t
U
t
c
146
58
,
8
42
,
11
O'tish toki va kuchlanishining topilgan qiymatlari, klassik usulda hisoblab topilgan
qiymatlar bilan mos keldi.
2 – topshiriq
1. O'TISh JARAYONINI VAQT USULIDA HISOBLASh
Barcha variantlar uchun zanjir kirishidagi videoimpuls beriladi.
3.1. N variant nomeri bo'yicha (N-talabaning gurush jurnalidagi tartib raqami)
sxema tanlang va uning elimentlari qiymatlarini hisoblang. (3.1-va 3.2-rasmlar).
;
В
К
М
U
c
T
u
=5
τ;
;
,
2
2
мкГн
К
M
L
мкФ
К
М
C
,
2
R=(М+К),Ом;
bu yerda M- guruh nomerining oxirgi raqami,
K=2 AEA fakulteti uchun;
K=4 MEA fakulteti uchun;
K=6 RRT fakulteti uchun;
K=8 maxsus fakulteti uchun.
3.2. Berilgan zanjirning o'tish xarakteristikasini hisoblang.
3.3. 0
t
t
4
oraliqda amplitudasi U
0
va uzunligi t
u
ga teng bo'lgan videoimpuls
tasirida zanjir chiqishida hosil bo'ladigan U
2
(t) kuchlanishning ifodasini yozing.
3.4. t
4
t
oraliqda zanjir chiqishida hosil biladigan U
2
(t) kuchlanish ifodasini
yozing.
3.5. U
2
(t) o'tish kuchlanish uchun vaqtning 8 ta qiymatida (bulardan 4 tasi 0
t
t
4
oraliqda va 4 tasi t
4
t
oraliqda)
son qiymatlar jadvalini tuzing.
3.6. U
2
(t) o'tish kuchlanish grafigini chizing.
16
Hisoblash uchun namuna.
1) boshlang'ich ma'lumotlar U
0
=40B; L=10мкГн;
R=4Ом; t
u
=5
τ
2.3-rasm. Tekshirilayotgan sxema.
2) operator usulidan foydalanib, berilgan zanjirning o'tish xarakteristikasi h(t) ni
hisoblaymiz.
2.1) birlamchi ta'sir (3.4-rasm) va nolinchi boshlangich shartlar uchun ekvivalent
operator sxema tuzamiz;
P
p
V
1
)
(
1
2.4-Operator o'rin almashish sxemasi.
2.2) operator uzatish funktsiyasidan foydalanib, U
2
(P) ni aniqlaymiz:
;
2
1
2
R
pL
R
pL
R
pL
R
P
I
PL
R
P
I
P
V
P
V
P
H
p
F
p
P
F
R
pL
P
R
PL
p
V
p
H
p
V
2
1
1
2
2
2.3) Bizga ma'lum bo'lgan U
2
(P) tasvirdan foydalanib haqiqiy qiymat (original) ni
aniqlaymiz:
;
2
t
h
t
u
R
PL
P
R
PL
p
V
t
h
2
2
Yoyish teoremasidan foydalanib qidirilayotgan vaqt funktsiyasi h(t) ni aniqlaymiz:
P
F
P
P
F
R
PL
P
R
PL
P
V
2
1
2
2
bu yerda
;
1
R
PL
P
F
17
дан
R
PL
P
F
0
2
2
1
5
1
10
8
2
c
L
R
p
F
2
(P) bitta P
1
ildizga ega bo'lgani sababli h(t) ning ifodasi quyidagicha bo'ladi:
t
P
e
P
F
P
P
F
F
F
t
h
1
1
2
1
1
1
1
'
0
0
Bu ifodaning alohida elimentlarini topamiz:
F
1
(p)=pL+R; F
1
(0)=R;
;
2
1
1
R
R
L
L
R
P
F
F
2
(p)=pL+2R; F
2
(0)=2R; F
2
(P
1
)=L;
R
L
L
R
p
F
P
2
2
'
1
2
1
Shunday qilib,
t
t
L
R
e
e
R
R
R
R
t
h
5
10
8
2
2
1
2
1
2
2
t
t
e
e
t
h
5
,
0
5
,
0
5
,
0
5
,
0
5
10
8
3) 0
t
t
4
oraliqda U
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