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Natijada bir oy davomida n=392 ta soʻzlashuv amalga oshirilganligini aniqlaymiz.
Necha minutlik soʻzlashuvlar nechta ekanligini aniqlash uchun esa
Excel
→
CТАТИСТИЧЕСКИЕ
→
СЧЁТЕСЛИ
→
buyrugʻidan foydalanamiz:
Qoʻlda hisoblashlarni soddalashtirish uchun formulalarga qoyib hisoblashda
yordamchi bir nechta ustunlarni ham qoʻshib hisoblab olamiz, natijada
1)
1-ustundagi sonlar 1-savolimizga javob boʻladi.
2)
3-ustundagi sonlar 2-savol javobi boʻladi.
3)
1-va 3-ustunlar esa biz qidirayotgan diskret tasodifiy miqdor taqsimot qonuni
boʻladi.
4)
Diskret tasodifiy miqdor taqsimot koʻpburchagini chizish uchun 3-ustundagi
sonlarni ajratib koʻrsatib, excelda diagramma chizamiz.
5)
Diskret tasodifiy miqdor taqsimot funksiyasi
𝑃(𝑋 < 𝑥) = 𝐹
𝑋
(𝑥) =
{
0.0 𝑎𝑔𝑎𝑟 𝑥 < 1
0.535 𝑎𝑔𝑎𝑟 1 ≤ 𝑥 < 2
0.770 𝑎𝑔𝑎𝑟 2 ≤ 𝑥 < 3
0.872 𝑎𝑔𝑎𝑟 3 ≤ 𝑥 < 4
0.908 𝑎𝑔𝑎𝑟 4 ≤ 𝑥 < 5
0.949 𝑎𝑔𝑎𝑟 5 ≤ 𝑥 < 6
0.964 𝑎𝑔𝑎𝑟 6 ≤ 𝑥 < 7
0.969 𝑎𝑔𝑎𝑟 7 ≤ 𝑥 < 8
0.981 𝑎𝑔𝑎𝑟 8 ≤ 𝑥 < 9
0.988 𝑎𝑔𝑎𝑟 9 ≤ 𝑥 < 10
0.99 𝑎𝑔𝑎𝑟 10 ≤ 𝑥 < 11
0.99 𝑎𝑔𝑎𝑟 11 ≤ 𝑥 < 12
0.995 𝑎𝑔𝑎𝑟 12 ≤ 𝑥 < 13
1.000 𝑎𝑔𝑎𝑟 𝑥 ≥ 13
Taqsimot funksiya qabul qiladigan qiymatlar sifatida 4-ustundagi
qiymatlardan foydalanamiz.
6)
Taqsimot funksiya grafigini chizishda aynan 4-ustundagi sonlarni ajratib
koʻrsatib diagramma chizilsa kifoya
7)
Matematik kutilmani topamiz
𝑀𝑋 = ∑ 𝑥
𝑖
∙ 𝑝
𝑖
= 2.060
𝑘
𝑖=1
Excel
→
Математические
→
СУММПРОИЗВ
→
Массив1 degan joyga
𝑥
𝑖
ustunni, Массив2 degan joyga
𝑝
𝑖
ustundagi sonlar oʻrni koʻrsatilsa,
matematik kutilma dasturning oʻzi xisoblab beradi.
8)
𝐷𝑋
Dispersiyani hisoblash
𝐷𝑋 = 𝑀(𝑋 − 𝑀𝑋)
2
= ∑
(𝑥
𝑖
− 𝑀𝑋)
2
∙ 𝑝
𝑖
= 3.156
𝑘
𝑖=1
bunday
koʻpaytmalar
yigʻindisini yordamchi jadvalimizda hisoblab qoʻyganmiz
Excelda dispersiyani hisoblash uchun, yana Excel
→
Математические
→
СУММПРОИЗВ
→
buyruqdan foydalanish mumkin, faqatgina kerakli massivlarni
koʻrsatsak boʻlgani.
9)
Oʻrtacha kvadratik chetlanishni topish uchun dispersiyadan ildiz olsak boʻlgani:
𝜎(𝑋) = √𝐷𝑋 = √3.15689 = 1.77676391
10)
Diskret tasodifiy miqdor modasi, bu X tasodifiy miqdorning eng katta
ehtimolli qiymatidir.
𝑀
𝑜
= 1
11)
𝑃(𝑋 < 3) = 𝑃(𝑋 = 1) + 𝑃(𝑋 = 2) = 0.77040816
12)
𝑃(𝑋 = 2 𝑦𝑜𝑘𝑖 𝑋 = 3) = 𝑃(𝑋 = 2) + 𝑃(𝑋 = 3) = 0.337
13)
𝑃(𝑋 > 1) = 1 − 𝑃(𝑋 = 1) = 1 − 0.536 = 0.464
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