Darsning borishi:
I.Tashkiliy qism:
Salomlashish;
Davomatni tekshirish
Darsning maqsadini aytish.
II.O’tgan mavzuni so’rash va mustahkamlash.
Uyga vazifa tekshirib chiqiladi. Og’zaki savol –javob o’tkazaman.
III.Yangi mavzu bayoni:
1 1-misoldagi yig‘indini songa bo’lish ikki usulda ko‘rsatib beriladi. Har ikki usul ta’riflanadi va tushuntiriladi.
2-masala
Birinchi o‘ramda 30 m, ikkinchisida 24 m gazlama
bor. Agar bitta ko‘ylak uchun 3 m gazlama sarflansa, ikkala o‘ramdagi jami gazlamadan nechta ko‘ylak tikish mumkin?
Yechish:
(30+24) :3= 54:3=18
Javob: 18ta ko’ylak tikish mumkin
3-misol
. (80 + 60) : 2=140:2=70 (90 + 120) : 3=210:3=70
(240 + 320) : 80 =560:8= 70 (100+50) : 50= 150:50=3
(80 + 160) : 40 = 240:40=6 (180 + 540) : 9=720:9=80
4. Yechilishini tushuntiring:
86 : 2= (80+6):2= 80:2+6:2= 40+3=43 84 : 4=80:4+4:4=20+1=21
55 : 5 88 : 8
66 : 6 96 : 3 63 : 3 48 : 2
Namuna: 86 : 2 = (80 + 6) : 2 = 80 : 2 + 6 : 2 = 40 + 3 = 43
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