Organic Chemistry I


Integration and Coupling in



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Integration and Coupling in
13
C NMR
Unlike
1
H NMR, the area under a
13
C NMR signal
cannot
easily be used to determine the number of carbons to which
it corresponds. The signals for some types of carbons are inherently weaker than for other types, for example peaks
corresponding to carbonyl carbons are much smaller than those for methyl or methylene (CH
2
) peaks. For this reason,
signal integration is generally not useful in
13
C NMR spectroscopy.
Because of the low natural abundance of
13
C nuclei, the spin-spin coupling between two nonequivalent
13
C atoms
is negligible.
13
C nuclei are coupled to nearby protons, however, which results in complicated spectra. For clarity,
chemists generally use a technique called
broadband decoupling
, which essentially ‘turns off’ C-H coupling, resulting
in a spectrum in which
all carbon signals are singlets
.
Below is the proton-decoupled
13
C NMR spectrum of ethyl acetate
in CDCl
3
(
Fig. 6.8a
), showing the expected four signals, one for each of the carbons.
6.8 ¹³C NMR Spectroscopy | 229


Figure 6.8a The 13C NMR spectrum of ethyl acetate
For our class purpose,
13
C NMR spectra are usually used as supporting information to confirm the structure of a
compound.
Exercises 6.2
Below are
13
C NMR spectra for methylbenzene (common name toluene) and methyl methacrylate. Refer
to
Table 6.3
to match the spectra to the correct structure.
230 | 6.8 ¹³C NMR Spectroscopy


Answers to Practice Questions Chapter 6
6.8 ¹³C NMR Spectroscopy | 231


6.9 Structure Determination Practice
1
H NMR provides a powerful tool for determining the structure of unknown compound. Other than that
1
H NMR,
additional information includes molecular formula, IR and
13
C NMR spectrum are usually provided as well. Solving the
structure of an unknown compound based on all the given information is an important type of question we will work
on for this chapter. We will take the C
5
H
12
O constitutional isomer example to go through the strategy for solving this
type of question.

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