for this normalized transfer function).
3.2 Frequency Response Function
2
1 2
n
ω ω
ζ
=
−
0
1 / 2
ζ
< <
1 / 2
ζ
≥
Ch. 3: Forced Vibration of 1-DOF System
3.2 Frequency Response Function
Ex. 3 Consider the pivoted mechanism with k=4x10
3
N/m,
l
1
=0.05 m, l
2
=0.07 m, l=0.10 m, and m=40 kg.
The mass of the beam is 40kg which is pivoted
at point O and assumed to be rigid. Calculate c
so that the damping ratio of the system is 0.2.
Also determine the amplitude of vibration of the
steady-state response if a 10 N force is applied
to the mass at a frequency of 10 rad/s.
Ch. 3: Forced Vibration of 1-DOF System
( )
( )
(
)
1
2
2
1
1
2
2
1
2
1
2
12
2
0.1 10 cos10
0.5
0.0049
59.05
0.0049
15.37, 0.2
, 627.3
Ns/m
2 0.5
O
O
n
n
l
l
M
I
Fl
mgl
Mg
c l
l
k l
l
l
l
l
l
ml
M
M
t
c
c
c
θ
θ
θ
θ
θ
θ
θ
θ
θ
ω
ζ
ω
ω
−
⎛
⎞
⎡
⎤
=
−
−
−
−
⎜
⎟
⎣
⎦
⎝
⎠
⎡
⎤
+
−
⎛
⎞
=
+
+
⎢
⎥
⎜
⎟
⎝
⎠
⎢
⎥
⎣
⎦
×
=
+
+
=
=
=
=
×
×
=
∑
( )
(
)
(
)
10, 0.6506
1
0.02677
24.268
59.05 0.5767
0.26
0.02677 cos 10
0.424
ss
r
H i
i
t
ω
θ
=
=
=
−
°
+
=
−
3.2 Frequency Response Function
Ch. 3: Forced Vibration of 1-DOF System
Ex. 4 A foot pedal for a musical instrument is modeled
as in the figure. With k=2000 kg/s
2
, c=25 kg/s,
m=25 kg, and F(t)=50cos2πt N, compute the
steady-state response assuming the system starts
from rest. Use the small angle approximation.
3.2 Frequency Response Function
Ch. 3: Forced Vibration of 1-DOF System
(
)
(
)
( )
(
)
2
2
0.15
0.05
0.05
0.05
0.1
0.15
5
100
3.75
50 cos 2
, positive CW
6
3
Find the parameters
2.98, 0.0373, 2 , 2.108
1
0.0087
177.4
1
2
since
0, the transie
O
O
n
M
I
F
k
c
m
t
r
H i
k
r
i
r
θ
θ
θ
θ
θ
θ
θ
π
ω
ζ
ω
π
ω
ζ
ζ
⎡
⎤
=
×
−
×
−
×
= ×
⎣
⎦
+
+
=
=
=
=
=
=
=
−
°
− +
≠
∑
( )
(
)
(
)
0
nt response will die out
cos
0.435 cos 2
3.096
ss
F H i
t
t
θ
ω
ω θ
π
=
+
=
−
3.2 Frequency Response Function
Ch. 3: Forced Vibration of 1-DOF System
3.3
Applications
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
Ch. 3: Forced Vibration of 1-DOF System
3.3 Applications
(
)
(
)
(
)
(
)
2
2
2
2
2
2
2
2
2
2
measured acc.
10
1
actual acc.
9.81
1
2
1
2
0.962
From the problem statement,
628 rad/s,
1
628 rad/s
1
1
758 rad/s
,
0.56
2
1
5745.6 N/m,
8.49 Ns/
n
d
n
d
d
n
n
z
y
r
r
r
r
r
k
c
m
m
k
c
ω
ζ
ζ
ω
ω
ω
ζ
ω
ω
ζ
ω
ω
ζ
ω
ζ
=
=
=
−
+
−
+
=
=
=
−
=
=
=
−
=
=
=
=
=
−
=
=
m
Ch. 3: Forced Vibration of 1-DOF System
3.4
Periodic Excitation
A periodic function is any function that repeats itself in
time, called period T.
It is more general than the harmonic function. Here, we
will find the response to the input that is a periodic
function. The idea is to decompose that periodic input
into the sum of many harmonics. The response, by the
superposition principle of linear system, is then the sum
of the responses of individual harmonic. The response
of a harmonic function was studied in section 3.1
3.4 Periodic Excitation
( )
(
)
f t
f t T
=
+
Ch. 3: Forced Vibration of 1-DOF System
Fourier found the way to decompose the periodic
function into sum of harmonic functions (sine & cosine)
whose frequencies are multiples of the fundamental
frequency. The fundamental frequency is the frequency
of the periodic function.
3.4 Periodic Excitation
Ch. 3: Forced Vibration of 1-DOF System
Fourier series
3.4 Periodic Excitation
( )
(
)
( )
( )
( )
0
0
0
0
0
1
0
0
0
0
Fourier series in real form:
2
cos
sin
,
2
Fourier coefficients:
2
cos
,
0,1, 2,
2
sin
,
1, 2, 3,
Fourier series in complex form:
n
n
n
T
n
T
n
in
t
n
n
a
f t
a
n
t
b
n
t
T
a
f t
n
t dt
n
T
b
f t
n
t dt
n
T
f t
C e
ω
π
ω
ω
ω
ω
ω
∞
=
∞
=−∞
=
+
+
=
=
=
=
=
=
∑
∫
∫
…
…
( )
0
0
0
2
,
Fourier cofficients (complex):
1
,
, 2, 1, 0,1, 2,
T
in
t
n
T
C
f t e
dt
n
T
ω
π
ω
−
=
=
=
− −
∑
∫
…
…
Ch. 3: Forced Vibration of 1-DOF System
Some properties of Fourier series
3.4 Periodic Excitation
)
( )
)
( )
)
( )
)
( )
( )
0
0
0
1
1 If
is an even function,
0.
2 If
is an odd function,
0.
3
is the average value of
over one period.
2
4 If
is real,
2 Re
n
n
in
t
k
k
n
n
f t
b
f t
a
a
f t
f t
C
C
f t
C
C e
ω
∞
−
=
=
=
⎛
⎞
=
⇒
=
+
⎜
⎟
⎝
⎠
∑
Ch. 3: Forced Vibration of 1-DOF System
Frequency spectrum
tells how much each harmonic
contributes to the periodic function .
Plot of the amplitude of each harmonic vs. its frequency
is the (discrete) frequency spectrum.
3.4 Periodic Excitation
( )
f t
( )
2
2
0
0
In real form, the harmonic at
has the amplitude
In complex form, the harmonic at
has the amplitude 2 Re
n
n
n
n
a
b
n
C
ω
ω
+
Ch. 3: Forced Vibration of 1-DOF System
3.4 Periodic Excitation
Ch. 3: Forced Vibration of 1-DOF System
Superposition principle of linear system
3.4 Periodic Excitation
Ch. 3: Forced Vibration of 1-DOF System
Response to harmonic excitation
3.4 Periodic Excitation
Ch. 3: Forced Vibration of 1-DOF System
3.4 Periodic Excitation
( )
(
)
(
)
( )
(
)
0
0
0
0
0
0
2
0
0
0
1
0
0
1
From section 3.1,
1
where
1
2
2 Re
by superposition,
2 Re
in
t
n
in
t
ss
n
n
n
in
t
n
n
in
t
ss
n
n
mx cx
kx
F t
C e
x
C H in
e
H in
n
n
k
i
mx cx
kx
F t
C
C e
C
x
C H in
e
k
ω
ω
ω
ω
ω
ω
ω
ω
ζ
ω
ω
ω
∞
=
∞
=
+
+
=
=
=
=
⎛
⎞
⎛
⎞
⎛
⎞
⎜
⎟
−
+
⎜
⎟
⎜
⎟
⎜
⎟
⎝
⎠
⎝
⎠
⎝
⎠
⎛
⎞
+
+
=
=
+
⎜
⎟
⎝
⎠
⎛
=
+
⎝
∑
∑
⎞
⎜
⎟
⎠
Ch. 3: Forced Vibration of 1-DOF System
3.4 Periodic Excitation
response frequency spectrum
excitation frequency spectrum
system frequency response
Ch. 3: Forced Vibration of 1-DOF System
Ex.
Calculate the response of a damped system to
the periodic excitation f(t) depicted in the figure
by means of the exponential form of the Fourier
series. The system damping ratio is 0.1 and the
driving frequency is ¼ of the system natural freq.
3.4 Periodic Excitation
Ch. 3: Forced Vibration of 1-DOF System
3.4 Periodic Excitation
( )
( )
( )
( )
( )
0
0
0
0
0
/ 2
0
0
0
/ 2
odd
Expand
as sum of harmonic series
1
1
2
,
0, even
1
1
2
, odd
2
2
in
t
n
n
T
T
T
in
t
in
t
in
t
n
T
n
n
i n
in
t
n
f t
f t
C e
C
f t e
dt
Ae
dt
Ae
dt
T
T
T
n
iA
C
i A
n
n
n
i A
A
f t
e
e
n
n
ω
ω
ω
ω
ω
ω
π
ω
π
π
π
π
∞
=−∞
−
−
−
=
=
⎡
⎤
=
=
+
−
=
⎢
⎥
⎣
⎦
=
⎧
⎪
⎡
⎤
=
− −
= ⎨
⎣
⎦
−
=
⎪⎩
∴
=
−
×
=
×
∑
∫
∫
∫
∑
( )
( )
(
)
(
)
(
)
(
)
( )
(
)
0
2
0
odd
1,3,
0
2
2
1
2
2
2
2
0
1,3,
4
1
sin
1
, 0.1,
1
2
4
1
1
/ 4
0.05
1
0.05
,
tan
1
0.25
1
0.25
0.05
4
1
sin
t
n
n
n
n
n
n
n
n
ss
n
n
n
A
n
t
n
n
n
G i
r
r
i
r
G i
n
i
n
n
G
G
n
n
n
A
x
t
G
n
t
G
n
π
ω
π
ω
ω
ω
ζ
ζ
ω
ω
ω
ω
π
⎛
⎞
∞
−
⎜
⎟
⎝
⎠
=
=
−
∞
=
=
=
=
=
=
=
− +
=
−
+
−
=
=
−
⎡
⎤
−
+
⎣
⎦
∴
=
+
∑
∑
∑
…
…
Ch. 3: Forced Vibration of 1-DOF System
3.4 Periodic Excitation
Ch. 3: Forced Vibration of 1-DOF System
Ex.
The cam and follower impart a displacement y(t)
in the form of a periodic sawtooth function to the
lower end of the system. Derive an expression
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