O’qtuvchi: Tursunoy Nurmuxamedova. 2 – laboratoriya ishi real mustaqil kuchlanish va tok manbalarining tadqiqoti

NI Multisim dasturiy muhitida yig‘ilgan holati

Dastlabki hisoblashlar

Variant №23. E₂=9.2V.

- zanjirning tokini hisoblash:

𝑼 = 𝑰 ∗ 𝑹_𝒚𝒖𝒌; - yukdagi kuchlanishini hisoblash:

𝑈₁ = 𝐼₁ ∗ 𝑅_{𝑦𝑢𝑘1} = 16.7 ∗ 50 = 0,8 𝑉; 𝑈₅ = 𝐼₅ ∗ 𝑅_{𝑦𝑢𝑘5} = 6,1 ∗ 1000 = 6,1𝑉;

𝑈₂ = 𝐼₂ ∗ 𝑅_{𝑦𝑢𝑘2} = 15,3 ∗ 100 = 1,53 𝑉; 𝑈₆ = 𝐼₆ ∗ 𝑅_{𝑦𝑢𝑘6} = 2,6 ∗ 3000 = 7,8𝑉;

𝑈₃ = 𝐼₃ ∗ 𝑅_{𝑦𝑢𝑘3} = 13,1 ∗ 200 = 2,62𝑉; 𝑈₇ = 𝐼₇ ∗ 𝑅_{𝑦𝑢𝑘7} = 1,6 ∗ 5000 = 8𝑉;
𝑈₄ = 𝐼₄ ∗ 𝑅_{𝑦𝑢𝑘4} = 9.2 ∗ 500 = 4.6𝑉;
𝑷 = 𝑰^𝟐 ∗ 𝑹_𝒚𝒖𝒌; - yukdagi quvvatini hisoblash: (Wt)

𝑃₁ = 𝐼₁² ∗ 𝑅_{𝑦𝑢𝑘1} = 16.7² ∗ 50 = 0,0139 𝑃₅ = 𝐼₅² ∗ 𝑅_{𝑦𝑢𝑘5} = 6,1² ∗ 1000 = 0,0372

𝑃₂ = 𝐼₂² ∗ 𝑅_{𝑦𝑢𝑘2} = 15,3² ∗ 100 = 0,0234 𝑃₆= 𝐼₆² ∗ 𝑅_{𝑦𝑢𝑘6}= 2,6² ∗ 3000 = 0,0202

𝑃₃ = 𝐼₃² ∗ 𝑅_{𝑦𝑢𝑘3} = 13.1² ∗ 200 = 0,0343 𝑃₇= 𝐼₇² ∗ 𝑅_{𝑦𝑢𝑘7} = 1,6² ∗ 5000 = 0,0128

𝑃₄ = 𝐼₄² ∗ 𝑅_{𝑦𝑢𝑘4} = 9,2² ∗ 500 = 0,0423

- foydali ish koeffitsiеnti ini hisoblash:

Berilgan				Е1 =9.2 V; Rich =500 Ω.
Ryuk		Tajribadan olingan		Tajriba natijalarini hisoblash						Dastlabki hisoblashlar
		Uyuk		I		Pyuk		η		I		U		Pyuk		η
[Ω]		[V]		[mA]		[Wt]		-		[mA]		[V]		[Wt]		-
1	50		0,836		16.72		0.01397		0.09		16.7		0.8		0.0139		0.09
2	100		1,533		15.33		0.0235		0.16		15.3		1.53		0.0234		0.16
3	200		2,629		13.14		0.0345		0.28		13.1		2.62		0.0343		0.28
4	500		4,6		9.2		0.0423		0.5		9.2		4.6		0.0423		0.5
5	1000		6,133		6.13		0.0375		0.66		6.1		6.1		0.0372		0.66
6	3000		7,885		2.62		0.0205		0.85		2.6		7.8		0.0202		0.85
7	5000		8,363		1.67		0.0139		0.9		1.6		8		0.0128		0.9

2. Tajriba natijalarga ishlov berish:

Tajriba asosida olingan kuchlanish U_yuk qiymati asosida keying hisoblashlarni amalga oshiring. .

- yuklama tokini hisoblash:

𝑷_𝒚𝒖𝒌 = 𝑰_𝒚𝒖𝒌^𝟐 ∗ 𝑹_𝒚𝒖𝒌; - yukning quvvatini hisoblash:

𝑃_{𝑦𝑢𝑘1} = 𝐼_{𝑦𝑢𝑘1}² ∗ 𝑅_{𝑦𝑢𝑘1} = 16,72² 𝑚𝐴 ∗ 50 𝑂𝑚 = 0,01397 𝑊𝑡

𝑃_{𝑦𝑢𝑘2}= 𝐼_{𝑦𝑢𝑘2}² ∗ 𝑅_{𝑦𝑢𝑘2} = 15,33² 𝑚𝐴 ∗ 100 𝑂𝑚 = 0,0235 𝑊𝑡

𝑃_{𝑦𝑢𝑘3} = 𝐼_{𝑦𝑢𝑘3}² ∗ 𝑅_{𝑦𝑢𝑘3} = 13,14² 𝑚𝐴 ∗ 200 𝑂𝑚 = 0,0345 𝑊𝑡

𝑃_{𝑦𝑢𝑘4}= 𝐼_{𝑦𝑢𝑘4}² ∗ 𝑅_{𝑦𝑢𝑘4} = 9,2² 𝑚𝐴 ∗ 500 𝑂𝑚 = 0,04232 𝑊𝑡

𝑃_{𝑦𝑢𝑘5} = 𝐼_{𝑦𝑢𝑘5}² ∗ 𝑅_{𝑦𝑢𝑘5} = 6,13² 𝑚𝐴 ∗ 1000 𝑂𝑚 = 0,03757 𝑊𝑡

𝑃_{𝑦𝑢𝑘6} = 𝐼_{𝑦𝑢𝑘6}² ∗ 𝑅_{𝑦𝑢𝑘6} = 2,62² 𝑚𝐴 ∗ 3000 𝑂𝑚 = 0,02059 𝑊𝑡

𝑃_{𝑦𝑢𝑘7} = 𝐼_{𝑦𝑢𝑘7}² ∗ 𝑅_{𝑦𝑢𝑘7} = 1,67² 𝑚𝐴 ∗ 5000 𝑂𝑚 = 0,01394 𝑊𝑡


-FIK hisoblash , bunda 𝐏_{𝐦𝐚𝐧𝐛𝐚} = 𝐄 ∗ 𝐈_𝐲𝐮𝐤;






Hisoblash natijalarini 2-jadvalga kiriting.

3. Quyidagi bog’lanishlar grafiklarini chizing:

1) I_yuk = f (R_yuk); 2) U_yuk = f(R_yuk); 3)P_yuk = f (R_yuk); 4) = f (_Ryuk).

1) I_yuk = f (R_yuk);



2) U_yuk = f(R_yuk);

3 )P_yuk = f (R_yuk);

4) = f (_Ryuk).

XULOSA

Men xulosa qilib shuni ayta olamanki - ushbu labaratoriya ishidan o`zimga kerakli bilim va ko`niklamarni oldim.. NI Multisim dasturiy muhiti yordamida yordamida kuchlanish va tok manbasining tashqi tavsifini o’rganish tatbiq etdim. Labaratoriya ishi bajarish davomida kuchlanish va tok manbasining tatbiq etish uchun sxema va formulalardan foydalandim. Jadvalni kelib chiqqan natijalar bilan to’ldirdim.Va chiqan natijalar orqali Excel orqali grafiklar chizdim..Ushbu laboratoriyani bajarish davomida real mustaqil kuchlanish va uning ishlash prinsiplari to’g’risida to’liqroq ma’lumotlarga ega bo’ldim. Shuningdek, foydali ish koeffitsienti yuqori bo’lishi uchun manbaning ichki qarshiligi kichikroq bo’lishi kerak. Ichki qarshilik 0 bo’lganda biz uni ideal kuchlanish manbasi deya olamiz. Amalda esa buni iloji yo’q. Multisim dasturi orqali kerakli ishlar bajarilib jadvalga yozildi. Quvvat, tok kuchi va F.I.K ni o’rgandik. Ryuk ning ma’lum qiymatida Pyuk maksimal qiymatga erishadi. Fizika kursidan ma’lumki, Rich = R bo’lganda quvvat maksimumga erishadi. Grafik orqali buni ko’rishimiz mumkin. Men bu labaratoryani bajarganimdan juda mamnunman.

Xurmat bilan.

Xudoyberdiyev Shoxijaxon.