Introduction General part

Cutting tool calculation.

Ø32 mm couuntersinker diameter is equal to the hole diameter half-finished product material CCH35-10 hardness HB 180
The length of the hole to be machined is l = 40 mm
1. Assume that the diameter of the hole is equal to the diameter of the hole being machined. According to GOST12509-75 * we accept N1; D = 32-0,245mm
2. Constructive and geometric dimensions of the working part of the couuntersinker:
Back angle a = 10 °; calibration section angle 8 °; front angle g = 0 bevel width f = 0.3 mm; screw groove angle ō = 10 °; plate cutting angle ō1 = 10 °; assume the shape of the grooves to be parallel. Screw ditch step
H = pDctg 10 ° = 3.14 * 11 * 5.6713 = 195.84 mm
The angle in the main plan is ph = 60 °
The angle of the cutting edge of the plan is ph1 = 30 °. The length of the return conical plate is 0.05 mm
3. We accept the design dimensions of the couuntersinker in accordance with GOST 3231-71.
Workpiece length: L = Lk + 3D = 40 + 3 * 32 = 49 mm;
Here: Lk -hole length, mm
D- couuntersinker diameter, mm
The length of the couuntersinker part is found by the following formula
L = 0.04D + 2 = 0.04 * 32 + 2 = 3.28 mm
The length of the neck l = 10-12 mm, we accept the cone morse for the tail part in accordance with GOST25557-82.
4. We accept couuntersinker technical requirements from GOST 12509-75 *.
4. Dowel slot according to GOST9472-83: conical 1:45 diameter Ø32 mm, groove width b = 4,3H13 (+0,18) mm, depth t = 4,8H13 (+0,18) mm radius r = 0 , 6 mm, interference tolerance z = 0.075 mm.
5. When processing gray cast iron we accept VK6, form 2515 according to GOST 2209-82 or 21 according to GOST 25400-82, couuntersinker body material Steel 40X according to GOST 4543-71 *

4. 
   Control device calculation and design.
   

Since the part we are given belongs to the class of parts that rotate around its axis, and the main surface of the part is a cylinder, we control our part with the help of indicators. We install our detail in the center of the device through the center holes. In this case, the calculated magnitude of the error of the control device is as follows.
∆ =∆
Here:
∆ = 0.005 mm - linear dimensional error in the manufacture of fabrication nodes;
∆ = 0 systematic error of transmission devices;
∆ = 0 installation error;
∆ = 0 Uncertainty when setting the measuring base of the part being tested aligned with the working surface of the unit
∆ = 0.005 mm random error,
∆ = 0.001 mm Methodological error of measurement.
This results in a device error
∆ = 0.005 = 0.057 mm
The calculated value of the control error must meet the following requirement.
∆ <<∆ << T
T = 0.08 mm is the allowable deviation area controlled here

4. 
   Economic part.
   

The projected department is designed for detail processing and operates in 2 shifts. The operating stock of equipment in 2 shifts is F = 4029 hours, and the number of working days per year is 253 days. based on the application.
According to the calculations in the section, the section under consideration in our project belongs to the type of multi-series production, with an annual production capacity of N = 90,000 units, part weight m = 1.66 kg.