Nizоmiy nоmidаgi tоshkеnt dаvlаt pеdаgоgikа univеrsitеti termiz filiali

4. 37 - 20 ni hisoblash usulini toping	37 – 20 = (37 - 7) – 20 = (30 – 20) + 7 = -10 - 7 = 17;	37 – 20 = (30 + 7) – 20 = (30 – 20) + 7 = 10 + 7 = 17;	37 – 20 = (30 - 7) – 20 = (30 – 20) -7 = 10 + 7 = 17;
37 – 20 = (30 - 7) + 20 = (30 – 20) - 7 = -10 + 7 = 17;
5. 37 – 2 ni hisoblash usulini toping.	37 – 2 = (37 - 7) – 2 = 30 + (7 – 2) = -30 + 5 = 35;	37 – 2 = (30 + 7) – 2 = 30 + (7 – 2) = 30 + 5 = 35;	37 – 2 = (30 - 7) + 2 = 30 + (7 – 2) = -30 - 5 = 35;	37 – 2 = (30 + 7) – 2 = 30 - (7 – 2) = 30 - 5 = 35;
6. 25 + 17 ni hisoblash usulini toping.	25 + 17 = (22 + 3) + 17 = 22 + (3 + 17) = 22 + 20 = 42;	25 + 17 = (20 + 5) - (10 + 7) = (20 + 10) - (5 + 7) = 30 + 12 = 42;	25 + 17 = (20 + 5) + 10+7 = (20 + 17) - 5 = 37 + 5 = (37 + 3) + 2 = 42;	25 + 17 = 20+5 - (5 + 12) = (25 + 5) - 12 = 30 + 12 = 42;
42 - 5 ni hisoblash usulini toping	42 – 5 = 42 – 2 – 3 = (42 – 2) – 3 = 40 – 3 = 37;	42 – 5 = 40 + 2 – 3 = (42 + 2) – 3 = 44 – 3 = 37;	42 – 5 = 40 – 2 + 3 = (42 – 2) + 3 = 40 + 3 = 37;	42 – 5 = 40 – 2 – 3 = (42 – 2) – 3 = - 40 – 3 = 37;
38 + 5 ni hisoblash usulini toping.	38 + 5 = 38 - 2 - 3 = (38 + 2) - 2+1 = 40 + 1 = 43;	38 + 5 = 38 + 2 + 3 = (38 + 2) + 3 = 40 + 3 = 43	38 + 5 = 40 - 2 + 3 = (38 - 2) - 3 = 36 + 3 = 43;	38 + 5 = 38 + 2 + 3 = (38 - 2) - 3 = - 40 - 3 = 43;
30 - 7 ni hisoblash usulini toping.	30 – 7 = (30 - 10) – 7 = 20 + (10 + 7) = -20 - 13 = -33;	30 – 7 = (20 + 10) – 7 = 20 + (10 – 7) = 20 + 3 = 23;	30 – 7 = - (20 + 10) – 7 = -20 - (10 – 7) = -20 - 3 = -23;	30 – 7 = (20 + 10) + 7 = 20 - (10 – 7) = 20 - 3 = 13;
23 + 34 ni hisoblash usulini toping.	23 + 34 = 26 - 3 + 38 - 4 = 20 - 30 - 3 - 4 = (20 - 30) -(3 - 4) = 57;	23 + 34 = -20 - 3 - 30 - 4 = -20 - 30 + 3 + 4 = (20 + 30) -(3 + 4) = - 57;	23 + 34 = 20 + 3 + 30 + 4 = 20 + 30 + 3 + 4 = (20 + 30) +(3 + 4) = 57;	23 + 34 = 20 + 3 + 30 + 4 =- 20 - 30 – (3 + 4) = - (20 + 30) - (3 + 4) = -57;

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   1^ Дмитриева О.И. Поурочные разработки по математике к учебному комплекту 4–класс. – М.: Вако 2007. 2–изд. с.220