Фарғона туманидаги

Reaksiya unumi

1. KOH--->KHCO3---->K2CO3--->KCl reaksiya unumlari mos ravishda ketma-ketlikda 75%, 80%, 50% bo'lsa va KCl massasi reaksiya uchun olingan KOH massasidan 33,65 g ga kam bo'lsa nordon tuz massasini gr toping.

A)75 B)120 C)80 D)100

Yechimi:
KCl Mr 74,5 g/mol

KCl(m) 74,5×0,5×0,8×0,75=22,35 g
KOH Mr=56 g/mol

56-22,35=33,65 g ga kamaydi

33,65 g kam------100 g KHCO3

33,65 g kam-------x=100 g

J: D

2. Bertole tuzini katalizator ishtirokida qizdirilganda hosil bo’lgan aralashmadagi xlorning massa ulushi 36% ni tashkil etsa, kaliy xloratning parchalanish darajasini (%) aniqlang.
Yechimi:
71 + 71x
0,36=------------------
245+149x
x= 1 mol
2 mol -------- 100%
1 mol --------- y= 50%
J: 50%

3. NO2 ning parchalanish unumi (%) hosil bo'lgan gazlarning molyar massasiga teng bulsa, parchalanish unumini (%) hisoblang

Yechimi:
1 mol NO2

2NO2-->2NO+O2
x. x. 0,5x
x. 46
---•100=--------------
1. 1-x+1,5x
x=0,385

Yana bir yechim:

NO2=NO+0,5O2
x. x. 0,5x

(30x+16x)+(46-46x). 46x•100

--------------------------------=------------
. (1-x)+x+0,5x. 46

x=0,385

J: 35,8%

4. 5 tonna CaCO3 dan 80% unum bilan X tonna pretsipitat olindi. Olingan o'g'it tarkibidagi ozuqa elementi miqdorini (t) toping. A) 3,55 B)4,26 C)3,9 D)2,84

Yechimi:
CaCO3+H3PO4=CaHPO4+H2O+CO2

100g------------------1 mol CaHPO4

5 000 kg-----------------x=50 kg/mol

2CaHPO4=P2O5

2 mol---------------142 g
50 kg/mol-------x=3,55 tonna

3,55×0,8=2,84 tonna

J: D

5. Is gazi va suv bug’i orasidagi qaytar reaksiya temir (III)-oksid katalizatori ishtirokida boradi. Dastlabki aralashmaning mol nisbati mos ravishda 1:1 bo’lganda reaksiyaning unumi y ga teng, 2:1 bo’lganda esa 25 % ga ortadi. y ni toping?

A) 0,4 B) 0,65 C) 0,7 D) 0,8

Bio-Cemistry, [03.01.18 15:57]

[Forwarded from Asqarjon Otaqulov]
Y^2 (1.25y)^2
----------=--------------------=>
(1-y)(1-y) (2-1.25y)(1-1.25y)

Y^2 1.5625y^2

----------=------------------------------
1-2y+y^2 2-3.75y+1.5625y^2

1.5625y^2-3.125y^3+1.5625y^4= 2y^2-3.75y^3+1.5625y^4

0.625y^3=0.4375y^2

0.625y=0.4375
Y=0.7

6.