Biologiya Umumlashtirish darsi

Yechimi
30 % S --------- G 30 %
20 % A -------- T 20 %
A + T = G + 18
0,2x + 0,2x = 0,3x + 18
0,1x = 18
x = 180. DNK tarkibidagi nukleotidlar soni
180 x 0,2 = 36 ta A DNK qo`sh zanjirida
36 / 2 = 18 ta A DNK bitta zanjirida (a)
DNK 2-zanjiridagi T soni ham 18 ta (b)
Javob: B

13. 4ta nomalum nukleotidli DNK molekulalarining biridan su`niy sharoitda 99 ta peptid bog`li oqsil molekulasi sintezlandi. Barcha DNK molekulasidagi nukleotidlar oqsil biosinteziga javob bo`lgan DNK molekulasidan 4,3 marta ko`p. 2-DNK nukleotidi 1-DNK nukleotidlaridan 1,2 marta, 3-DNK dan 0,8 marta, 4-DNK nukleotidlaridan 2 marta katta bo`lsa, transkripsiya ishtrok etgan DNK molekulasini aniqlang.

13. 4ta nomalum nukleotidli DNK molekulalarining biridan su`niy sharoitda 99 ta peptid bog`li oqsil molekulasi sintezlandi. Barcha DNK molekulasidagi nukleotidlar oqsil biosinteziga javob bo`lgan DNK molekulasidan 4,3 marta ko`p. 2-DNK nukleotidi 1-DNK nukleotidlaridan 1,2 marta, 3-DNK dan 0,8 marta, 4-DNK nukleotidlaridan 2 marta katta bo`lsa, transkripsiya ishtrok etgan DNK molekulasini aniqlang.

A)1-DNK B)2-DNK

C)3-DNK D)4-DNK

DNK ga oid murakkab masalalarni ishlash usullari
Yechimi
99 + 1 = 100 ta aminokislota
100 x 6 = 600 ta nukleotid DNK da
600 x 4,3 = 2580 ta nukleotid barcha DNK da
1-DNK – x
2-DNK – 1,2 / 1 = 1,2x
2-DNK – 1,2/ 0,8 = 1,5x
4-DNK – 1,2 / 2 = 0,6x
x + 1,2x + 1,5x + 0,6x = 2580
x = 600. Bu 1-DNK dagi nukleotidlar
Javob: A

14. 3 xil nomalum nukleotidli DNK molekulasi mavjud bo`lsa. Ulardan oqsil sintezlanishi uchun jami 420 ta t-RNK sarflangan. 2-DNK malekulasidan oqsil sintezlanishi uchun sarflangan t-RNKlar soni 1-DNKdan oqsil sintezlanishi uchun sarflangan t-RNKlar sonidan 0.75 marta kam, 3-DNKdan oqsil sintezlanishi uchun sarf bo`lgan t-RNKlar sonidan 0.8 marta ko`p bo`lsa, 3-DNKdagi peptid bog`lar sonini aniqlang.