§. Harakatning xususiy hollari

**Masala 3².

12-19a rasmda tekislikda qisqa vaqt ichidagi masofa y = (0.00lx2)m ko’rsatilgan. Doimiy tezlik 10 m\s, ga oshib borsa masofadagi tezlik va tezlanish qiymatlarini aniqlang bunda y = 100 m.
Yechish:
Bu yerda y = 100 m., u xolda 100 = 0.001x2 yoki x = 316.2 m.Bundan tashqari boshlang’ich tezligi Vy = 10 m\s, bunda

Tezlik. Quyidagicha aniqlanadi
(1)

(a) (b)
rasm.12-19
Bu yerda

Tezlikning natijalovchi qiymati

Tezlanish.. Quyidagicha aniqlanadi

Bunda

Tezlanishning natijalovchi qiymati
Javob:
Bu qiymatlar rasm. 12-19b.da ko’rsatilgan. [kamol]

1^ **3. R. K. HIBBELER. ENGINEERING MECHANIKS. STATIKS. DYNAMIKS. TWELFTH EDITION . © 2010 by R.K. Hibbeler Published by Pearson Prentike Hall Pearson Edukation, Ink.Upper Saddle River, New Jersey 07458E ISBN -10: 0-13-607791-9, ISBN -13:-978-0-136077916. Printed in the United States of Amerik (str.10).

2^ **3. R. K. HIBBELER. ENGINEERING MECHANIKS. STATIKS.DYNAMIKS. TWELFTH EDITION . © 2010 by R.K. Hibbeler Published by Pearson Prentike Hall Pearson Edukation, Ink.Upper Saddle River, New Jersey 07458E ISBN -10: 0-13-607791-9, ISBN -13:-978-0-136077916. Printed in the United States of Amerik (str.38).