++,- binar amallari Inkrement dikrement

++,-- binar amallari

Inkrement dikrement

&,|,^ - razyrad amallari

package javaapplication4;

public class JavaApplication4 {

public static void main(String[] args) {

Scanner Behzod=new Scanner(System.in);

//int a,b,c,d,m;

/*System.out.println("to'rt xonali son a=");

a=.nextInt();

b=a%10;

c=(a%100)%10;

d=(a%1000)%100;

m=a/1000;

System.out.println("m+c="+(m+c));

System.out.println("b+d"+(b+d));*/

//qoldig`ini topish uchun ishlatiladi//

/* System.out.println("a=");

c=a&b ; System.out.println("va c="+c);

c=a|b; System.out.println("yoki c="+c);

c=a^b; System.out.println("xor c="+c);*/ // HISOBLAYDI

/*

System.out.println("a="); a=Behzod.nextInt();

b=a>>2;

System.out.println("b="+b);

bu chapga surarkan*/

// c=a<<2 bu orqasidan yana 2 ta nol qo'shadi ya'ni son 13 bo'lsa 2likda 1101 ni orqasidan yana

//2 ta nol qo'shadi keyingi son esa 110100 bo'ladi bu esa 10likda 52 degani zz

int a,b,c,d,m=4;

System.out.println("a="); a=Behzod.nextInt();

m+=a;

System.out.println("m="+m);

m+=a degani m=m+a degani bilan bir xil;

d=a++ => birga oshirish degani;

a++ <=> a=a+1

d=++a=> oldindan birni qo'shadi;

++a <=> oldindan 1 ni qo'shadi

sonni o'rinlarini almashtirish

b=a%10;

c=(a%100)%10;

d=a/100;

1-usul: m=d*100+b*10+c;

2-usul: (""+d+b+c);

boolean z;

z=(a>=16); son kiritamiz va shu son 16dan kichik bo'lsa unda z rost chiqadi

a=[4;16];

agar bunday bo'lsa z=(a>=4 && a<=16);

bu degani shu oraliqdagi sonlarni kiritsa bo'ladi

40 ta masalani yechish kkcekan shularni ko’rib bilganimizni ko’rish kk ekn

}

}