The amount of exhaust gases (V1) 70m3 / sec



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Task №1.

Near the village of "A" in Andijan planned to place a factory for the production of dyes, air emissions, which have the following characteristics:

- The amount of exhaust gases (V1) - 70m3 / sec;

- Amount of phenol therein (Mfen) - 6gr / sec;

- The amount of sulfur dioxide (M SO4) - 10 g / sec.

 Parameter taking into account the conditions of the gas outlet pipe (f) - 0.4 m / s * hail.

- Height of the output (H) - 100m;

- The difference in temperature exhaust gases and ambient air (delta T) - 170c.

 Give an opinion on the possibility of placing the factory in the selected area.

It is necessary to take into account that according to sannadzora background concentration of sulfur dioxide in the village of "A" is determined periodically at the level of 0.1 mg / m3.

Decision.

 1. To address the issue of the possibility of building a factory on the selected area, you must use predictive calculations to determine what concentration of contaminants will be in a / in existing residential areas.

  To this end, in accordance with the CH-369-74 first define the maximum concentration (cm) contamination in the surface layer A / B at the point of landing flare according to the formula:

  Cm = A * M * F * m * n * G

a) m - find the schedule at f = 0,4 «m» = 1.0 on schedule

b) to find the «n» on the schedule you need to know vM.

 VM find the nomogram for H = 100 m, and the product

   V T - 70 * 170 = 11900 (1.2 * 10 ^ 4)

VM nomogram is 3.5

c) at Vm = 3,5 * n (schedule) = 1.

g) G is found from the nomogram. If the value is:

 

   V T = 1.2 * 10 ^ 4 and N = 100 G = 4 * 10 ^ -6



Substituting the values ​​according to the formula, we get

See phenol = 200 * 6 * 1 * 1 * 1 * 4 * 10 ^ -6 = 0.0048 mg / m3

 Similarly, we define the maximum concentration of sulfur dioxide

See SO2 = 200 * 10 * 1 * 1 * 1 * 4 * 10 ^ -6 = 0,008mg / m3

2. Since phenol and sulfur dioxide have a summation of action in accordance with the formula (2) CH-369-74 determine the total concentration of pollution at the point of landing of phenol:

0.0048 / 0.01 + 0.008 / 0.5 = 0.496 less than 1

The total concentration does not exceed the maximum permissible concentration (1.0).

3. Determine the distance from the source of release to touchdown phenol (Hm) according to the formula:

Hm = H * d

d find on schedule at Vm = 3.5 and f = 0,4 d = 17 then

  Um = 100 * 17 = 1700 m

Consequently, at a distance of 1700 m from the factory total concentration of phenol and sulfur dioxide will not exceed the MPC. The actual distance to the village "A" 2125m, to the village of "M" - 2000m and to the village of "C" - 2250m.

All these distances concentration in the surface layer is less than the landing point of phenol, i.e. less than See.

In the presence of background concentrations in the village of "A" total concentration of contaminants does not exceed the MPC.

0.0048 / 0.01 + (0.008 + 0.1) / 0.5 = 0.696, ie, lower than the MPC (1.0).

Wind rose playground factory is beneficial to all villages.

Conclusion. Placing factories dyes selected site is possible because According to our calculations the total contamination and / in phenol and sulfur dioxide at the point of landing flare and surrounding villages will not exceed the permissible limits.

 Task number 2.

In the area of ​​"k" in the Samarkand region is planned construction of CHP in emissions which, after cleaning in electrostatic contain:

Mpyli = 332g / sec;

NO2 = 561 g / sec;

MO2 = 1173g / sec.

The volume of exhaust gases V1 = 980 m3 / sec.

 Gas temperature T2 = 150C, t - the ambient air, the hottest month TB = 25 ° C, the release height H = 250m, f- option takes into account the conditions of the gas outlet tube f = 0,6.

 Give an opinion on the possibilities and conditions of the construction of the CHP on the planned site.

Decision.

1. Determine the maximum surface concentration of contaminants by the formula:

Cm = A * M * F * m * n * V

To do this first:

   1) we find «m» schedule f = 0,6; «M» -1,2

   2) «V» - the nomogram

When making V1 to T = 980 * 125 = 1.2 * 10 ^ -4

H = 240m «V» -10 ^ -7

   3) To find the «n» first define «V».

When V1 T = 1.2 * 10 ^ 4 and H = 240m and «V» -2,4, then «n» = 1.

   4) «F» dust - 2 to NO2, SO4 - 1.

"A" = 200 Siberia

See Dust = 200 * 7 * 322 * 2 * 11 * 7 * 10 ^ 7 = 0.0929 mg / m3

SmNO2 = 200 * 560 * 11 * 1 * 7 * 10 ^ -7 = 0,785mg / m3

SmSO2 = 200 * 1173 * 1 * 1 * 1 * 7 * 10 ^ -7 = 0,164mg / m3

2. These are the maximum concentrations at the point of landing flare at a distance (Hm) from the emission source. Hmm distance determined by the formula

              Hm = H * d

When V = 2,7 and f = 0,6

Um = 240 * 14 = 3360m

At this distance, the dust See below the published limits, and the total dimensionless concentration of sulfur dioxide and nitrogen oxides, with the effect of summation - above the permissible limits

0.164 / 0.5 + 0.0785 / 0.085 = 1.25

According to the situation plan, the nearest residential area of ​​the city is located at a distance of 4-5km, rest area of ​​the city - at a distance of 6 km and villages "C" and "P." practically next door.

   Total dimensionless concentration of sulfur dioxide and nitrogen oxides is at a distance of 5 km:

X / XM = 5000/3360 = 1.48 in this case S1 = 0,9

C500 = 1,25 0,9 <1,125, ie more MAC (1.0)

At a distance of 6 km, in a recreation area

6000/3360 = 1.78 wherein S1 = 0,85

C600 = 1,25 0,85 <1,06 which is also more than MPC equal to 0.8 recreation area.

Conclusion. Construction of the planned CHP selected area is not possible, because According to our calculations, the total contamination and / in a residential and recreation area in the city of sulfur dioxide and nitrogen oxides will exceed the allowable level exceed the permissible level.

Task №1.

On the attached location plan applied area planned for construction of a pharmaceutical plant for the production of synthetic drugs.

 According to calculations made by the institute "Gidromedrom" according to the CH-369-74, the maximum total dimensionless concentration of sulfur dioxide, ammonia and phenol will be 1.3 and will be determined at a distance of 1.5 km. Define the required boundaries of the SPZ, give it a graphic representation and the conclusion of the terms of the construction of HAP on the selected site.

  Task №2.

At a distance of 3 km north-east of the village of "K" Fergana region sinter plant to be built. To clean the air emissions are plans to establish multicyclones.

 Assess the adequacy of the planned treatment if:

-ostatochnoe amount of suspended substances in emissions (m) - 600g / sec;

-sernistogo gas (MSO4) - 800g / sec;

is the volume of exhaust gases (f) - 50m3 / s;

parameter that takes into account the conditions of the gas outlet pipe (f) - 0.8 m / s2 * hail.

Difference t exhaust gases and the surrounding air (T) - 160grad. The height of the output (H) - 100m.

Problem №1

On the attached the copy of the master plan of the district number 20 suffered a kindergarten for 140 places, which is proposed to be built instead of the projected residential building.

Determine the adequacy of insolation areas kindergarten during walking children, which under the regime of the day is done 10 to 11 hours.

Give conclusion about the possibility of placement scheduled kindergarten.

Problem №2

With insolyatsionnoy line define that in view of the shadow angle insolation premises, located on the facade, oriented to the northeast, is no more than one hour.

According to the plan of a typical floor of an apartment house all the living rooms of 2-room apartments is focused on the facade.

As a result, 2-bedroom apartments will not have the necessary 3 -x hour insolation.

Case study №1

Orientation four - room apartment south and south-east, living room voucher from 1-1.5. Insolation premises up to 3 hours. The ratio of main and auxiliary facilities 60% - 40%. The room have through ventilation and angular. Light ratio 1: 4.5; 1: 5.5.

Solution


1. Planning activities in the apartment Regulatory Compliance SanPin 0004-94.

2. Orientation of the apartment is correct.

3. KEO meets the hygiene requirements, the ratio of main and auxiliary facilities are normal.

Problem №2

Orientation 3-room apartment south. KEO in the living room of 0.3%. Insolyauiya premises to 1.5 hours. The ratio of main and auxiliary facilities of 30-70%. The room has a corner airing. Illuminated ratio of 1: 6, 1: 5.5.

Rate planning events around the apartment.

 Solution

1.Orientatsiya apartments correct, it corresponds to SNIP 01.07.-03

"Gradostroiteltvo"

2. KEO does not meet hygiene requirements

3. The ratio of main and auxiliary facilities normally

Case study: № 1.

When designing a new settlement "Dashtobod" allocated 15 hectares of land. The site is located 1 km from the centers of breeding of malaria mosquitoes. The plan of the village consists of 5 elements: residential area, industrial area. municipal warehouse zone, external transport and green area. The gap between residential and industrial zone of 500 m. The production area is located on the leeward side of the housing lower terrain and downstream open reservoirs. In the industrial zone is planned construction of machine building plant, which is equipped with electrostatic precipitators

Evaluate the accuracy of the new layout of the village.

Decision.

Land with an area of ​​15 hectares allotted properly, the general plan of the village meets the hygienic requirements. Location of the plant site in relation to residential correctly. The site should be located 3 km from the centers of breeding of malaria mosquitoes. SPZ meets the hygiene requirements SanPin 0006 - 93 as Machine-Building Plant refers to class 4 and is equipped with electrostatic precipitators.

Case study number 2.

When designing a new settlement "Ziff" allocated 12 hectares of land. The site is located 500 m from the centers of breeding of malaria mosquitoes. The plan of the village consists of 4 elements: residential zone, industrial zone, external transport and green area. The gap between residential and industrial zone of 100 m. The production area is located on the windward side of the home. In the production area is planned construction of the plant with the steel industry cycle capacity of more than 1 million. M. / Year of iron and steel.

Evaluate the accuracy of the new layout of the village.

Solution:

Land with an area of ​​12 hectares allotted properly, the plan of the village does not meet the hygienic requirements as no communal storage area and landscape and recreation area. Location of the plant site in relation to residential wrong. The site should be located 3 km from the centers of breeding of malaria mosquitoes. SPZ does not meet hygienic requirements on SanPiN 0006 - 96 as Steel mill with a cycle capacity of more than 1 million. m. / year of iron and steel refers to the first class and the SPZ to be 1000 m. The project also lacks a sewage treatment plant.

Case studies: № 1.

When designing a new settlement "Quruvchi" allocated 20 hectares of land. The site is located 1,500 meters from the centers of breeding of malaria mosquitoes. The plan of the village consists of 4 elements: residential zone, industrial zone, external transport and resort area. The gap between residential and industrial area of ​​1000 m. The production area is located on the windward side of the home. In the production area is planned construction works for the extraction of ores of mercury arsenic margantsa.Po project not pedusmotrena treatment sooruzheniya.SZ0Z 500m.

Rate the correct layout of the new settlements

Situational problem number 2.

When designing a new settlement "Pakhtachi" allocated 2 hectares land. The site is located 250 m from the centers of breeding of malaria mosquitoes. The plan of the village consists of 4 elements: residential zone, industrial zone, external transport and obshestvennyh center. The gap between residential and industrial zone of 700 m. The production area is located on the windward side of the home. In the production area is planned to construct 5 fabriki.Po sewing project all the factories equipped treatment plant that is cyclone with an efficiency of 50 percent of the work.

Rate the correct layout of the new village

Problem №1

Olmaliq coal in coal-fired furnaces with solid slag removal with angled burner CHP consumes 100 tons of coal per hour.

0 ash content of 32%, a sulfur content of 24.7%, volatile 40% calorie - 4643 kcal. The power plant is equipped with treatment facilities type - B-B - 250.

Define

1. Daily ash ash and unburned carbon



2. Proper selection of the treatment plant.

Problem №2

Be determined by the ash and sulfur content, if the boiler is translated with Olmaliq coal moschnstyu 100 tons of coal per hour, with an ash content of 32% sulfur content - 4.7%, volatile substances - 40%, 4643 kcal calorie coal.

Case study №1

In the city of "H" in the industrial zone located CHP. Based on these analyzes, air received on a stationary post in October 2008 (Table №1) make "rose gassed" to assess the condition of air in "H"

Solution


On the basis of stationary post in October 2008 revealed

exceeding the maximum permissible concentration of sulfur dioxide at the south-west wind. A possible source of air pollution is the CHP located at a distance of 500 meters to the south-west of the city.

Necessary to carry out sanitary inspection of CHP to determine the cause of exceeding allowable emissions of sulfur dioxide in October 2008 and to make recommendations for their elimination

Case study №2

During commissioning of the new processing plant nonferrous metals found that all the technological workshops are equipped pollution control scrubbers, the reception of which is carried out in 2 stages. This hygienic assessment is based aggregation node and technological lines.

At the end of Phase 1 inspection is made the act of pre-acceptance facilities. During the trial examination conducted technical tests built gas treatment plants, and for monitoring the effectiveness of the facilities participating factory laboratory. Give your opinion



Solution of the problem.

To monitor the effectiveness of treatment facilities in addition to the plant laboratory must participate laboratory CSES. Whose task is to determine the concentration of certain substances released into the atmosphere enterprises and the degree of dispersion of harmful emissions in the surface layer

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