= co s4 + sin 4xagar sin2;c = bo’lsa
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Matem X 2019 @dtm axborotnoma
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- 2 1 . 3 — 4 s in 2* , ifodani ko’paytma ko’rinishiga
- 2 3 . 4 cos 2 x - 1, ifodani k o’paytma ko’rinishiga keltiring.
- 2 4 . 2 sin x 2x — 1 , ifodani ko’paytma ko’rinishiga
- 2 9 . № + « S y = * bo’l s a , c o s t , - , ) =
- 3 0 . [> « * + * » ’ = + bo’ l s a , c o s (x — y ) =
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1. tg4x = — - bo’lsa, ctgx -
tgx - 2tg2x ni
toping A) - 8 B ) - 5 C) - 6 D) - 7
2 . = — - bo’lsa, ctgx - tgx: - 2tg 2 x ni toping A) - 1 2 B) - 5 C) - 6 D) - 7 3. tg 4x = — - bo’lsa, ctgx - tgx -
2tg2x ni
toping A) - 6 B ) - 5 C) - 8 D) - 7 4.
ctg4x = - i bo’lsa, ctgx — tg x — 2tg2x ni
toping A) - 2 B ) - 5 C) - 8 D) - 7 5.
= — - bo’lsa, ctgx - tg x - 2tg2x ni
toping A) - 1 0 B) - 5 C) - 8 D) - 7
6- f i x ) = co s4* + sin 4xagar sin2;c = ^ bo’lsa. fix') ni toping? A) ^ B) - 5 C) - 8 D) - 7 7.
ctglQ + 4cos7Q ni hisoblang? A) V3 B ) - 5 C) - 8
D) - 7 8.
cos3 + cos{7r} ni hisoblang? A) 0 B) - 5 * C) - 8
D) - 7
9. sin3 — sin{7r} ni hisoblang? A) 0 B) - 5 C) - 8 D) - 7 10.
Agar sinx + cosx = - bo’lsa, tg | ni toping? A) - | ; 2 B) - 5 C) - 8 D) - 7
11. il^rJsiny 'W aning eng kichik qiymatini toping? A) - 1 B) - 5 C) - 8 D) - 7 12.
Hisoblang tg 9 + tg 15 — tg 2 7 — ctg 27 + $tg 15 + ctg 9 A) 8 B) - 5 C) - 8 D)
- 7 13.
/ (x) = 3cosx — 4sinx + 3 qiymatlar soxasini toping ?
A) [ - 2 ; 8] B) - 5 C) - 8 D) - 7
14. Hisoblang cos 20 + 2 sin 255 - V Isin 65 ? A l l B) - 5 C)
- 8 D) - 7
15. Hisoblang — 4sin 70 ?
A) 2 B) - 5 C) —8 D) —7 16.
Hisoblang J i - i J ~ + ^ cosx n < x < 2 n B ) - 5 C ) - 8 D ) - 7
A) c o s - 17.
Hisoblang J ^ + ^ J^ + ^ cos2x ^ - < x <
A) - c o s | B )—5
0 - 8 D ) - 7
18. / (*) = - j= ~ bo’lsa, f i t g x ) = ?
A )f(tg x ) - sinxtgx B ) - 5 0 ~ 8 D )- 7
19. f i x ) = y = f bo’ls a , f i c t g x ) = ?
A )fic t g x ) = cosxctgx
B ) - 5 Q - 8 D )- 7
20. Soddalashtiring x ,y e ( ^ ; 2я)
+ y) - tgx - tgy
A)
B ) - 5 C ) - 8 ,D )-7
A) 4co s(3 0 +
cos(30 — x ),4 s in ( 6 0 + x)sin(60 — x) B ) - 5 0 - 8 D )-7
22. 4
- 1 ? A) 4sin (x - 30)sin (x + 30) B ) - 5 C )- 8
D)—7 2 3 . 4 cos 2 x - 1, ifodani k o’paytma ko’rinishiga
A) 4sin (60 - x )sin (60 +
B )—5 C )- 8 D)—7
2 4 . 2 sin x 2x
A) - 2 s m ( 4 5 - x )sin (45 + x)
B ) - 5 0 - 8 D ) - 7
25. Hisoblang cos22 + 2sin256 - V2sin67 A) 1 B ) - 5 0 - 8 D ) - 7 26.
Hisoblang cos24 + 2st'n257 - V2sin69 A) 1
B ) - 5 0 - 8 D )- 7 27. cos26 + 2sin 258 — V 2sin71 A) 1 B ) - 5 0 - 8 D)—7 28.
cos28 + 2sin259 — V 2sin73 = ? A) 1
B ) - 5 0 - 8 D ) - 7 2 9 . № + « S y = * bo’l s a , c o s t , - , ) = ? [sinycosx = 0.2 > \ s j A) 0.6
B ) - 5 0 - 8 D )- 7 3 0 . [> « * + * » ’ = + bo’ l s a , c o s (x — y ) = ? (.sinycosx = 0.2 ’ 4
B )—5 0 - 8 D)—7 31
b o 'lsa, cos(x — y) =? (. sin ycosx = 0.2 4 A) -0.6 B ) - 5 0 - 8
D )- 7 32.
( tgx +
ctg y = 3
isinycosx = -
0.2
bo’lsa, c o s ( x - y ) = ? A ) -0.6 B ) - 5 0 - 8 D ) - 7
33. \t9X + Ct9y = l
bo’lsa, соs ( * - y ) = ? isin ycosx = 0.2 ’ v
B ) - 5 0 - 8
D )- 7 34.
Agar sin ^ — x j =
bo’lsa sin2x ni toping ? A) 0.25 B ) - 5 0 - 8 D ) - 7
35. Agar sin - x ) = i bo’lsa
ni toping ? A) 0.5 B ) - 5 0 - 8
D)—7 36.
Agar sin ( “ — * ) = bo’lsa
sin2x ni toping ? A) 0.75 B )—5
0 - 8 D )- 7
37. Agar cos — x ) = bo’lsa
sin2x ni toping A ) -0.25 B ) - 5 0 - 8 D )-7 38.
Agar cos — x ) = bo’lsa
ni toping A ) -0.75 B ) - 5 0 - 8 D )-7 39.
tgx = — 4 bo’lsa . 3cos2x
2 nj toping ?
2 - 9 c o s 2x s r A ) -3.16 B ) - 5 0 - 8 D )-7 40.
= - 4 bo’ls a , ~ — 2x ni toping ? А ) -3,24 В )—5 С )—8 D)—7
41. tgx = —2 bo’lsa , lcos2x l nj toping ? a
1 - 3 c o s 2x r b A) -5.5 B ) - 5 C ) - 8 D ) - 7
42. Yig’indini hisoblang tg3Q + tg 23 0 + tg 33 0 +
= ? a
— 2 43.
Yig’indini hisoblang c tg 60 + c tq 260 + ct^ 360 + ■■■ = ? A ) ^
B ) - 5 Q - 8 D ) - 7
44. A )_0
45. B ) - 5 0 - 8 D ) - 7
Yig’indini hisoblang tg60 + t^ 260 + tg 3 60 + . . . = ? B ) - 5 0 - 8 D)—7
Yig’indini hisoblang ctg30 + c tg 2 30 +
ctg 3 30 -I— = ? AM B ) - 5 0 - 8 D)—7
46. /(x) = 7 x2 — 4x
+ 5 bo’ls a , / (co sx ) = ? A ll 2 — 4cosx — 7
B )—5 C)—8 D ) - 7
47. / (x) = 7 x 2 — 4x - 5 bo’lsa , / (co sx ) = ? A) 2 — 4cosx — 7
B )—5 Q —8 48.
/ (x) = 7 x 2 + 4 x + 5 bo’ls a , / (co sx ) = ? A 112 + 4cosx — 7sin2x
B )—5 Q - 8 D)—7
49. / (x) = 7jc2 + 4 x — 5 bo’ls a , / (co sx) = ? A)2 + 4cosx — 7
B )—5 Q —8 50.
/ (x) = 7 x 2 — x — 5 bo’ls a , / (co sx ) = ? A1 2 — cosx — 7sin2x
B ) - 5 Q - 8 \ y -
" (y = cosx ega?
B ) - 5 Г у = 2 x 3 1^ =
ega? B ) - 5 Q - 8
D)—7 = 3 x 3 у — cosx
ega? B ) - 5 Q - 8
D)—7 - 2 x 3 , у =
ega? B ) - 5 Q - 8
D )—7 Juft sondagi hadlardan tashkil topgan arifmetik progressiyaning ayirmasi 3 ga teng.Toq nomerli va juft nomerli hadlar yig’indisi mos ravishda 12 va 24 ga teng. Uning barcha hadlari nechta ? B ) - 5 Q - 8 D ) - 7
Juft sondagi hadlardan tashkil topgan arifmetik progressiyaning ayirmasi 3 ga teng.Toq nomerli va juft nomerli hadlar yig’indisi mos ravishda 14 va 26 ga teng. Uning barcha hadlari nechta ? B ) - 5 Q - 8
D ) - 7 Arifmetik progressiyaning o’ninchi hadi 7 , yettinchi hadi 10 ga teng. 20-hadini toping? B ) - 5 Q - 8 D ) - 7
Arifmetik progressiyaning o’ninchi hadi 7 , yettinchi hadi 10 ga teng. 1-hadini toping? 51. A)1
52. A)1
53. A)1
54. A)1
55. A}
8 56.
A) 8 57. A}-3 58.
ly = <
ega? B)- r - 1У = tenglamalar sistemasi nechta yechimga Q - 8
D)—7
_ tenglamalar sistemasi nechta yechimga . tenglamalar sistemasi nechta yechimga tenglamalar sistemasi nechta yechimga A116 B ) - 5 Q - 8
D ) - 7
59. Arifmetik progressiyaning o’ninchi hadi 7 , yettinchi hadi 10 ga teng. 2 -hadini toping? A}15 B ) - 5 Q - 8 D ) - 7
60. Arifmetik progressiyaning o’ninchi hadi 7 , yettinchi hadi 10 ga teng. 3-hadini toping? A)14 B ) - 5 C ) - 8
D ) - 7
61. Arifmetik progressiyada a 3 + a 7 + a
10 +
ax2 +
ais + a 19 = 81 bo’lsa a s + a 17 =?
A)27 B ) - 5 Q - 8 D ) - 7
62. Arifmetik progressiyada ( a 2 + a X7
4 ^o’lsa dastlabki 20-ta hadini yig’indisini (a 19 - a 17 = 5
3 ° toping?
A}90 B )—5 Q - 8 D ) - 7
63. a x, a 2, a 3, ... bx, b2, b3, ... arifmetik progressiya hadlari uchun
—
bx = 3 a
4 =
b5 =£■ 3
B ) - 5 Q - 8
D)—7
a2-ai AlJ
64. Cheksiz kamayuvchi geometric progressiyaning barcha hadlari yig’indisi / (x) = x 3 + 3x — 9 Funksiyaning [-2;3] kesmadagi eng katta qiymatiga va bx — b2 = / '(0) ga teng bo’lsa, cheksiz kamayuvchi geometric progressiyaning maxrajini toping?
A ) j B ) - 5 Q - 8
D )-7 65.
Arifmetik progressiya uchun a x = 2.5
bx — 7.5
va a 100 + baoo = 10 a x + bx, a 2 +
b2, ... , a n + bn ketma-ketlikning dastlabki 100 ta hadi yig’indisini toping? AjlOOO B ) - 5 Q - 8 D)—7 66.
Arifmetik progressiya uchun a x = 2.5
bx = 7.5
va a xoo +
bx oo = 10
a x + bx,a 2 + b2, ... , a n + bn ketma-ketlikning dastlabki 10 ta hadi yig’indisini toping? A)100 B)—5 0 - 8 D )- 7
67. Arifmetik progressiya uchun a x = 2.5
bx - 7.5
va a x00 +
b100 = 10
a x +
bx, a 2 +
b2, —, a n +
bn ketma-ketlikning dastlabki 200 ta hadi yig’indisini toping? A) 2000 B) - 5 Q - 8 D) - 7
68. Arifmetik progressiya uchun a x = 2.5
bx - 7.5
va Oxgg +
bxgo = Ю
a x +
bx, a 2 + b2, ..., a„ +
bn ketma-ketlikning dastlabki 300 ta hadi yig’indisini toping? A) 3000 B) - 5 О - 8 D) - 7 69.
Musbat sonlardan tashkil topgan aXl a 2, ... ketma
ketligi uchun a x — 1 va barcha natural n-da an+ 2 =
a n * an+1 shart bajarilsin. Ketma ketlikning 100 - hadini toping ? B) - 5 О - 8 D) - 7
manfiy butun son uchun с - butun a - b +
1 3 , bo’ls a , с ningeng katta qiymatini toping? A) - 1 7 B ) - 5 О - 8 D) - 7 71.
a + b + с = —7 , bo’lsa (— + — + — ) = 1 ,
\a + b й+с a + c / A Q l
70. bo’lsa
a + b + с — (------ 1 -
c + a — +
ni toping ? A L - 3 B) - 5 О D) —7
72. Bironta sonning kvadratini 7 ga bo’lganda qanday qoldiq qolishi mumkin? A) 0.1.2.4 B ) - 5 C) - 8 D) - 7 73.
g (x ) =
x sin2x A) 1 B ) - 5 bo'Isa, g' ( - J =? 74. - +
-I — 2 2 + 4 2 + 4 + 6 C) - 8 + ••• + D) - 7
. = 9 A L ^ B ) —5 2 + 4 + 6 + - + 2 4 C) - 8 D) - 7 75.
f i x ) =
x 3 + 2a x 2 + 3
bx + 8 , bo’lsa/ " (3 ) = 2 2 , a = ?
A L 1 B) - 5 C) - 8 D) - 7 76.
Kvadratga 2 ta aylana ichki chizilgan radiusi 1 ga teng bo’lgan 1-aylana kvadratning 2 ta qo’shni tomoniga urinadi.Radiusi 3 ga bo’lgan qolgan 2 - tomonga va 1 - aylanaga urinadi. Kvadratning diagonalini toping? A )_ 2 (2 + 2л/2) B ) - 5 C) - 8 D) - 7
77. cos9x = 4
cosx , bo’lsa (4co s23x — 3 )(4 c o s2x — 3) ni toping ?
4 B) - 5 C) - 8 D) - 7
78. x = l bo’lsa, ^ +
+ ( a - f c ) ( a - c ) ( b —a ) ( b - c )
( c - a ) ( c - b ) A) 1 B) - 5 * C) - 8
D) - 7 79.
^ (x ) berilgan (a, b) intervalda va differensiallanuvchi bo’lsa
( x ) ) _1 funksiyaning (a,
intervalida hosilasini toping? АL - t e M f V o O B) - 5 C) - 8 D)—7 80.
g {x ) berilgan (a, b) intervalda va differensiallanuvchi bo’lsa Q?(x
funksiyaning (a, b) intervalida hosilasini toping? А } - 2 ( Д х ) ) ' У « b ) - 5 C ) - 8 D ) - 7 81.
ab +
be — ac , bo’lsa a 2 + b 2 + c 2 = 4
|a — b + c| ni toping? A) 2 B ) - 5 C)—8
D )- 7 82.
xy = a 2 , bo’lsa a) a- ni toping? x ( y - a ) - y ( x - a )
r ° A) 0 B ) - 5 C ) - 8 D ) - 7
83. Agar 0 ga teng bo’lmagan haqiqiy sonlar uchun x + y + z = xyz va x 2 = yz shartlarni qanoatlantirsa x 2 ning eng kichik qiymatini toping ?
A} 3 B ) - 5 C ) - 8 D)—7 84.
Agar 0 ga teng bo’lmagan haqiqiy sonlar uchun x + y + z = xyz va x 2 = yz shartlarni qanoatlantirsa x ning eng kichik qiymatini toping ? A) - V 3 B ) - 5 C ) - 8 D ) - 7
85. a + x =
у bo’lsa , ( a 2 — y 2 — x 2 + 2xy) : —y~x J J a + y + x ni toping ? A) 0 B ) - 5 Q —8 D)—7
86. —J L ifoda natural qiymat qabul qiluvchi barcha a £ Asonlarni toping ? A)
£ 1,9 B ) - 5 0 - 8 D ) - 7 87.
- ~ ifoda natural qiymat qabul qiluvchi barcha a £ N sonlami yig’indisini toping ? A] 10 B ) - 5 0 - 8 D )- 7
—* У
ifodani aniqlash soxasini 88
x ( x - y ) toping ?
A) {(x,y)|x € R ,y 6
R ,x ^ 0 ,y * x) B)—5 C)—8 D)—7 Vx + 2 + x — 4 < 6 tengsizlikning butun sondagi yechimlar yig’indisini toping ? A)25 B ) - 5 0 - 8 D ) - 7 89.
\x+3\+x x + 2 bor?
A12 ta B )—5
\x+2\+x 90.
x + l bor?
A)1 ta B ) - 5 > 1
0 - 8 D )- 7
> 1 tengsizlikni nechta manfiy butun ildizi 0 - 8 D ) - 7
[x+4\+x 91.
" x+3~ >
tengsizlikni nechta manfiy butun ildizi bor? A}3
ta B ) - 5 0 - 8 D )- 7
92. Agar
2 mn
= - bo’lsa , — 3mn =7 n 2+ 1 2 m 2 7 2 n 2- 5 m 2 A l- ^ y o k il B ) - 5 0 - 8 D )- 7
93. x 2 > 17 tengsizlikning eng katta manfiy va eng kichik musbat butun qiymatlari ko’paytmasini toping?
A) - 2 5 B )—5 0 - 8
D )- 7 94.
x 2 < 31 ning nechta butun yechimi bor? A) 11
ta B)—5
0 - 8 D )- 7
х 2+лг-3 0 95.
< 0 tengsizlikning natural sonlardan l*-s|+i
iborat yechimlari yig’indisini toping? A} 15 B ) - 5 0 - 8 D)—7
96.
< 0 tengsizlikning natural sonlardan l* -5 | + l iborat yechimlari yig’indisini toping? A) 21 B )—5 C)—8 D ) - 7 x2+ar-20
97 < 0 tengsizlikning natural sonlardan l* -3 | + l iborat yechimlari yig’indisini toping? A) 10 B ) - 5 0 - 8 D)—7
98.
< 0 tengsizlikning natural sonlardan |x-2| + l iborat yechimlari yig’indisini toping? A] 6 B )—5 0 - 8 D ) - 7
99.
< 0 tengsizlikning natural sonlardan I*—4| + 1 iborat yechimlari yig’indisini toping? A} 28 B ) - 5 0 - 8 D ) - 7 100.
10 ta o’quvchi bor. Ularni 3 tadan qilib necha xil usul bilan gurux qilish mumkin? A U 20 B)130 0 8 0
0 1 6 101.
8-mart bayrami 10 ta o’gil bola o’quvchi 8 ta qizga xar biri 1 tadan sovg’a berdi va xamma qizlar 5 tadan sovg’a olishdi. Guruhda nechta qiz bor? A)16
B)130 0 8 0
0 1 6 102.
10 ta pochtachi 8 ta qutiga har biri 1 tadan hat tashadi. Har bir qutida 5 tadan hat bo’lsa, nechta quti bor ? A}16
B)130 0 8 0
0 1 6 103.
Aloqa binosida 50 ta kompyuter bor. Ularni bir biriga ulash davomida 8 ta sim chiqsa kompyuterlarni ulash uchun nechta sim kerak ?
А1200 В) 130 С)80
С)16 104.
10 ta kitob bor. Ularni 3 ta dan qilib sovg’a tariqasida necha xil usulda guruxlash mumkin ? A tl2 0 B)130 C)80
C)16 105.
10 ta gul bor ularni 3 tadan qilib necha xil usul bilan guldasta qilish mumkin ? A1120 B)130 C)80
C)16 106.
9 ta xatni 9 xil joyga 2 ta odam necha xil usul bilan tarqatadi? A1512 B)130 C)80
C)16 107.
Maktab xovlisida 1006 ta atirgul ekilgan Samandar barcha atirgullarni yarmini Diyora xam barchasini yarmini suv quyib sug’ordi. Bunda 3 ta atirgul ham Diyora ham Samandar tomondan sug’orildi. Nechta atirgul sug’orilmay qoldi ? A13
B)130 C)80
C)16 108.
3462 sonini raqamlar o ’zgarmagan xolda. Necha xil usul bilan yozish mumkin. A124 B)130 C)80
C)16 109.
Raketa so’zidan nechta turli so’z yozish mumkin? A 1 3 6 0 B 1 130 C) 80 C) 16
110. 5498 sonining raqamlaridan foydalanib nechta to’rt xonali son tuzish mumkin ?
2 4 B )1 3 0 C) 80 C) 16
111. 1 , 2 , 3, ... , 9 gacha raqamlardan nechta to’rt xonali son tuzish mumkin ( raqamlardan faqat 1 marta foydalanish mumkin) A) 3024
B) 130 C ) 80 C) 16
112. Basketbol musobaqasida 10 ta odam bor 5 tadan qilib 2 ta guruhni necha xil usul bilan yasah mumkin?
A t 2 5 2 B t 130 C) 80
C) 16 113.
30 ta O’quvchi bor sinfda boshliq yordamchi va kotib necha xil usul bilan saylash mumkin? A! 24360* B) 130 C) 80 C) 16
114. Bir kunlik dars jadvalda 3 ta turli fan bor 11 ta fanni xuddi shunday qilib necha xil usul bilan yaratish mumkin? At 990 Bt 130 C) 80
C) 16 115.
a . b e R [ a ] = [ b ] a - b = ? [ a ] - butun qism degani At f—1: I t B) 130 C) 80 C) 16
116. a vab sonlar berilgan. a2 < a , b > l bo’lsa quydagilardan qaysi biri o ’rinli? At
a b > a B ) 130 C) 80 C) 16 117. Agar P soni 3 dan katta tub son bo’lsa quydagilarni qaysi biriga P2 - 1 qoldiqsiz bo’linadi? At 6 B) 130
C) 80 C) 16 118.
x ning qanday qiymatlarida l ; 2 ( x —1 ) ; 4 ( x —1 ) 2 cheksiz kamayuvchi geometric progressiya bo’ladi? AM 0.5 ; 1 ) U ( 1 ; 1.5 ) B ) 1 3 0 C ) 8 0 C) 16
119. n ning qanday qiymatlarida 2" - 1 7g a bo’linadi? At 3 va 6
B )1 3 0 C) 80 C) 16 120.
Ko’paytmasi 7920 ga teng bo’lgan 4 ta ketma-ket natural sonlar yig’indisini toping? At 38 B) 130 C) 80 C) 16 121. - + — H -----1------ 1------------ hisoblang? 2 2 + 4
2 + 4 + 6 2 + 4 + - + 2 0 ° A) JY B )1 3 0 C) 80 C) 16 122. Ko’paytmasi 3192 ga teng bo’lgan 2 ta ketma-ket natural sonlar yig’indisi toping? A 1113 B ) 130 C) 80 C) 16 P(x) = 4x2+20x+25 Download 0,5 Mb. Do'stlaringiz bilan baham:
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