Kafedra: Ximiya Ózbetinshe júmisi

11) Eriwsheńlik koefsiyenti 25,5 bolgan 1,5 molyalli toyingan eritpedegi eriwshi zatti tawiń.
Sheshiliwi:

1. 
   Eriwshenlik koeffisent degenimizdin ozi 100gr eritiwshide erigen zattin massasi, demek 100gr da 25,5gr eritpe erigen. Uliwma eritpe massasi 125,5 gr.
   
2. 
   1000gr-----1,5M
   

100gr H₂O---x=0,15mol bul jerde bizler erigen zattin molin tawip aldiq.
0,15/25,5= 170gr AgNO₃ J=170gr AgNO₃
12) 6,25 molyalli kaustik soda eritpesiniń molyar konsentratsiyasin tawiń? (p=1,2 gr/ml).
Sheshiliwi:
1000gr suw
6.25mol NaOH 250gr
Eritpe 1250gr
V=1250/1.2=1.041 litr Cm=6.25 mol/1.041 litr =6 M J=6M
13) Tigizliǵi 1,215 g/ml bolgan eritpeniń molyarligi 2,25 molyalligi 2 ge teń. Erigen zatti aniqlań.
1) 1000 ml eritpe 2.25 mol zat 1215 gr eritpe
2) 2.25mol/x= 2 molyal
X=1.125 kg yaki 1125 gr eritiwshi
3) 1215-1125=90 erigen zat
90/2.25 mol =40 Mr NaOH J=NaOH


14) H₂SO₄*1,25SO₃ quramli oliemniń qanday mugdarin(gr) 1272,5ml suwda eritilip 1,8molyalli eritpe aliw mumkin?
Sheshiliwi: Bul maseleni sheshiwde esapti dioganal usili menen tabamiz
1.8 molyal*98=176.4gr H₂SO₄
176.4+1000g suw=1176.4 eritpe
176.4/1176.4=%=15%
H2SO₄*1.25SO₃=2.25H₂SO₄
198g--------------220.5
100%--------------x=111.4%

111.4% 15%---------x=198gr

15%
0% 96.4%-------1272.5


15) NaOH tiń molyal va payiz konsentratsiyalari qatnasi 1:3 bolsa C% ti tawiń.
Sheshiliwi:
X mol NaOH, 1000 gramm suw.
Qatnas: Molyal:C%(1:3)

X=8.3333 mol NaOH
Yaki 8.33▪️40=333.3gr
C%=333.3/1333.3=%=25% J:25%