1
= (1, 0,
1, 1). We already have X
1
associated with Y
1
. This means that X
3
is not associated with any vector in the
output space. On the other hand, if instead of getting X
1
we obtained a different X
4
vector, and if this in the
feed forward operation produced a different Y vector, then we repeat the operation of the network until no
changes occur at either end. Then we will have possibly a new pair of vectors under the heteroassociation
established by this BAM network.
Special Case—Complements
If a pair of (distinct) patterns X and Y are found to be heteroassociated by BAM, and if you input the
complement of X, complement being obtained by interchanging the 0’s and 1’s in X, BAM will show that the
complement of Y is the pattern associated with the complement of X. An example will be seen in the
illustrative run of the program for C++ implementation of BAM, which follows.
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