Timsollarni tanib olish” fanidan

V₁

X2	1	1	0	0	0	1	0	0	1	0	0	0	0	1	0	0	0
X3	1	0	1	1	1	1	0	0	0	1	0	0	1	0	0	0	0
X4	0	0	0	1	1	0	1	0	0	1	0	0	1	0	0	0	1	V2
X5	0	0	0	1	1	1	0	1	1	0	0	0	0	1	0	0	1
X6	1	0	0	1	1	0	1	0	0	1	0	0	0	0	0	0	0
X7	1	0	0	1	0	0	0	0	1	1	1	0	0	1	0	0	0	V3
X8	0	0	0	0	1	0	0	0	1	1	1	1	1	0	0	0	1
X9	1	0	0	1	0	1	0	0	1	1	1	0	0	1	0	0	0
X10	0	0	0	1	0	0	0	0	0	0	0	0	1	1	1	0	0	V4
X11	1	0	0	0	1	1	0	0	0	1	0	0	1	1	0	1	0
X12	1	0	0	0	1	0	0	0	1	0	0	0	1	1	1	1	0
X*	1	0	0	0	1	0	0	0	1	0	0	0	0	1	1	1	1

Talab etiladi: O’Tdan sinflarga xos boʻlgan 1 va 2 - tipli oddiy BTni toping va yangi timsolni sinflarning qaysi biriga tegishli ekanligini aniqlang:

3) V₂ sinfga xos 1-tipli OB;

Dasturdan screenshot:

Dastur kodi:

import numpy as np
import random
import math
array = np.random.randint(2, size=(6, 5))
print("Klasslar berilgan:" + '\n' + str(array))

res = [random.randrange(0, 2, 1) for i in range(5)]

print("Tanlanma obyekti : " +'\n'+ str(res))

array2 = []

array3 = []
array4 = np.random.randint(2, size=(6, 5))
for x in range(6):
array2.clear()
for y in range(5):
if array[x][y]==res[y]:
array2.append(1)
else:
array2.append(0)
array3.append(array2)

print('Obyektlar: ')

print(array4)
count = 0
for x in range(5):
for y in range(6):
if array[y][x]==array4[y][x]:
count+=1
S1 = count

count2 = 0

for x in range(5):
for y in range(6):
if array[y][x]==array3[y][x]:
count2+=1
S2 = count2
for x in range(5):
for y in range(6):
if array[y][x]==array3[y][x]:
count2+=1
S3 = count2

print(f"1-klass uchun V1={count} va 2-klass uchun V2={count2}")

if S1>S2:
print("K1 sinf qiymati K2 sinf qiymatidan katta bo'lgani uchun obyekt 1 - sinfga tegishli")
else:
print("K2 sinf qiymati K1 sinf qiymatidan katta bo'lgani uchun obyekt 2 - sinfga tegishli")

Natija:

Alohida tanlanma uchun: