Test matematika progressiya 1

17.Dastlabki 5 ta hadining yig’indisi 242 va mahraji 3 ga teng geometrik progressiyaning 4- hadini toping. A) 486 B) 162 C) 54 D)27


18.02+a³+…=8a bo’lsa a ni toping.
A) 0,25 B) 125 C) 0,75 D) 0,875


19.-2, 3t-2, 3t-14 sonlari kamayuvchi geometrik progressiyaning ketma-ket 3ta hadlari bo’ladigan t ning barcha qiymatlari yig’indisi yoki t ning qiymatini toping. A) -7 B)-5 C)2 D) -4/3


20.Agar arifmetikprogressiyada a₂+a₅–a₃ =10 va
a₁+a₆ =17 bo’lsa uning o’ninchi hadini toping.
A) 24 B)26 C)28 D)29


21.O’suvchi arifmetikprogressiyaningdastlabki uchta hadining yig’indisi 24 ga teng. Shu progressiyaning ikkinchi hadini toping.
A) 8 B) aniqlab bo’lmaydi C) 10 D) 6


22. y,3y+5,5y+10,…… arifmetik progressiyaning dastlabki 8 ta yig’indisi 396 ga teng.y ning qiymatini toping.
A) 2 B) 3 C) 4 D)5 E)6
23.O’zidan oldinkelganbarcha toq natural sonlar yig’indisining 1/6 qismiga teng bo’lgan natural sonni toping?
A) 18 B)30 C)24 D)36 E)48


24.Arifmetik progressiyabirinchio’nta hadining yig’indisi 140 ga teng bo’lsa, a₂ +a₉ ni aniqlang.
A)24 B)26 C) 30 D)28 E)27


25.Dastlabki 1000 ta natural sonlarning o’rta arifmetigini toping.
A)500 B)501 C) 501,5 D)500,5 E)502,5


26.Agar geometrikprogressiyahadlari uchun b₁b₃ …b₁₃ =b₂b₄….b₁₄ /128 tenglik o’rinli bo’lsa progressiyaning mahrajini toping.
A)128 B)64 C)32 D)256 E)aniqlabbo’lmaydi.
27. 2 va 12 orasiga 14 ta son arifmetik progressiya hosil qiladigan shaklda joylashtirildi.Shu progressiyaning yettinchi hadini toping.
A)5,75 B)7 C)6 D)6,5
28. 1 va 35 orasiga 23 ta son arifmetik progressiya hosil qiladigan shaklda joylashtirildi.Shu progressiyaning 13- hadini toping.
A)18 B)16,5 C)19,5 D)16