The Compton Effect Introduction


The Klein-Nishina Angular Distribution Formula



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Bog'liq
compton

The Klein-Nishina Angular Distribution Formula 
While Equations 1-3 tell us how to compute the energies of the scattered photon and electron in terms of 
the photon's angle, they do not tell us anything about the likelihood of finding a scattered photon at one angle 
relative to another. For this we must analyze the scattering process in terms of the interactions of electrons and 
photons. 
The electron-photon interaction in the Compton effect can be fully explained within the context of 
our theory of Quantum Electrodynamics or QED for short. This subject is beyond the scope of this course 
and we shall simply quote some results. We are interested particularly in the angular dependence of the 
scattering or the differential cross-section and the total cross-section both as a function of the energy of the 
incident photon. If you haven’t seen the term “cross section” before, for now you can just think of it as a 
quantity proportional to the relative probability of an interaction with a particular value of the variables. 
First we write the differential cross-section, also known as the Klein-Nishina formula: 

/
1
/
/
(5) 
where 
ε
= E
0
/m
e
c

and r
0
is the "classical radius of the electron" defined as e
2
/m
e
c

and equal to about 2.8 x 
10
-13
cm. The formula gives the probability of scattering a photon (integrated over 
φ
) into the solid angle 
element d
Ω
= 2
π
|d (cos 
Θ) | = 
2
π 
|sin 
Θ
| d
Θ
when the incident energy is E
0
. We illustrate this angular 
dependence in Figure 3 for one particular photon energy.
Fig. 3: Differential Cross-section of Compton scattering vs. angle (radians) 
Note that the most likely scattering is in the forward direction and that the probability of scattering 
backward is relatively constant with angle. On this plot and fig 2 we illustrate the dependence on initial 
photon energy Eo by choosing some arbitrary values. Since the gamma ray energies of interest are around 1 
MeV, we choose Eo= .5, 1.0, 2.0 m
e
c
2
as sample energies, that is for roughly .25, .5, and 1 MeV (since m
e
c
2

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