pastki ucltiga esa F = 2 0
кН bo‘lgan yig ‘iq kuch qo‘yilgan (2.2-rasm, a). Y ec h ish . B rusda h o s il boMgan ic h k i k u c h la rn i aniqlash u ch u n kesish
u su lid a n fo y d a la n a m iz . B u n in g uchun a w a l b ru s n in g pastki q is m in i kesib,
undan
N [ = F = 20kH n i a n iq la y m iz (2 .2 -ra sm , b). K e y in y u q o ri q is m in i
kesam iz va
N !x = F + qx te n g la m a sin i tu z a m iz (2.2-rasm , d). Tenglam ada-
g i x 0 dan
1/2 gacha o ‘ zgaradi. x = 0 boM ganda
N ‘‘ =20kF I ,
x = l / 2 boMganda esa
N“ = 2 0 + 1 0 -
\=3QkH boM adi. B o ‘ y la m a k u c h la r epyurasi 2.2-
rasm , e da k o ‘ rsatilgan.
N o rm a l k u c h la n is h la m i a n iq la y m iz . B ru s n in g pastki q is m id a g i n o rm a l
ku c h la n is h
N !
2 0 - I O 3
<7. = — = -------— = 10-107Я / д < 2
= \ 0 0 M H / m 2