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). Берилган  ] 2 / ; 2 / [    оралиқда аргумент ихтиёрий  х



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4). Берилган 
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оралиқда аргумент ихтиёрий 
х
- учун
функциянинг қийматларини Лагранж интерполяцион формуласида 
ҳисоблаймиз.  




































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5
.
0

x
нуқтада функциянинг қийматларини ҳисоблаш учун формуладаги
i
x
ва 
i
y


10
..
1

i
ўрнига унинг қийматларни қуйамиз ва ҳисоблаш 
натижасида функциянинг тақрибий қиймати 
1
.229853743
0
)
5
.
0
(

f
ни топамиз. 
5). а). 
)
(
sin
2
x
y

функциянинг Maple тилидаги графиги. 
>
plot(sin(x)^2,x=-1.57..1.57,color=red); 


61 
 
б). Берилган жадвал асосида Лагранж интерполяцион формуласи 
ёрдамида топилган функциянинг Maple тилидаги графиги чизиш дастури. 
 
> u:=proc(z)local s,s1,s2,i,k,x,y;x:=array(1..10);y:=array(1..10); 
x:=[-1.2566,-0.9425,-0.6283,-0.3142,0.0,0.3142,0.6283,0.9425,1.2566
,1.5708]; y:=[0.9045,0.6545,0.3455,0.0955,0.0,0.0955,0.3455,0.6545,0.9045,1.0];
s:=0; for i to 10 do
s1:=1; s2:=1; for k to 10 do if i<>k then s1:=s1*(z-x[k]); s2:=s2*(x[i]-
x[k]);fi; od; 
s:=s+s1/s2*y[i]; od;return(s) end; 
u
z

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