O’zgaruvchilar

A \ B
ni toping?

1

1

1

1
^а) A \ B  (x ^b) A \ B  (x ^с) A \ B  (x ^e) A \ B  (x
| 0.35),(x₂
| 0.28),(x₂
| 0.35),(x₂
| 0.35),(x₂
| 0.45),(x₃
| 0.10),(x₃
| 0.45),(x₃
| 0.55),(x₃
|1),(x₄
|1),(x₄
| 0),(x₄
| 0),(x₄
| 0);
| 0);
|1);
| 0).

32. Bizga ܷ = ^{ݔ_ଵ, ݔ_ଶ, ݔ_ଷ, ݔ_ସ^}, ܯ = ^[0,1^],
ܣ = ^{(ݔ_ଵ^|0.25⁾, ⁽ݔ_ଶ^|0.73⁾, ⁽ݔ_ଷ^|1⁾, ⁽ݔ_ସ^|0^)},
ܤ = ^{(ݔ_ଵ^|0.35⁾, ⁽ݔ_ଶ^|0.87⁾, ⁽ݔ_ଷ^|0⁾, ⁽ݔ_ସ^|1^)}.
berilgan bo’lsin.

Ayirma amalidan foydalanib
B \ A
ni toping?

1

1

1

1
^а) B \ A  (x ^b) B \ A  (x ^с) B \ A  (x ^e) B \ A  (x
| 0.35),(x₂
| 0.10),(x₂
| 0.60),(x₂
| 0.35),(x₂
| 0.27),(x₃
| 0.27),(x₃
| 0.14),(x₃
| 0.27),(x₃
| 0),(x₄
|1),(x₄
| 0),(x₄
| 0),(x₄
|1);
|1);
|1);
| 0).

33. 
    Bizga
    

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻
A=	1	0	1	1	1	0	1
B=	0	1	1	0	0	1	0

berilgan bo’lsin. A va B noravshan to’plamostilar orasidagi Xemming masofasini toping?

а) ݀⁽ܣ, ܤ⁾ = 6; b) ݀⁽ܣ, ܤ⁾ = 7; с) ݀⁽ܣ, ܤ⁾ = 5; e) ݀⁽ܣ, ܤ⁾ = 4.

33. 
    Bizga
    

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻	ݑ଼
A=	1	0	1	1	1	0	1	1
B=	1	1	0	0	1	1	0	0

berilgan bo’lsin. n=8 quvvatga ega bo’lgan chekli U to’plamdagi ikkita A va B
noravshan to’plamostilar orasidagi Xemming masofasini toping?

а) ߜ⁽ܣ, ܤ⁾ = ^଺ ; b) ߜ⁽ܣ, ܤ⁾
଼
= ^ସ ;
଼
с) ߜ⁽ܣ, ܤ⁾ = ^ଷ ;
଼
e) ߜ⁽ܣ, ܤ⁾
= ^଼. ହ

33. 
    Bizga A noravshan to’plamosti
    

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻
A=	0.5	0.2	0	0.1	0.3	0.7	0.9

berilgam bo’lsin. A ga α-pog’onali to’plamostini qo’llab ܣ_଴.ଶ va ܣ_଴.଻ ravshan to’plamostilarini toping?
а)

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻
^ܣ଴.ଷ ^=	1	0	0	0	1	1	1
^ܣ଴.଻	0	0	0	0	0	1	1

b)

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻
^ܣ଴.ଷ ^=	1	0	0	0	1	1	1
^ܣ଴.଻	0	0	0	0	0	1	1

с)

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻
^ܣ଴.ଷ ^=	1	0	0	0	1	1	1
^ܣ଴.଻	0	0	0	0	0	1	1

e)

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻
^ܣ଴.ଷ ^=	1	0	0	0	1	1	1
^ܣ଴.଻	0	0	0	0	0	1	1

33. 
    Bizga A noravshan to’plamosti
    

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻
A=	0.5	0.2	0	0.1	0.3	0.7	0.9

berilgam bo’lsin. A ga α-pog’onali to’plamostini qo’llab ܣ_଴.ଶ va ܣ_଴.଻ ravshan to’plamostilarini toping?
а)

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻
^ܣ଴.ଷ ^=	1	0	0	0	1	1	1
^ܣ଴.଻	0	0	0	0	0	1	1

b)

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻
^ܣ଴.ଷ ^=	1	0	0	0	1	1	1
^ܣ଴.଻	0	0	0	0	0	1	1

с)

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻
^ܣ଴.ଷ ^=	1	0	0	0	1	1	1
^ܣ଴.଻	0	0	0	0	0	1	1

e)

33. 
    

X Y ^{to’plamda da beriladigan noravshan munosabat tavsiflanadi.}

	ݑଵ	ݑଶ	ݑଷ	ݑସ	ݑହ	ݑ଺	ݑ଻
^ܣ଴.ଷ ^=	1	0	0	0	1	1	1
^ܣ଴.଻	0	0	0	0	0	1	1

а) ^{x  X , y Y : xRy;}
с) x  X , y Y : xRy;
b) ^{x  X , y Y : xRy;}
e) x  X , y Y : xRy.

33. 
    

X Y
to’plamda da beriladigan noravshan munosabat tavsiflanadi.

а) x  X , y Y : xRy;
с) x  X , y Y : xRy;
b) x  X , y Y : xRy;
e) ^{x  X , y Y : xRy.}

33. 
    R munosabatning birinchi proyeksiyasini aniqlovchi ifodani to’g’ri ko’rsating?
    

^а)  ⁽¹⁾ (x)    (x, y); ^b)  ⁽¹⁾ (x)   
(x, y);

R _y R R _y R

^с)  ⁽¹⁾ (x)    (x, y); ^e)  ⁽¹⁾ (x)   
(x, y);

R _{y x} R R _{y x} R

33. 
    R munosabatning ikinchi proyeksiyasini aniqlovchi ifodani to’g’ri ko’rsating?
    

^а)  ⁽¹⁾ (x)    (x, y); ^b)  ⁽¹⁾ (x)   
(x, y);

R _y R R _y R

^с)  ⁽¹⁾ (x)    (x, y); ^e)  ⁽¹⁾ (x)   
(x, y);

R _{y x} R R _{y x} R

33. 
    R munosabatning global proyeksiyasini aniqlovchi ifodani to’g’ri ko’rsating?
    

^а) H (R)     (x, y); ^b) H (R)    
(x, y);

y x ^R y x ^R

^с) H (R)    (x, y); ^e) H (R)   
(x, y);

y x ^R y ^R

33. 
    X = {x₁ , x₂ , x₃ , x₄ }; Y = {y₁ , y₂ , y₃ , y₄ } ^{to’plamlar va XRY munosabat matritsasi} jadval ko’rinishda berilgan.
    

	y 1	y 2	y 3	y 4	1-proyeksiya
x 1	0.3	0.2	0	0.5	?
x 2	0.7	0.8	1	0.1	?
x 3	1	0.5	0.3	0.6	?
x 4	0.8	0.1	0.9	0	?
	2-proyeksiya					Global proyeksiya
	?	?	?	?	?

1va 2-proyeksiyalar hamda global proyeksiyani toping?


а)

	y 1	y 2	y 3	y 4	1-proyeksiya
x 1	0.3	0.2	0	0.5	0.5
x 2	0.7	0.8	1	0.1	1
x 3	1	0.5	0.3	0.6	1
x 4	0.8	0.1	0.9	0	0.9
	2-proyeksiya				Global proyeksiya
	1	0.8	1	0.6	1

b)

	y 1	y 2	y 3	y 4	1-proyeksiya
x 1	0.3	0.2	0	0.5	0
x 2	0.7	0.8	1	0.1	0.1
x 3	1	0.5	0.3	0.6	0.3
x 4	0.8	0.1	0.9	0	0.9
	2-proyeksiya				Global proyeksiya
	1	0.8	1	0.6	1

с)

	y 1	y 2	y 3	y 4	1-proyeksiya
x 1	0.3	0.2	0	0.5	0.5
x 2	0.7	0.8	1	0.1	1
x 3	1	0.5	0.3	0.6	1
x 4	0.8	0.1	0.9	0	0.9
	2-proyeksiya				Global proyeksiya
	0.1	0.1	0	0	1

e)

	y 1	y 2	y 3	y 4	1-proyeksiya
x 1	0.3	0.2	0	0.5	0.5
x 2	0.7	0.8	1	0.1	1
x 3	1	0.5	0.3	0.6	1
x 4	0.8	0.1	0.9	0	0.9
	2-proyeksiya				Global proyeksiya
	1	0.8	1	0.6	0.5

33. 
    R₁ va R₂ munosabatlarning “max-min” – kompozitsiyasini ifodalovchi formulani ko’rsating?
    

R oR R R
а) ^{ (x, z)  [ (x, y)   ( y, z)]  max[min(}
1 2 _y 1 2

R oR R R
b) ^{ (x, z)  [ (x, z)   ( y, z)]  max[min(}
1 2 _y 1 2
 (x, y),  ( y, z))].

R R
1 2



R R
 (x, z),  ( y, z))].
1 2

R oR R R R R
с) ^{ (x, z)  [ (x, y)   ( y, z)]  min[max(  (x, y),  ( y, z))].}
1 2 _y 1 2 1 2

R oR R R
e) ^{ (x, z)  [ (x, y)   (x, z)]  max[min(}
1 2 _y 1 2
 (x, y),  (x, z))].

R R
1 2

33. 
    R₁ va R₂ munosabatlarning “max-min” – kompozitsiyasini ifodalovchi formulani ko’rsating?
    

y
_а) _R1oR2 (x, z)  [_R1 (x, y)  _R2 ( y, z)]  max[min( _R1 (x, y), _R2 ( y, z))].

y
_b) _R1oR2 (x, z)  [_R1 (x, z)  _R2 ( y, z)]  max[min( _R1 (x, z), _R2 ( y, z))].

y
_с) _R1oR2 (x, z)  [_R1 (x, y)  _R2 ( y, z)]  min[max( _R1 (x, y), _R2 ( y, z))].

y
_e) _R1oR2 (x, z)  [_R1 (x, y)  _R2 (x, z)]  max[min(_R1 (x, y), _R2 (x, z))].

33. 
    Mamdani bo`yicha noravshan mantiqiy xulosa chiqarish ifodasi qaysi formula bilan aniqlanadi?
    

_C (z)  _C (z)  _C (z)  [₁  _C (z)]  [₂  _C (z)] 
_а) 1 2 1 2
 max[min(₁, _c (z)),min(₂ , _c (z))];
1 2

1
_C (z)  _C (z)  _C (z)  [₁  _C (z)]  [₂  _C
(z)] 

1
^b)  max[min(
, _c1
2
(z)),max(₂
, _c2
1 2
(z))];

1
_C (z)  _C (z)  _C (z)  [₁  _C (z)]  [₂  _C
(z)] 

1
^с)  max[max(
, _c1
2
(z)),min(₂
, _c2
1 2
(z))];

1
_C (z)  _C (z)  _C (z)  [₁  _C (z)]  [₂  _C
(z)] 

1
^e)  min[max(
, _c1
2
(z)),max(₂
, _c2
1 2
(z))].

33. 
    Larsen bo`yicha noravshan mantiqiy xulosa chiqarish qiymati qaysi formula bilan aniqlanadi?
    

а) ^
z    
z   
z;

C 1 C₁ 2 C₂

b) ^
z    
z   
z;

C 1 C₁ 2 C_2
с) _C z  ₁  _C z ₂  _C z;

1
      2  

1

2
_e) _C z  ₁  _C z  ₂  _C z .

33. 
    Zade bo`yicha noravshan mantiqiy xulosa chiqarish qiymati qaysi formula bilan aniqlanadi?
    

1

1

2
_а) _C (z)  1   _Ñ z 1   _Ñ z;

b) ^_C
с) ^
(z)  1 

1

1
(z)  1 
 _Ñ
 
z 1 

1

2
z 1 
 _Ñ
 
z;
z;

C
e) ^
(z)  1 
Ñ₁
 
z 1 
2 Ñ
 
z.

C 1 Ñ₁ 2 Ñ

33. 
    Lukasevich bo`yicha noravshan mantiqiy xulosa chiqarish qiymati qaysi formula bilan aniqlanadi?
    

_а)  z 1 1   z 1 1   z;
Ñ 1 Ñ₂ 2 Ñ₂

_b)  z 1 1   z 1 1  
z;

Ñ 1 Ñ₂ 2 Ñ₂

с) ^{ z 1 1   z 1 1  }
z;

Ñ 1 Ñ₂ 2 Ñ₂

2

2
_e) _Ñ z  1 1₁  _Ñ z 1 1 ₂  _Ñ
z.

33. 
    Lingvistik o’zgaruvchining strukturasini tavsivlash uchun quyidagi qanday qoidalardan foydalaniladi?
    

а) Sintaktikli va semantikli qoidalardan;
b) Grafikli va semantikli qoidalardan;
с) Chiziqli va sintaktikli qoidalardan;
e) Statistik li va ehtimolli qoidalardan.

33. 
    Lingvistik o’zgaruvchi tushunchasining strukturasito’g’ri keltirilgan javobni ko’rsating?
    

а) ⟨A, T (A), U, V, M⟩; b) ⟨A, T (M), U, V, M⟩;
с) ⟨A, T (V), U, V, M⟩; e) ⟨A, T (U), U, V, M⟩.

33. 
    Lingvistik o’zgaruvchi tushunchasining strukturasi to’g’ri keltirilgan javobni ko’rsating?
    

а) ⟨A, T (A), U, V, M⟩; b) ⟨A, T (M), U, V, M⟩;
с) ⟨A, T (V), U, V, M⟩; e) ⟨A, T (U), U, V, M⟩.