Mavzu: Hisoblash geometriyasi

Qaror. Peak formulasi bo'yicha: S \u003d B + - 1 .
Shakl 8 S \u003d 12 + 6/2 - 1 \u003d 14 (sm²)
7-topshiriq.
Trapezoid katakchali qog'ozga 1 sm 1 sm o'lchamdagi kataklar bilan tasvirlangan. Uning maydonini kvadrat santimetrda toping.
Qaror. Peak formulasidan foydalanamiz:
B \u003d 12, G \u003d 17
Shakl 9 S \u003d 12 + 17/2 - 1 \u003d 19.5 (sm²)
Javob: 19.5
Peak formulasi, shuningdek, amaliy tarkib bilan geometrik muammolarni echishga yordam beradi.
8-topshiriq
1 sm - 200 m shkala bo'yicha 1 × 1 (sm) kvadrat panjara bilan rejada tasvirlangan o'rmon maydonini (m² da) toping.
Qaror.
Shakl 10 V \u003d 8, G \u003d 7. S \u003d 8 + 7/2 - 1 \u003d 10.5 (sm²)
1 sm² - 200 m² S \u003d 40,00010.5 \u003d 420,000 (m²)
Javob: 420,000 m²
9-topshiriq .
1 sm - 200 m shkala bo'yicha 1 × 1 (sm) kvadrat panjara bilan rejada ko'rsatilgan maydonning maydonini (m² da) toping.
Qaror. Pik formulasi bo'yicha katakli qog'ozda tasvirlangan to'rtburchakning S maydonini toping: S \u003d B + - 1
B \u003d 7, G \u003d 4. S \u003d 7 + 4/2 - 1 \u003d 8 (sm²)
Shakl 11 1 sm² - 200 m² S \u003d 40,000.8 \u003d 320,000 (m²)

• Teshikli ko'pburchakning maydonini topish.

• Tugatgan: Ismoilov Dilshodbek

• 10-sinf MOBU SOSH№1 Baymak

• Matematikadan imtihon vazifalari qatoriga raqamlar, xususan panjara ko'pburchaklar sohalarini topish vazifalari kiradi:

• (B6-sonli vazifalar - 2010, 2011 yy.,

• B3 - FOYDALANISH 2012)