Masalalar ishlanish usullari 0 gr eritmada gr K

Masalalar ishlanish usullari

1. 
   50 gr eritmada 6.5 gr K₂SO₄ tuzi erigan bo’lsa, eruvchanlik koeffisentini toping.
   

50 gr Eritma massasi

6,5 gr tuz (K₂SO₄)

50-6.5=43.5 gr Suv

43.5 gr suvda ------------ 6.5 gr tuz

100 gr suvda ------------ X= 14,94 gr

2. 
   500 gr eritmadagi erigan moddaning massani aniqlang. (Eruvchanlik koeffisenti S=91,6)
   

100 gr ---------- 91,6 gr

500 gr ---------- X= 458 gr

3. 
   Zichligi 1.12 gr/ml hajmi 300 ml bo’lgan 30% li eritma tarkibidagi erigan modda massasini aniqlang.
   

1.12 gr ------------ 1 ml

336 gr =X ------------- 300 ml

336 gr eritma massasi

336 gr ------------- 100 %

100,8 gr =X-------------- 30 %

4. 
   0.75 mol NaNO₃ suvda eritilib 250 ml eritma tayyorlandi. Hosil bo’lgan eritmaning molyar konsentratsiyasini toping.
   

1l -------- X= 3 mol

0.25l --------- 0.75 mol C_M= 3 mol/l

5. 
   11.2 l vodorod xlorid suvda eritilib 100 ml eritma tayyorlandi. Eritmaning molyar konsentratsiyasini aniqlang.
   

11.2 l HCl ------- X= 0,5 mol

22.4 l --------- 1 mol

1 l ----------- X= 5 mol C_M=5 mol/l

1. 
   l ----------- 0.5 mol
   

6. 
   N₂ va H₂ reaksiya kirishib NH₃ hosil bo’ldi. Ushbu reaksiyadan Azotning sarflanish tezligi 3 mol/l*min. V=8 l , N₂ 104 moldan 8 molgacha kamaygan. Reaksiya qancha vaqt davom etgan (min)?
   

N₂ 104-8=96 mol

C=96/8=12mol/l

1min ----------- 3 mol/l

4min = x ----------- 12 mol/l

7. 
   3A + 2B = C ushbu reaksiyada dastlabki moddalarning konsentratsiyalari 2 marta oshirilsa tezlik qanday o’zgaradi?
   

V=K[A]^a * [B]^b

V= [2]³ * [2]² = 32 marta ortadi

8. 
   Dissotsialanish darajasi 75% bo’lgan 100ml 0.2 molyalli CaNO₃ eritmasida necha mol kation bo’ladi?
   

1l --------- 0.2 mol

0.1l --------- x = 0.02 mol

0.02 * 0.75 = 0.015 mol

Ca(NO)₂ = Ca²⁺ + 2NO₃^-

1 --------- 1

15. 
    ------- x= 0.015 mol Ca²⁺ kationi
    

9. 
   ²³⁸₉₂U + ₀¹n = _-1e + ₉₆²⁴⁴Cm ushbu yadro reaksiyasida 9.52 gr uran reaksiyaga kirishishi natijasida nechta electron hosil bo’lgan?
   

9.52g ---------- x= 0.41*NA

²³⁸₉₂U + 6 ₀¹n = 4 _-1e + ₉₆²⁴⁴Cm

92g ------------ 4*NA

10. 
    Tarkibi 71.5 % metan CH₄ va 28.55 % uglerod (II) oksid CO laridan iborat 7.84 m³ aralashmaning massasini aniqlang.
    

V= 7.84 * 0.7145 = 5.6 m³ CH₄

V= 7.84 * 0.2855 = 2.24 m³ CO

22,4 m³ ------- 16 kg

5.6 m³ --------- x= 4 kg CH₄

22,4 m³ --------- 28 kg

2.24 m³---------- x= 2.8 kg CO

4+2.8= 6.8 kg