Laboratoriya ishi standart algoritmlar va itеratorlar. Standart algoritmlar. Itеratorlar va ularning qo`llanilishi. Xotirani taqsimlovchilar va ularga qo`yilgan talablar. Standart bo`yicha taqsimlovchi. Ishning maqsadi

#include "stdafx.h"

#include

#include

using namespace System;

using namespace std;

6. 
   int main( )
   
7. 
   {
   
8. 
   using namespace std;
   
9. 
   double pi = 3.14159265359;
   

10. 
    complex c1 ( polar ( 5.0 ) ); // Default argument = 0
    
11. 
    complex c2 ( polar ( 5.0 , pi / 6 ) );
    
12. 
    complex c3 ( polar ( 5.0 , 13 * pi / 6 ) );
    
13. 
    cout << "c1 = polar ( 5.0 ) = " << c1 << endl;
    
14. 
    cout<< "c2 = polar ( 5.0 , pi / 6 ) = " << c2 << endl;
    
15. 
    cout<<"c3 = polar (5.0, 13*pi / 6 ) = " << c3 << endl;
    

16. 
    double absc1 = abs ( c1 );
    
17. 
    double argc1 = arg ( c1 );
    
18. 
    cout << "C1 moduli c1 dan quyidagilar yordamida tiklanadi: abs ( c1 ) = "
    
19. 
    << absc1 << endl;
    
20. 
    cout << "C1 argumenti c1 dan quyidagilar yordamida tiklanadi:\n arg ( c1 ) = "
    
21. 
    << argc1 << " radians, qaysiki " << argc1 * 180 / pi
    
22. 
    << " darajasi." << endl;
    

23. 
    double absc2 = abs ( c2 );
    
24. 
    double argc2 = arg ( c2 );
    
25. 
    cout << "C2 moduli c2 dan s2 yordamida tiklanadi: abs ( c2 ) = "
    
26. 
    << absc2 << endl;
    
27. 
    cout << "C2 argumenti c2 dan quyidagilar yordamida tiklanadi:\n arg ( c2 ) = "
    
28. 
    << argc2 << " radianda, qaysiki " << argc2 * 180 / pi
    
29. 
    << " darajalar." << endl;
    
30. 
    if ( (arg ( c2 ) <= ( arg ( c3 ) + .00000001) ) ||
    
31. 
    (arg ( c2 ) >= ( arg ( c3 ) - .00000001) ) )
    
32. 
    cout << " c2 & c3 komplex sonlar bir xil argumentlardan "
    
33. 
    << "tashkil topgan."<< endl;
    
34. 
    else
    
35. 
    cout << " c2 & c3 komplex sonlar bir xil argumentlardan "
    
36. 
    << "tashkil topmagan."<< endl;
    
37. 
    getchar();
    
38. 
    }
    

Dastur natijasi:
c1 = polar ( 5.0 ) = (5,0)
c2 = polar ( 5.0 , pi / 6 ) = (4.33013,2.5)
c3 = polar ( 5.0 , 13 * pi / 6 ) = (4.33013,2.5)
C1 moduli c1 dan quyidagilar yordamida tiklanadi: abs ( c1 ) = 5
C1 argumenti c1 dan quyidagilar yordamida tiklanadi:
arg ( c1 ) = 0 radians, qaysiki 0 darajasi.
C2 moduli c2 dan s2 yordamida tiklanadi: abs ( c2 ) = 5
C2 argumenti c2 dan quyidagilar yordamida tiklanadi:
arg ( c2 ) = 0.523599 radians, qaysiki 30 darajalar.
c2 & c3 komplex sonlar bir xil argumentlardan tashkil topgan.

2. 
   comj() complex funksiyasiga misol:
   

Funksiya shabloni:
template
complex conj(const complex& complexNum);


Dastur matni:

1. 
   #include "stdafx.h"
   
2. 
   #include
   
3. 
   #include
   
4. 
   int main( )
   
5. 
   {
   
6. 
   using namespace std;
   

7. 
   complex c1 ( 4.0 , 3.0 );
   
8. 
   cout << "Komplex raqam c1 = " << c1 << endl;
   

9. 
   double dr1 = real ( c1 );
   
10. 
    cout << " c1 ning haqiqiy qismi bu haqiqiy ( c1 ) = "
    
11. 
    << dr1 << "." << endl;
    

12. 
    double di1 = imag ( c1 );
    
13. 
    cout << " c1 ning no'malum qismi bu imag ( c1 ) = "
    
14. 
    << di1 << "." << endl;
    

15. 
    complex c2 = conj ( c1 );
    
16. 
    cout<<"c1 ning komplex kasr qismi bu c2 = conj(c1)= "
    
17. 
    << c2 << endl;
    

18. 
    double dr2 = real ( c2 );
    
19. 
    cout << " c2 ning haqiqiy qismi bu real ( c2 ) = "
    
20. 
    << dr2 << "." << endl;
    

21. 
    double di2 = imag ( c2 );
    
22. 
    cout << " c2 ning no'malum qismi bu imag ( c2 ) = "
    
23. 
    << di2 << "." << endl;
    

24. 
    complex c3 = c1 * c2;
    
25. 
    cout<<"(c1 * conj (c1) ) ning haqiqiysi bu c1 * c2 = "
    
26. 
    << real( c3 ) << endl;
    
27. 
    getwchar();
    
28. 
    }
    

Dastur natijasi:
Komplex raqam c1 = (4,3)
c1 ning haqiqiy qismi bu haqiqiy ( c1 ) = 4.
c1 ning no'malum qismi bu imag ( c1 ) = 3.
c1 ning komplex kasr qismi bu c2 = conj ( c1 )= (4,-3)
c2 ning haqiqiy qismi bu real ( c2 ) = 4.
c2 ning no'malum qismi bu imag ( c2 ) = -3.
(c1 * conj (c1) ) ning haqiqiysi bu c1 * c2 = 25

3. 
   imag() complex funksiyasiga misol:
   

Funksiya shabloni:
template
Type imag(const complex& complexNum);


Dastur matni:

1. 
   #include "stdafx.h"
   
2. 
   #include
   
3. 
   #include
   

4. 
   int main( )
   
5. 
   {
   
6. 
   using namespace std;
   
7. 
   complex c1 ( 4.0 , 3.0 );
   
8. 
   cout << " c1 komplex son = " << c1 << endl;
   
9. 
   double dr1 = real ( c1 );
   
10. 
    cout << " c1 ning haqiqiy qismi bu real ( c1 ) = "
    
11. 
    << dr1 << "." << endl;
    

12. 
    double di1 = imag ( c1 );
    
13. 
    cout << " c1 ning noma'lum qismi bu imag ( c1 ) = "
    
14. 
    << di1 << "." << endl;
    
15. 
    getchar();
    
16. 
    }
    

Dastur natijasi:
c1 komplex son = (4,3)
c1 ning haqiqiy qismi bu real ( c1 ) = 4.
c1 ning noma'lum qismi bu imag ( c1 ) = 3.

4. 
   polar() complex funksiyasiga misol:
   

Funksiya shabloni:
template
complex polar(const Type& _Modulus, const Type& _Argument = 0);


Dastur matni:

1. 
   #include "stdafx.h"
   
2. 
   #include
   
3. 
   #include
   

4. 
   int main( )
   
5. 
   {
   
6. 
   using namespace std;
   
7. 
   double pi = 3.14159265359;
   

8. 
   complex c1 ( polar ( 5.0 ) );
   
9. 
   // Default argument = 0
   
10. 
    complex c2 ( polar ( 5.0 , pi / 6 ) );
    
11. 
    complex c3 ( polar ( 5.0 , 13 * pi / 6 ) );
    
12. 
    cout << "c1 = polar ( 5.0 ) = " << c1 << endl;
    
13. 
    cout << "c2= polar ( 5.0 , pi / 6 ) = " << c2 << endl;
    
14. 
    cout << "c3= polar(5.0, 13*pi / 6 ) = " << c3 << endl;
    

15. 
    if ( (arg ( c2 ) <= ( arg ( c3 ) + .00000001) ) ||
    
16. 
    (arg ( c2 ) >= ( arg ( c3 ) - .00000001) ) )
    
17. 
    cout << " c2 & c3 komplex sonlar bir xil argumentlardan "<< "tashkil topgan."<< endl;
    
18. 
    else
    
19. 
    cout << " c2 & c3 komplex sonlar bir xil argumentlardan "<< "tashkil topmagan." << endl;
    
20. 
    double absc2 = abs ( c2 );
    
21. 
    double argc2 = arg ( c2 );
    
22. 
    cout << " c2 ning moduli bu : abs ( c2 ) = "
    
23. 
    << absc2 << endl;
    
24. 
    cout << " c2 argumenti bu :\n arg ( c2 ) = "
    
25. 
    << argc2 << " radianda, qaysiki " << argc2 * 180 / pi
    
26. 
    << " daraja." << endl;
    
27. 
    getchar();
    
28. 
    }
    

Dastur natijasi:
c1 = polar ( 5.0 ) = (5,0)
c2 = polar ( 5.0 , pi / 6 ) = (4.33013,2.5)
c3 = polar ( 5.0 , 13 * pi / 6 ) = (4.33013,2.5)
c2 & c3 komplex sonlar bir xil argumentlardan tashkil topgan.
c2 ning moduli bu : abs ( c2 ) = 5
c2 argumenti bu :
arg ( c2 ) = 0.523599 radianda, qaysiki 30 daraja.

Komplex sonlar uchun qayta yuklangan teng emas operatori - operator!= ga misol:

Operator shabloni:
template <class Type>
bool operator!=(
const complex& left,
const complex& right);


template <class Type>
bool operator!=(
const complex& left,
const Type& right);


template <class Type>
bool operator!=(
const Type& left,
const complex& right);


Dastur matni:

1. 
   #include "stdafx.h"
   
2. 
   #include
   
3. 
   #include
   

4. 
   int main( )
   
5. 
   {
   
6. 
   using namespace std;
   
7. 
   double pi = 3.14159265359;
   
8. 
   complex cl1 ( polar (3.0, pi / 6 ) );
   
9. 
   complex cr1a ( polar (3.0, pi /6 ) );
   
10. 
    complex cr1b ( polar (2.0, pi / 3 ) );
    

11. 
    cout << " cl1 komplex sonning chap tarafi= " << cl1 << endl;
    
12. 
    cout<<"cr1a komplex sonning birinchi o'ng tarafi = " <
    
13. 
    cout<<"cr1b komplex sonning ikkinchi o'ng tarafi = " <
    
14. 
    if ( cl1 != cr1a )
    
15. 
    cout << " cl1 & cr1a komplex sonlar teng emas." << endl;
    
16. 
    else
    
17. 
    cout << " cl1 & cr1a komplex sonlar teng." <
    
18. 
    if ( cl1 != cr1b )
    
19. 
    cout << " cl1 & cr1b komplex sonlar teng emas."<< endl;
    
20. 
    else
    
21. 
    cout << " cl1 & cr1b komplex sonlar teng." << endl;
    
22. 
    cout << endl;
    
23. 
    complex cl2a ( 3, 4 );
    
24. 
    complex cl2b ( 5,0 );
    
25. 
    int cr2a =3;
    
26. 
    int cr2b =5;
    

27. 
    cout<<"cl2a komplex sonning birinchi chap tarafi ="<
    
28. 
    cout<<"cr2a komplex sonning birinchi o'ng tarafi = " << cr2a << endl;
    
29. 
    if ( cl2a != cr2a )
    
30. 
    cout << " cl2a & cr2a komplex sonlar teng emas." << endl;
    
31. 
    else
    
32. 
    cout << " cl2a & cr2a komplex sonlar teng." << endl;
    
33. 
    cout<<"cl2b komplex sonning ikkinchi chap tarafi="<
    
34. 
    cout<<"cr2b komplex sonning ikkinchi o'ng tarafi="<
    
35. 
    if ( cl2b != cr2b )
    
36. 
    cout << " cl2b & cr2b komplex sonlar teng emas." << endl;
    
37. 
    else
    
38. 
    cout << " cl2b & cr2b komplex sonlar teng." << endl;
    
39. 
    cout << endl;
    
40. 
    double cl3a =3;
    
41. 
    double cl3b =5;
    
42. 
    complex cr3a ( 3, 4 );
    
43. 
    complex cr3b ( 5,0 );
    

44. 
    cout<<"cl3a komplex sonning birinchi chap tarafi="<
    
45. 
    cout<<"cr3a komplex sonning birinchi o'ng tarafi="<
    
46. 
    if ( cl3a != cr3a )
    
47. 
    cout << " cl3a & cr3a komplex sonlar teng emas." << endl;
    
48. 
    else
    
49. 
    cout << " cl3a & cr3a komplex sonlar teng." << endl;
    
50. 
    cout<<"cl3b komplex sonning ikkinchi chap tarafi="<
    
51. 
    cout<<"cr3b komplex sonning ikkinchi o'ng tarafi="<
    
52. 
    if ( cl3b != cr3b )
    
53. 
    cout << " cl3b & cr3b komplex sonlar teng emas." << endl;
    
54. 
    else
    
55. 
    cout << " cl3b & cr3b komplex sonlar teng." << endl;
    
56. 
    cout << endl;
    
57. 
    getchar();
    
58. 
    }
    

Dastur natijasi:
cl1 komplex sonning chap tarafi= (2.59808,1.5)
cr1a komplex sonning birinchi o'ng tarafi = (2.59808,1.5)
cr1b komplex sonning ikkinchi o'ng tarafi = (1,1.73205)
cl1 & cr1a komplex sonlar teng.
cl1 & cr1b komplex sonlar teng emas.

cl2a komplex sonning birinchi chap tarafi = (3,4)

cr2a komplex sonning birinchi o'ng tarafi = 3
cl2a & cr2a komplex sonlar teng emas.
cl2b komplex sonning ikkinchi chap tarafi = (5,0)
cr2b komplex sonning ikkinchi o'ng tarafi = 5
cl2b & cr2b komplex sonlar teng.

cl3a komplex sonning birinchi chap tarafi = 3

cr3a komplex sonning birinchi o'ng tarafi= (3,4)
cl3a & cr3a komplex sonlar teng emas.
cl3b komplex sonning ikkinchi chap tarafi = 5
cr3b komplex sonning ikkinchi o'ng tarafi = (5,0)
cl3b & cr3b komplex sonlar teng.