Java for Fucking Idiots: Learn the Basics of Java Programming Without any experience!

while
(index < alphabet.
length
) {
char
letter = alphabet[index];
if
(letter ==
'F'
) {
continue
;
}
System.
out
.println(letter);
index = index +
1
;
}
We print out everything except ‘F’. The code after a continue statement is
never reached, instead we return to the top of the loop.
It’s like a break statement’s little brother. It “breaks” this iteration and goes
to the next, but it doesn’t kill the entire loop. Lil boi.
If you hated ‘F’ so much that you wanted to immediately stop printing out
letters, you’d go back to using continue .
A BUG? IN MY CODE?
There’s a problem with my last example. A “bug” as a programmer might
say, where something happens that you didn’t expect.
Did you notice it? Probably not. But can you see it now? Why might this
beautifully written code not do exactly what I described?
Hint: look at where the 
continue;
statement is. What doesn’t happen when
the letter is F?
Did you get it? Take a second.

---

Answer: the loop runs forever! Look what happens when the letter is an F;
we immediately skip the iteration using a 
continue;
and go to the next
iteration of the loop.
But what letter are we gonna look at next iteration? F. And the next one? F.
We never increased the value of the index!!! We’ll keep pulling F out of the
array since the index doesn’t change. Don’t make this mistake.
Here’s the fixed example. We increase the index immediately after pulling
the letter from the array:
while
(index < alphabet.
length
) {
char
letter = alphabet[index];
index = index +
1
;