Introduction to Industrial Automation


Figure 4.34  Bidirectional and two-speed movable worktable via lead screw



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Introduction to Industrial Automation by Stamatios Manesis, George

Figure 4.34  Bidirectional and two-speed movable worktable via lead screw.


Logical Design of Automation Circuits 



 



147

For each of the auxiliary variables, we have:

 

Turn ON A S S



x

Turn OFF A S

x

B

C



=

=

=



=

=

1 2



0

1

2



 

( )


,

,

BC



SS

yB

Turn ON B S S



y

z

B



C

A

1



0

1

1 3



0

 

 



( )

( )


,

,

=



=

=

=



=

C

C



A

C

zAC



Turn OFF B S S

wAC


Turn

w

=



=

=

=



=

=

1



3 1

0

1



 

( )


,

ON C S S


Turn OFF C S S

b

A



B

=

=



=

=

0 1



0

0

1 0



1

 

 



( )

(

,



bb

x

S S



b AB xAB

S S


A

B

A



B

0

0



0

4 3


0

1

1



3 4

)

( )



,

,

=



=

=

=



+

=

+



+

 

 



( )

,

y



b AB yAB

A

B



=

=

=



+

0

1



0

Applying the logical Equation (1) to three auxiliary variables, we obtain,

 

A yBC xBC A



y B C xBC A

=

+



= + +

+

(



) (

)(

)



 

B wAC zAC B

w A C zAC B

=

+



=

+ +


+

(

) (



)(

)

 



C

b AB yAB b AB xAB C

b

A B y A B b AB x



=

+

(



)

+

+



=

+ +


+ +

+

0



1

0

1



(

) (


)(

)(

AAB C



+

),

and also



 

R

ABC, R



ABC, L

ABC, L


ABC

LS

HS



LS

HS

=



=

=

=



S

0

S



1

R

LS



b

1

b



0

S

3



L

LS

z



w

S

4



L

HS

y



x

S

2



R

HS

x



y

ABC


000

001


011

010


101

R = motion to the right, L = motion to the left, LS = low speed, HS = high speed



Figure 4.35  State diagram for application in Section 4.3.1, shown in Figure 4.34.


148

 



  Introduction to Industrial Automation

The implementation of these logical expressions results in the automation circuit shown in 

Figure 4.36, where it can also be checked that its operation satisfies the desired described 

automation.

4.4.2   Palindromic Movement of a Worktable with Memory

In Figure 4.37, a simplified form of the carrier (lead screw worktable) of a machine tool is depicted, 

which is called a “lathe”. The worktable of the lathe is desired to be moved in between two limit 

positions to the left and to the right, according to the following specifications:

  1. Initially, we define the movement of the table to the right with “S

R

” and the movement to 



the left with “S

L

”. In both states, and with the press of a button “s” (STOP), the table stops 



in its current position.

N

A



R

x

R



LS

Α

b



1

b

0



C

 

Α



Β

B

C



y

Β

A



B

z

C



A

C

w



A

B

C



A

B

A



C

A

y



B

x

B



A

C

Β



R

HS

C



Β

C

Α



Β

Α

C



L

HS

L



LS

Β

Figure 4.36  Automation circuit for application in Section 4.3.1 based on the state diagram of 



Figure 4.35.


Logical Design of Automation Circuits 



 



149

  2. With a press of the button “m” (memory button), the table continues moving in the same 

manner before it was stopped, due to the press of the button “s”.

  3. If the table is moving to the right (S

R

), then either by the press of a button “a” or when it 



reaches the end of its movement where the limit switch “z” is energized, the direction of the 

motion will be inverted, which means that the table should move to the left (S

L

).

  4. With the same approach, when the table is moving to the left (S



L

), either with a press of 

a button “d”, or when it reaches in the end of its movement where the limit switch “w” is 

energized, the direction of the motion will be inverted, which means that the table should 

move to the right (S

R

).



  5. If, during the movement of the table to the left (S

L

), the limit switch “w” is ener-



gized, while the limit switch “z” remains energized, due to a fault (e.g., the limit switch 

has been blocked), then the table should stop, like in the case where the button “s” had been 

pressed.

Overall, we have the following operational buttons and limit switches:

s = STOP button

m = motion continuation button

a = S

L

 motion button



d = S

R

 motion button



z = limit switch of the S

R

 motion



w = limit switch of the S

L

 motion



The corresponding state diagram is indicated in Figure 4.38, where the STOP state of S

0L

 and 



S

0R

 is noted, with a previous S



L

 or S


R

 motion correspondingly.

Based on this remark, we have the following Turn ON and Turn OFF sets for the auxiliary 

variables:

w

z

Worktable



Lead  screw

Motor


Motion

reverse


Motion

reverse


Figure 4.37  The movable carrier (lead screw worktable) of a machine tool.

S

0L



S

L

m



s+zw

S

R



a+z

d+w


S

0R

m



s

AB

00



01

11

10



Figure 4.38  State diagram for application in Section 4.4.2, shown in Figure 4.37.


150

 



  Introduction to Industrial Automation

Turn ON A S S d w

d w B


Turn OFF A S

L R


B

=

+



= +

=

=



 

(

)



(

) ,


1

R

R L



B

L L


S a z

a z B


Turn ON B S S m

 

 



(

)

(



(

)

+



= +

=

=



1

0

))



(

)

A



L

L

A



R R

Turn OFF B S S s zw

S S

=

=



=

+

+



0

0

0



0

 

( )



( )

(

)



m

s

mA mA m



S S

s zw A sA z

A

R

R



A

=

=



=

+

=



+

= +


+

=

1



0

1

w



wA s

+

Applying the logical Equation (1) to the A and B auxiliary variables, we obtain,



 

A (a z)B (d w)B A

a z B (d w)B A

= +


+

+

(



)

=

+



+

+

(



)

(

)



 

B

zwA s m B



z w A s(m B)

=

+



(

)

+



= + +

+

(



) (

)

,



and also,

 

S



AB S

AB

L



R

=

=



,

The implementation of these logical expressions is presented in the automation circuit shown in 

Figure 4.39.

N

R



B

A

z



B

w

 



s

m

d



 

A

A



B

w

a



z

B

S



R

Α

Β



Β

Α

S



L

Figure 4.39  Automation circuit for application in Section 4.4.2 based on the state diagram of 

Figure 4.38.


Logical Design of Automation Circuits 



 



151

4.4.3   Operation of N Machines with Pause under Specific Conditions

Let’s assume that we have a set of n identical machines, which we would like to start and stop 

manually with a corresponding n number of START-STOP pairs of buttons. For the START 

operation of the machines no specific condition is needed. However, for the STOP operation, due 

to some functional specifications, it is important that the STOP action is applied immediately to 

all the machines, except for the last in operation machine, which should terminate its operation 

only when a sensor is energized. The operation of the rest of the machines, except the last one, must 

stop independently of the sensor’s state. The difficult part of this problem is the fact that the last 

machine in operation is not predefined, rather it is randomly selected from the n of total machines. 

In the case that the sensor is activated, and the STOP button of the final operation machine is not 

pressed; then the machine continues to operate. To summarize, every machine from the n total can 

act as the last machine in operation, where we would like to stop it in cooperation with a sensor. In 

this case, it is assumed that the rest of the machines will have been stopped already.

At this point is should be mentioned that this problem is not an abstract example for tutorial 

purposes; it occurs frequently in the central autonomous heating systems of multiple apartments. 

In this case, the machines are replaced from the central electrovalves of the apartments (heating 

or cooling of the apartment). In these systems, every inhabitant can stop the heating at any time 

it is desired. In the case that the inhabitant is the last one who switches off the heating, in order 

not to have hot water trapped in specific areas of the pumps’ network, the automation system 

should prevent the electrovalve of the last apartment to close, even if the inhabitant keeps it open 

until all the thermal heating of the apartment is reduced to an acceptable level (based on a specific 

temperature sensor) before closing the final electrovalve.

Since the construction of the state diagram for 1, 2, 3,…, n-1,…, n machines is very complicated, 

we will only represent the case of three machines, but in a way that the expansion of the diagram to 

more machines would be straightforward. In Figure 4.40, this state diagram is presented with all the 

potential operational combinations of the machines; with the indications of the machines (A, B, C) and 

the three states (S

1

, S



2

, S


3

), where only the last machine is in operation, and from where the transition 

to S

0

 requires the logical condition for the sensor to be energized. In this automation system, the sensor 



signal, which is also the transition event, is represented by “t”. Additionally, we denote with “s

i

” and “p



i

” 

the START and STOP buttons of the i



th

 machine, with i=1, 2, 3 for the illustrated example.

Based on this analysis, the Turn ON and Turn OFF logical expressions for the auxiliary vari-

ables A, B, and C are defined as:

 

Turn ON A



S S s

S S s


0 1

B 0, C 0


3 2

B

=



+

=

=



=

 

 



( )

( )


1

1

1,, C 0



7 6

B , C 1


4 5

B ,


S S s

S S s


=

=

=



=

+

+



 

 

( )



( )

1

1



1

0 C


C

1

s BC s BC s BC s BC s B s B s



=

=

+



+

+

=



+

=

1



1

1

1



1

1

1



 

Turn OFF A

S S p t

S S p


1

B 0, C 0


1 B

=

+



=

=

1 0



5 4

 

 



( )

( )


==

=

=



=

=

+



+

0, C 1


1 B 1, C 0

1 B


S S p

S S p


2 3

6 7


1

 

 



( )

( )


,, C 1

p tBC p C p BC p BC p BC p Bt p B

p BC

=

=



+

+

+



=

+

+



=

+

1



1

1

1



1

1

1



1

Β

pp B p t p B p C p t p B C t



1

1

1



1

1

1



+

=

+



+

=

+ +



(

)



152

 



  Introduction to Industrial Automation

 

Turn ON B



S S s

S S s


1 2

A 1, C 0


0 3

A

=



+

=

=



=

 

 



( )

( )


2

2

0,, C 0



5 6

A , C 1


4 7

A ,


S S s

S S s


=

=

=



=

+

+



 

 

( )



( )

2

1



2

0 C


C

2

s AC s AC s AC s AC s C s C s



=

=

+



+

+

=



+

=

1



2

2

2



2

2

2



 

Turn OFF B

S S p

S S p t


2 A 1, C 0

2

A



=

+

=



=

1 2


3 0

 

 



( )

(

)



==

=

=



=

=

+



+

0, C 0


2 A , C 1

2 A


S S p

S S p


7 4

0

6 5



1

 

 



( )

( )


,, C 1

p AC p tAC p AC p AC p CA p Ct p C

p CA

=

=



+

+

+



=

+

+



=

+

2



2

2

2



2

2

2



2

pp C p t p C p A p t p C A t

2

2

2



2

2

2



+

=

+



+

=

+ +



(

)

 



Turn ON C

S S s


S S s

0 4


A 0, B 0

1 5


A

=

+



=

=

=



 

 

( )



( )

3

3



1,, B 0

2 6


A , B 1

3 7


A ,

S S s


S S s

=

=



=

=

+



+

 

 



( )

( )


3

1

3



0 BB

3

s AB s AB s AB s AB s B s B s



=

=

+



+

+

=



+

=

1



3

3

3



3

3

3



S

4

S



5

s

3



p

1

S



6

S

7



S

1

ABC



000

101


111

011


100

S

2



110

S

0



S

3

Machine A



Machine B

010


001

Machine C

p

3

•t



p

2

•t



p

1

•t



s

1

s



2

s

1



p

1

p



2

s

2



p

2

s



2

p

2



s

2

s



1

p

1



s

s



3

s

3



s

3

p



3

p

3



p

3

Figure 4.40  State diagram for the operation of three machines with pause under specific con-




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