Introduction to Industrial Automation


and two START-STOP control positions



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Introduction to Industrial Automation by Stamatios Manesis, George

and two START-STOP control positions.

N

C



C

R

 



f

0

b



1

 

b



0

e

f



1

Figure 4.8  The automation circuit extracted from the state diagram of Figure 4.7 for the direct 

on line starting motor with thermal overload protection and two START-STOP control positions.


Logical Design of Automation Circuits 



 



125

we would like to introduce the concept of mutual exclusion, which means that the operation of 

one motor should exclude the operation of the other one. Thus, in this case, it means that for 

C

1



 we will have that ‘Turn OFF’ = b

0

+C



2

, as indicated in Figure 4.9. In the same approach, for the 

C

2

 motor, the C



1

 operation signal will be equivalent to the stop of the C

2

 operation. If we apply 



the logical expression (1) for both variables C

1

 and C



2

 we will get that:

 

C

b



C

b C


b C

b C


1

0

2



1

1

0



2

1

1



=

+

+



=

+



(



)

(

)



and

 

C



C s C

2

1



2

=

+



(

)



The implementation of these logical expressions is displayed in Figure 4.10, where an error exists, 

since the energizing of C

2

 and the operation of the corresponding motor cannot be altered. This is 



due to the fact that, from the moment the relay C

2

 gets energized, this will be in a continuous latch



independent of the operation of the sensor. Moreover, the energizing of C

1

 is not possible due to the 



corresponding latch in the first branch of the automation circuit, and thus C

2

 will always be ener-



gized. If the C

2

 variable with the logical expression (1) is applied without the term of the “present 



state of variable”, then we will obtain that:

 

C



C s

2

1



=

which can be implemented from the third correct branch, indicated in the same figure. Thus, as a 



general design consequence, when the operation signal (or the Turn ON signal) for a state is not 

C

1



=1

C

1



=0

C

2



=0

b

1



b

0

+C



2

C

2



=1

s

C



1


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