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[book] [en] Pro C# 2008 and the NET 3.5 Platform Fourth Edition

// Can we treat hex2 as IPointy?

Hexagon hex2 = new Hexagon("Peter");

IPointy itfPt2 = hex2 as IPointy;

if(itfPt2 != null)

Console.WriteLine("Points: {0}", itfPt2.Points);

else


Console.WriteLine("OOPS! Not pointy...");

Console.ReadLine();

}

Notice that when you make use of the as keyword, you have no need to make use of try/catch



logic, given that if the reference is not null, you know you are calling on a valid interface reference.

Obtaining Interface References: The is Keyword

You may also check for an implemented interface using the is keyword (also first seen in Chapter 6).

If the object in question is not compatible with the specified interface, you are returned the value

false. On the other hand, if the type is compatible with the interface in question, you can safely call

the members without needing to make use of try/catch logic.

To illustrate, assume we have an array of Shape types containing some members that imple-

ment IPointy. Notice how we are able to determine which item in the array supports this interface

using the is keyword, as shown in this retrofitted Main() method:

C H A P T E R   9  

W O R K I N G   W I T H   I N T E R FA C E S



277

8849CH09.qxd  10/1/07  10:41 AM  Page 277




static void Main(string[] args)

{

Console.WriteLine("***** Fun with Interfaces *****\n");




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